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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
The Singh family lives in a housing development full of Scientists and engineers (god forbid!). The Home Owners have come up with weird ways of numbering their houses.
K Street is all engineers and M street is all mathematicians.
Turns out Mr. Singh is an engineer and of course Mrs. (Dr.) Singh is a
Mathematician! So they have a house at the corner of K and M street.
So assuming they followed the patterns for both streets, what is their house number?
Hint
Engineers like "Metrics" Think Metric Measurements and !
pattern lateral-thinking
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
$endgroup$
add a comment |
$begingroup$
The Singh family lives in a housing development full of Scientists and engineers (god forbid!). The Home Owners have come up with weird ways of numbering their houses.
K Street is all engineers and M street is all mathematicians.
Turns out Mr. Singh is an engineer and of course Mrs. (Dr.) Singh is a
Mathematician! So they have a house at the corner of K and M street.
So assuming they followed the patterns for both streets, what is their house number?
Hint
Engineers like "Metrics" Think Metric Measurements and !
pattern lateral-thinking
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
$endgroup$
1
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
1
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08
add a comment |
$begingroup$
The Singh family lives in a housing development full of Scientists and engineers (god forbid!). The Home Owners have come up with weird ways of numbering their houses.
K Street is all engineers and M street is all mathematicians.
Turns out Mr. Singh is an engineer and of course Mrs. (Dr.) Singh is a
Mathematician! So they have a house at the corner of K and M street.
So assuming they followed the patterns for both streets, what is their house number?
Hint
Engineers like "Metrics" Think Metric Measurements and !
pattern lateral-thinking
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
$endgroup$
The Singh family lives in a housing development full of Scientists and engineers (god forbid!). The Home Owners have come up with weird ways of numbering their houses.
K Street is all engineers and M street is all mathematicians.
Turns out Mr. Singh is an engineer and of course Mrs. (Dr.) Singh is a
Mathematician! So they have a house at the corner of K and M street.
So assuming they followed the patterns for both streets, what is their house number?
Hint
Engineers like "Metrics" Think Metric Measurements and !
pattern lateral-thinking
pattern lateral-thinking
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
edited Aug 11 at 10:26
DEEM
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
asked Aug 6 at 13:05
DEEMDEEM
7,9431 gold badge25 silver badges140 bronze badges
7,9431 gold badge25 silver badges140 bronze badges
1
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
1
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08
add a comment |
1
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
1
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08
1
1
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
1
1
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
I think the house number is
1000
Since K street is all engineers,
In Roman Numerals, 1000, 100, 500, and 1 translate to M, C, D, and I. When combining these with a metric measurement (metres) per @DEEM, we see that we get MM (millimetres), CM (centimetres), DM (decimetres), and M (metres) which are increasing units of length. Thanks to @Levieux for the assist!
Since M street is all mathematicians,
In Roman Numerals, M translates to 1000, which could mean that all house numbers (ie. 1000, 2000, 6000) are all multiples of 1000. @Braegh has further noted that the house numbers follow the pattern x! times 1000, as 1! = 1, 2! = 2, and 3! = 6. Thanks, @Braegh!
The house number
1000 meets both criteria.
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
$endgroup$
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
|
show 7 more comments
$begingroup$
Partial answer.
I believe the answer is
50
Because
the engineer sequence turned in roman numerals would then be LCDI, which is engineer slang for Leakage Current Detection And Interruption.
Also
A mathematician will tell you that there are billions of good reasons 50, 2000 and 6000 could be consecutive terms of a sequence, although OEIS has no results (perhaps that's what makes it special: it's the only sequence of three $leq 4$-digits numbers that OEIS doesn't know an extension of :) )
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
$endgroup$
add a comment |
$begingroup$
I think the answer is
900
Because on M street:
If you convert to roman numerals, each house has two characters with one being an M $rightarrow$ MM = 2000, $overline VM$ = 6000. So the Singh's house could be CM = 900, MI = 1001, MV = 1005, MC = 1100, MD = 1500, etc.
Because on K street:
The letter K represents a thousand. It doesn't make sense to represent a number under 1 or over 999 with a K. Therefore the number is limited between 1 -> 999. This leaves CM = 900 as the only remaining house number.
