Buliding a larger matrix from a smaller oneHow to transform this matrix & swap its columns in a simple way?Add a sub-matrix of zeros in big matrixInsert all elements from one matrix into anotherMatrix form of complex numbersExpress block matrix in terms of matrix basisOperatorial matrixPartitioned matrix operationsBuilding a matrix in block matrix formatFactor multiplied matrix with vectorMatrix Decomposition and Collect
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Buliding a larger matrix from a smaller one
How to transform this matrix & swap its columns in a simple way?Add a sub-matrix of zeros in big matrixInsert all elements from one matrix into anotherMatrix form of complex numbersExpress block matrix in terms of matrix basisOperatorial matrixPartitioned matrix operationsBuilding a matrix in block matrix formatFactor multiplied matrix with vectorMatrix Decomposition and Collect
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I have my matrix $h$ of size $2Ntimes 2N$ in this form
$$h=beginpmatrix
a & b \
c & d
endpmatrix
$$
where $a,b,c,d$ are smaller matrices which i don't know.
Is there any simple way to get this matrix?
$$beginpmatrix
a &0& b&0 \
0 &a& 0&b\
c &0& d&0 \
0 &c& 0&d\
endpmatrix
$$
matrix performance-tuning
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
$endgroup$
add a comment |
$begingroup$
I have my matrix $h$ of size $2Ntimes 2N$ in this form
$$h=beginpmatrix
a & b \
c & d
endpmatrix
$$
where $a,b,c,d$ are smaller matrices which i don't know.
Is there any simple way to get this matrix?
$$beginpmatrix
a &0& b&0 \
0 &a& 0&b\
c &0& d&0 \
0 &c& 0&d\
endpmatrix
$$
matrix performance-tuning
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
$endgroup$
$begingroup$
Check outKroneckerProduct
$endgroup$
– chuy
Jun 25 at 14:41
add a comment |
$begingroup$
I have my matrix $h$ of size $2Ntimes 2N$ in this form
$$h=beginpmatrix
a & b \
c & d
endpmatrix
$$
where $a,b,c,d$ are smaller matrices which i don't know.
Is there any simple way to get this matrix?
$$beginpmatrix
a &0& b&0 \
0 &a& 0&b\
c &0& d&0 \
0 &c& 0&d\
endpmatrix
$$
matrix performance-tuning
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
$endgroup$
I have my matrix $h$ of size $2Ntimes 2N$ in this form
$$h=beginpmatrix
a & b \
c & d
endpmatrix
$$
where $a,b,c,d$ are smaller matrices which i don't know.
Is there any simple way to get this matrix?
$$beginpmatrix
a &0& b&0 \
0 &a& 0&b\
c &0& d&0 \
0 &c& 0&d\
endpmatrix
$$
matrix performance-tuning
matrix performance-tuning
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
asked Jun 25 at 14:33
Alexander NikolaenkoAlexander Nikolaenko
283 bronze badges
283 bronze badges
$begingroup$
Check outKroneckerProduct
$endgroup$
– chuy
Jun 25 at 14:41
add a comment |
$begingroup$
Check outKroneckerProduct
$endgroup$
– chuy
Jun 25 at 14:41
$begingroup$
Check out
KroneckerProduct$endgroup$
– chuy
Jun 25 at 14:41
$begingroup$
Check out
KroneckerProduct$endgroup$
– chuy
Jun 25 at 14:41
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
MatrixForm[h = a, b, c, d]
$ h=left(
beginarraycc
a & b \
c & d \
endarray
right)$
KroneckerProduct[h, IdentityMatrix@2] // MatrixForm
$ left(
beginarraycccc
a & 0 & b & 0 \
0 & a & 0 & b \
c & 0 & d & 0 \
0 & c & 0 & d \
endarray
right)$
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
$endgroup$
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
MatrixForm[h = a, b, c, d]
$ h=left(
beginarraycc
a & b \
c & d \
endarray
right)$
KroneckerProduct[h, IdentityMatrix@2] // MatrixForm
$ left(
beginarraycccc
a & 0 & b & 0 \
0 & a & 0 & b \
c & 0 & d & 0 \
0 & c & 0 & d \
endarray
right)$
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
$endgroup$
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
add a comment |
$begingroup$
MatrixForm[h = a, b, c, d]
$ h=left(
beginarraycc
a & b \
c & d \
endarray
right)$
KroneckerProduct[h, IdentityMatrix@2] // MatrixForm
$ left(
beginarraycccc
a & 0 & b & 0 \
0 & a & 0 & b \
c & 0 & d & 0 \
0 & c & 0 & d \
endarray
right)$
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
$endgroup$
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
add a comment |
$begingroup$
MatrixForm[h = a, b, c, d]
$ h=left(
beginarraycc
a & b \
c & d \
endarray
right)$
KroneckerProduct[h, IdentityMatrix@2] // MatrixForm
$ left(
beginarraycccc
a & 0 & b & 0 \
0 & a & 0 & b \
c & 0 & d & 0 \
0 & c & 0 & d \
endarray
right)$
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
$endgroup$
MatrixForm[h = a, b, c, d]
$ h=left(
beginarraycc
a & b \
c & d \
endarray
right)$
KroneckerProduct[h, IdentityMatrix@2] // MatrixForm
$ left(
beginarraycccc
a & 0 & b & 0 \
0 & a & 0 & b \
c & 0 & d & 0 \
0 & c & 0 & d \
endarray
right)$
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
answered Jun 25 at 14:45
Okkes DulgerciOkkes Dulgerci
5,9231 gold badge11 silver badges21 bronze badges
5,9231 gold badge11 silver badges21 bronze badges
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
add a comment |
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
$begingroup$
thank you,it is exactly what i wanted!
$endgroup$
– Alexander Nikolaenko
Jun 25 at 14:53
add a comment |
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$begingroup$
Check out
KroneckerProduct$endgroup$
– chuy
Jun 25 at 14:41