Ttdfjt

Why doesn't a person bounce back after falling down like a ball? If we push a person and he falls down then why doesn't he come back to its initial position. Although according to Newton's 3rd law of motion: To every action there is always equal but opposite reaction. If we take the example of ball then it comes back with the same force as it falls down.But in the case of a human body, this law is not applicable. Why?

Newton's third law just says when the person is hitting the floor the force the person exerts on the ground is equal to the force the ground exerts on the person. i.e. all forces are interactions.

Newton's third law does not say that all collisions are elastic, which is what you are proposing. When someone hits the floor most of the energy is absorbed by the person through deformation (as well as the floor, depending on what type of floor it is), but there is barely any rebound since people tend to not be very elastic. i.e. the deformation does not involve storing the energy to be released back into kinetic energy. Contrast this with a bouncy ball where much of the energy goes into deforming the ball, but since it is very elastic it is able to spring back and put energy back into motion. However, it is unlikely the collision is still perfectly elastic, as you seem to suggest in your question.

Your misunderstanding likely comes from the imprecise usage of the words "action" and "reaction". In this case, these words refer to just forces, not entire processes. You can get some confusing questions if you don't understand this. For example, why is it that when I open my refrigerator that my refrigerator doesn't also open me?

When you body hits the floor, it does receive an equal and opposite reaction force from the floor. But unlike a ball a body is an complex object. So not all energy is transferred back as kinetic energy. Some energy is used to produce sound, some is used to deform your body... etc. I think you are confusing force with energy. Does every ball bounce back the same amount? Newton's 3rd law talks about force only. More force doesn't always(mostly) equal to more work done.

In your case if all the force was used to change the body's kinetic energy somehow(which is not realistically possible), then it would have bounced back the same amount.

If we push a person and he falls down then why doesn't he come back to its initial position. Although according to Newton's 3rd law of motion: To every action there is always equal but opposite reaction.

That's not a correct statement of Newton's third law.

Newton's third law of motion actually says: "If one object exerts a force on another object, then the second object also exerts a force on the first object, which is of the same magnitude but in the opposite direction."

So in this case, what Newton's third law is saying is: "If the floor pushes up on a person with a certain amount of force, then the person pushes down on the floor with the same amount of force." From this, there's no reason to think that the person would bounce back to his initial position.

It's true that on the impact the human body experiences a force upwards equal to the force the body exerts downwards on the Earth: $vecF=fracDeltavecpDelta t$. Now $Deltavecp$ doesn't send the body's momentum in the opposite direction, but instead, all the momentum change is used to crack the bones, or more general deform the body in a horrible way (unless the person jumps from a small height, in which case he or she can give his(her)self an upward force by stretching his legs in which case he can reach the same height as where he came from, or even higher; in this case though, the energy necessary to return to the same hight comes from the body, which makes it an explosive collision and here we are talking about an inelastic collision). Some parts may bounce back upwards but are pulled back again by the rest of the body. So all kinetic energy has conversed in other forms of energy (including kinetic energy $frac12mvec v^2$ in which most $vecv$'s don't have a direction upwards).