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
$endgroup$
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
add a comment |
$begingroup$
Partial
I don't actually have an answer, yet. Here's something, though:
K could be kilo and M could be mega as both have something to do with numbers and it looks like the numbers on K (kilo) Street are smaller than the numbers on M (mega) Street by a factor of 10, so... maybe 1,000 to mark the transition point?
Might be worth noting that
K and M can be kilometers, as well, which is another metric measurement...
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
$endgroup$
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
add a comment |
$begingroup$
Converting my Aug 7 comment into an answer:
The house number is
1000
because on M street:
the letter M is one thousand in Roman numerals
and on K street:
the letter K in lower case is the multiplier for one thousand in the metric system
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
$endgroup$
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think the house number is
1000
Since K street is all engineers,
In Roman Numerals, 1000, 100, 500, and 1 translate to M, C, D, and I. When combining these with a metric measurement (metres) per @DEEM, we see that we get MM (millimetres), CM (centimetres), DM (decimetres), and M (metres) which are increasing units of length. Thanks to @Levieux for the assist!
Since M street is all mathematicians,
In Roman Numerals, M translates to 1000, which could mean that all house numbers (ie. 1000, 2000, 6000) are all multiples of 1000. @Braegh has further noted that the house numbers follow the pattern x! times 1000, as 1! = 1, 2! = 2, and 3! = 6. Thanks, @Braegh!
The house number
1000 meets both criteria.
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
$endgroup$
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
|
show 7 more comments
$begingroup$
I think the house number is
1000
Since K street is all engineers,
In Roman Numerals, 1000, 100, 500, and 1 translate to M, C, D, and I. When combining these with a metric measurement (metres) per @DEEM, we see that we get MM (millimetres), CM (centimetres), DM (decimetres), and M (metres) which are increasing units of length. Thanks to @Levieux for the assist!
Since M street is all mathematicians,
In Roman Numerals, M translates to 1000, which could mean that all house numbers (ie. 1000, 2000, 6000) are all multiples of 1000. @Braegh has further noted that the house numbers follow the pattern x! times 1000, as 1! = 1, 2! = 2, and 3! = 6. Thanks, @Braegh!
The house number
1000 meets both criteria.
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
$endgroup$
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
|
show 7 more comments
$begingroup$
I think the house number is
1000
Since K street is all engineers,
In Roman Numerals, 1000, 100, 500, and 1 translate to M, C, D, and I. When combining these with a metric measurement (metres) per @DEEM, we see that we get MM (millimetres), CM (centimetres), DM (decimetres), and M (metres) which are increasing units of length. Thanks to @Levieux for the assist!
Since M street is all mathematicians,
In Roman Numerals, M translates to 1000, which could mean that all house numbers (ie. 1000, 2000, 6000) are all multiples of 1000. @Braegh has further noted that the house numbers follow the pattern x! times 1000, as 1! = 1, 2! = 2, and 3! = 6. Thanks, @Braegh!
The house number
1000 meets both criteria.
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
$endgroup$
I think the house number is
1000
Since K street is all engineers,
In Roman Numerals, 1000, 100, 500, and 1 translate to M, C, D, and I. When combining these with a metric measurement (metres) per @DEEM, we see that we get MM (millimetres), CM (centimetres), DM (decimetres), and M (metres) which are increasing units of length. Thanks to @Levieux for the assist!
Since M street is all mathematicians,
In Roman Numerals, M translates to 1000, which could mean that all house numbers (ie. 1000, 2000, 6000) are all multiples of 1000. @Braegh has further noted that the house numbers follow the pattern x! times 1000, as 1! = 1, 2! = 2, and 3! = 6. Thanks, @Braegh!
The house number
1000 meets both criteria.
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
edited Aug 12 at 12:57
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
answered Aug 6 at 20:01
El-GuestEl-Guest
25.8k3 gold badges62 silver badges106 bronze badges
25.8k3 gold badges62 silver badges106 bronze badges
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
|
show 7 more comments
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
1
1
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
Membrane Capacity___ It is lot simpler @El-Guest
$endgroup$
– DEEM
Aug 7 at 1:13
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
How does the updated answer look, @DEEM ?
