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Grandpa has another non math question

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15

1

$begingroup$

Grandpa says, " This is not algebra or may be it is!

IF

X = 2

R + C = 6

B + P = 5 or 6

Then

What is

I + T ?

There are, with my logic, three different answers!"

lateral-thinking

share|improve this question

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yay! Another one of these! +1 and favorite.
  $endgroup$
  – Duck
  Jun 9 at 20:23
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Grandpa seems like a troublemaker.
  $endgroup$
  – Rubio♦
  Jun 9 at 20:24
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  That he is @Rubio that he is. (Ask Grandma)
  $endgroup$
  – DEEM
  Jun 9 at 20:25
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
  $endgroup$
  – Duck
  Jun 9 at 20:26
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
  $endgroup$
  – DEEM
  Jun 9 at 20:39
  

  
  
  
  

 | 
show 1 more comment

15

1

$begingroup$

Grandpa says, " This is not algebra or may be it is!

IF

X = 2

R + C = 6

B + P = 5 or 6

Then

What is

I + T ?

There are, with my logic, three different answers!"

lateral-thinking

share|improve this question

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yay! Another one of these! +1 and favorite.
  $endgroup$
  – Duck
  Jun 9 at 20:23
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Grandpa seems like a troublemaker.
  $endgroup$
  – Rubio♦
  Jun 9 at 20:24
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  That he is @Rubio that he is. (Ask Grandma)
  $endgroup$
  – DEEM
  Jun 9 at 20:25
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
  $endgroup$
  – Duck
  Jun 9 at 20:26
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
  $endgroup$
  – DEEM
  Jun 9 at 20:39
  

  
  
  
  

 | 
show 1 more comment

$begingroup$

Grandpa says, " This is not algebra or may be it is!

IF

X = 2

R + C = 6

B + P = 5 or 6

Then

What is

I + T ?

There are, with my logic, three different answers!"

lateral-thinking

share|improve this question

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

$endgroup$

share|improve this question

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

share|improve this question

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

asked Jun 9 at 20:11

DEEMDEEM

6,917123125

2 Answers
2

active

oldest

votes

22

$begingroup$

Here’s a thought...

X = 2

X is said like the word “ex” = 2 letters

R + C = 6

“are” plus “cee” (or “see” or “sea”) = 6

B + P = 5 or 6

“be” or “bee” plus “pee” (or “pea”) = 5 or 6

Thus, I + T =

Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6

for three solutions using the same logic, as requested.

... and “ti” would actually allow four answers, 3 4 5 or 6 :)

share|improve this answer

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
  $endgroup$
  – Jonathan Allan
  Jun 10 at 12:17
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
  $endgroup$
  – Bizhan
  Jun 10 at 15:34
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Bizhan ay me, you might be right. Er, wait ...
  $endgroup$
  – Rubio♦
  Jun 11 at 2:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh! ay me! haha!
  $endgroup$
  – Bizhan
  Jun 11 at 7:27
  

  
  
  
  

add a comment | 

3

$begingroup$

X = 2

X is written in two strokes

R + C = 6

R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6

B + P = 5 or 6

B is 2 strokes, + is 2, P is 2 which will result in 6?

I + T

I will be 1 stroke + is 2, T is also 2 which will make 5

share|improve this answer

answered Jun 10 at 7:26

MichaelMichael

692

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  How do you make B two? At least three, surely.
  $endgroup$
  – Rand al'Thor
  Jun 10 at 9:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
  $endgroup$
  – Rubio♦
  Jun 10 at 9:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
  $endgroup$
  – UKMonkey
  Jun 10 at 10:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
  $endgroup$
  – Mario Garcia
  Jun 10 at 11:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
  $endgroup$
  – Darrel Hoffman
  Jun 10 at 12:47
  

  
  
  
  

 | 
show 4 more comments

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22

$begingroup$

Here’s a thought...

X = 2

X is said like the word “ex” = 2 letters

R + C = 6

“are” plus “cee” (or “see” or “sea”) = 6

B + P = 5 or 6

“be” or “bee” plus “pee” (or “pea”) = 5 or 6

Thus, I + T =

Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6

for three solutions using the same logic, as requested.