$endgroup$
– El-Guest
Aug 7 at 2:07
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
$begingroup$
Also, rot13(Jvgu 1000, gurer pbhyq nyfb or n frdhrapr va gur Z fgerrg ubhfrf, bs gur sbez ((cerivbhf ubhfr ahzore/1000)^2)*1000 + (cerivbhf ubhfr ahzore))
$endgroup$
– Stiv
Aug 7 at 8:45
1
1
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
$begingroup$
I think the M street pattern is rot13(1000 gvzrf k!, jurer k vf gur ahzore bs gur ubhfr, fgnegvat sebz gur pbeare. Gur arkg bar jbhyq or gjragl-sbhe gubhfnaq, va guvf cnggrea.)
$endgroup$
– Braegh
Aug 11 at 23:26
1
1
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
$begingroup$
The Roman numeral part holds for mm, cm, and dm, but you gloss over the fact that im isn't a unit.
$endgroup$
– Nuclear Wang
Aug 12 at 13:05
|
show 7 more comments
$begingroup$
Partial answer.
I believe the answer is
50
Because
the engineer sequence turned in roman numerals would then be LCDI, which is engineer slang for Leakage Current Detection And Interruption.
Also
A mathematician will tell you that there are billions of good reasons 50, 2000 and 6000 could be consecutive terms of a sequence, although OEIS has no results (perhaps that's what makes it special: it's the only sequence of three $leq 4$-digits numbers that OEIS doesn't know an extension of :) )
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
$endgroup$
add a comment |
$begingroup$
Partial answer.
I believe the answer is
50
Because
the engineer sequence turned in roman numerals would then be LCDI, which is engineer slang for Leakage Current Detection And Interruption.
Also
A mathematician will tell you that there are billions of good reasons 50, 2000 and 6000 could be consecutive terms of a sequence, although OEIS has no results (perhaps that's what makes it special: it's the only sequence of three $leq 4$-digits numbers that OEIS doesn't know an extension of :) )
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
$endgroup$
add a comment |
$begingroup$
Partial answer.
I believe the answer is
50
Because
the engineer sequence turned in roman numerals would then be LCDI, which is engineer slang for Leakage Current Detection And Interruption.
Also
A mathematician will tell you that there are billions of good reasons 50, 2000 and 6000 could be consecutive terms of a sequence, although OEIS has no results (perhaps that's what makes it special: it's the only sequence of three $leq 4$-digits numbers that OEIS doesn't know an extension of :) )
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
$endgroup$
Partial answer.
I believe the answer is
50
Because
the engineer sequence turned in roman numerals would then be LCDI, which is engineer slang for Leakage Current Detection And Interruption.
Also
A mathematician will tell you that there are billions of good reasons 50, 2000 and 6000 could be consecutive terms of a sequence, although OEIS has no results (perhaps that's what makes it special: it's the only sequence of three $leq 4$-digits numbers that OEIS doesn't know an extension of :) )
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
answered Aug 6 at 19:56
Arnaud MortierArnaud Mortier
4,96213 silver badges45 bronze badges
4,96213 silver badges45 bronze badges
add a comment |
add a comment |
$begingroup$
I think the answer is
900
Because on M street:
If you convert to roman numerals, each house has two characters with one being an M $rightarrow$ MM = 2000, $overline VM$ = 6000. So the Singh's house could be CM = 900, MI = 1001, MV = 1005, MC = 1100, MD = 1500, etc.
Because on K street:
The letter K represents a thousand. It doesn't make sense to represent a number under 1 or over 999 with a K. Therefore the number is limited between 1 -> 999. This leaves CM = 900 as the only remaining house number.
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
$endgroup$
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
add a comment |
$begingroup$
I think the answer is
900
Because on M street:
If you convert to roman numerals, each house has two characters with one being an M $rightarrow$ MM = 2000, $overline VM$ = 6000. So the Singh's house could be CM = 900, MI = 1001, MV = 1005, MC = 1100, MD = 1500, etc.
Because on K street:
The letter K represents a thousand. It doesn't make sense to represent a number under 1 or over 999 with a K. Therefore the number is limited between 1 -> 999. This leaves CM = 900 as the only remaining house number.