... and “ti” would actually allow four answers, 3 4 5 or 6 :)

share|improve this answer

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
  $endgroup$
  – Jonathan Allan
  Jun 10 at 12:17
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
  $endgroup$
  – Bizhan
  Jun 10 at 15:34
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Bizhan ay me, you might be right. Er, wait ...
  $endgroup$
  – Rubio♦
  Jun 11 at 2:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh! ay me! haha!
  $endgroup$
  – Bizhan
  Jun 11 at 7:27
  

  
  
  
  

add a comment | 

22

$begingroup$

Here’s a thought...

X = 2

X is said like the word “ex” = 2 letters

R + C = 6

“are” plus “cee” (or “see” or “sea”) = 6

B + P = 5 or 6

“be” or “bee” plus “pee” (or “pea”) = 5 or 6

Thus, I + T =

Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6

for three solutions using the same logic, as requested.

... and “ti” would actually allow four answers, 3 4 5 or 6 :)

share|improve this answer

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
  $endgroup$
  – Jonathan Allan
  Jun 10 at 12:17
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
  $endgroup$
  – Bizhan
  Jun 10 at 15:34
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @Bizhan ay me, you might be right. Er, wait ...
  $endgroup$
  – Rubio♦
  Jun 11 at 2:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Oh! ay me! haha!
  $endgroup$
  – Bizhan
  Jun 11 at 7:27
  

  
  
  
  

add a comment | 

$begingroup$

Here’s a thought...

X = 2

X is said like the word “ex” = 2 letters

R + C = 6

“are” plus “cee” (or “see” or “sea”) = 6

B + P = 5 or 6

“be” or “bee” plus “pee” (or “pea”) = 5 or 6

Thus, I + T =

Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6

for three solutions using the same logic, as requested.

... and “ti” would actually allow four answers, 3 4 5 or 6 :)

share|improve this answer

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

$endgroup$

share|improve this answer

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

answered Jun 9 at 23:59

Rubio♦Rubio

32.2k669196

3

$begingroup$

X = 2

X is written in two strokes

R + C = 6

R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6

B + P = 5 or 6

B is 2 strokes, + is 2, P is 2 which will result in 6?

I + T

I will be 1 stroke + is 2, T is also 2 which will make 5

share|improve this answer

answered Jun 10 at 7:26

MichaelMichael

692

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  How do you make B two? At least three, surely.
  $endgroup$
  – Rand al'Thor
  Jun 10 at 9:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
  $endgroup$
  – Rubio♦
  Jun 10 at 9:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
  $endgroup$
  – UKMonkey
  Jun 10 at 10:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
  $endgroup$
  – Mario Garcia
  Jun 10 at 11:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
  $endgroup$
  – Darrel Hoffman
  Jun 10 at 12:47
  

  
  
  
  

 | 
show 4 more comments

3

$begingroup$

X = 2

X is written in two strokes

R + C = 6

R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6

B + P = 5 or 6

B is 2 strokes, + is 2, P is 2 which will result in 6?

I + T

I will be 1 stroke + is 2, T is also 2 which will make 5

share|improve this answer

answered Jun 10 at 7:26

MichaelMichael

692

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  How do you make B two? At least three, surely.
  $endgroup$
  – Rand al'Thor
  Jun 10 at 9:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
  $endgroup$
  – Rubio♦
  Jun 10 at 9:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
  $endgroup$
  – UKMonkey
  Jun 10 at 10:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
  $endgroup$
  – Mario Garcia
  Jun 10 at 11:26
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
  $endgroup$
  – Darrel Hoffman
  Jun 10 at 12:47
  

  
  
  
  

 | 
show 4 more comments

$begingroup$

X = 2

X is written in two strokes

R + C = 6

R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6

B + P = 5 or 6

B is 2 strokes, + is 2, P is 2 which will result in 6?

I + T

I will be 1 stroke + is 2, T is also 2 which will make 5

share|improve this answer

answered Jun 10 at 7:26

MichaelMichael

692

$endgroup$

share|improve this answer

answered Jun 10 at 7:26

MichaelMichael

692

answered Jun 10 at 7:26

MichaelMichael

692

answered Jun 10 at 7:26

MichaelMichael

692