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
$endgroup$
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
add a comment |
$begingroup$
I think the answer is
900
Because on M street:
If you convert to roman numerals, each house has two characters with one being an M $rightarrow$ MM = 2000, $overline VM$ = 6000. So the Singh's house could be CM = 900, MI = 1001, MV = 1005, MC = 1100, MD = 1500, etc.
Because on K street:
The letter K represents a thousand. It doesn't make sense to represent a number under 1 or over 999 with a K. Therefore the number is limited between 1 -> 999. This leaves CM = 900 as the only remaining house number.
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
$endgroup$
I think the answer is
900
Because on M street:
If you convert to roman numerals, each house has two characters with one being an M $rightarrow$ MM = 2000, $overline VM$ = 6000. So the Singh's house could be CM = 900, MI = 1001, MV = 1005, MC = 1100, MD = 1500, etc.
Because on K street:
The letter K represents a thousand. It doesn't make sense to represent a number under 1 or over 999 with a K. Therefore the number is limited between 1 -> 999. This leaves CM = 900 as the only remaining house number.
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
edited Aug 7 at 4:21
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
answered Aug 7 at 4:06
C. LangeC. Lange
2841 silver badge5 bronze badges
2841 silver badge5 bronze badges
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
add a comment |
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
How is VM=6000?
$endgroup$
– JonMark Perry
Aug 7 at 4:12
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
$begingroup$
@JonMarkPerry I think like this: $overline VM$?
$endgroup$
– C. Lange
Aug 7 at 4:20
add a comment |
$begingroup$
Partial
I don't actually have an answer, yet. Here's something, though:
K could be kilo and M could be mega as both have something to do with numbers and it looks like the numbers on K (kilo) Street are smaller than the numbers on M (mega) Street by a factor of 10, so... maybe 1,000 to mark the transition point?
Might be worth noting that
K and M can be kilometers, as well, which is another metric measurement...
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
$endgroup$
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
add a comment |
$begingroup$
Partial
I don't actually have an answer, yet. Here's something, though:
K could be kilo and M could be mega as both have something to do with numbers and it looks like the numbers on K (kilo) Street are smaller than the numbers on M (mega) Street by a factor of 10, so... maybe 1,000 to mark the transition point?
Might be worth noting that
K and M can be kilometers, as well, which is another metric measurement...
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
$endgroup$
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
add a comment |
$begingroup$
Partial
I don't actually have an answer, yet. Here's something, though:
K could be kilo and M could be mega as both have something to do with numbers and it looks like the numbers on K (kilo) Street are smaller than the numbers on M (mega) Street by a factor of 10, so... maybe 1,000 to mark the transition point?
Might be worth noting that
K and M can be kilometers, as well, which is another metric measurement...
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
$endgroup$
Partial
I don't actually have an answer, yet. Here's something, though:
K could be kilo and M could be mega as both have something to do with numbers and it looks like the numbers on K (kilo) Street are smaller than the numbers on M (mega) Street by a factor of 10, so... maybe 1,000 to mark the transition point?
Might be worth noting that
K and M can be kilometers, as well, which is another metric measurement...
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
edited Aug 11 at 23:08
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
answered Aug 11 at 10:54
Voldemort's WrathVoldemort's Wrath
4151 silver badge23 bronze badges
4151 silver badge23 bronze badges
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
add a comment |
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
On the right path. Think another metric measurement. Your answer (number) is correct though, just like @El-Guests
$endgroup$
– DEEM
Aug 11 at 11:03
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
$begingroup$
@DEEM - Am I still on the right path? Have I advanced? Did I go backwards?
$endgroup$
– Voldemort's Wrath
Aug 11 at 23:09
add a comment |
$begingroup$
Converting my Aug 7 comment into an answer:
The house number is
1000
because on M street:
the letter M is one thousand in Roman numerals
and on K street:
the letter K in lower case is the multiplier for one thousand in the metric system
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
$endgroup$
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
add a comment |
$begingroup$
Converting my Aug 7 comment into an answer:
The house number is
1000
because on M street:
the letter M is one thousand in Roman numerals
and on K street:
the letter K in lower case is the multiplier for one thousand in the metric system
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
$endgroup$
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
add a comment |
$begingroup$
Converting my Aug 7 comment into an answer:
The house number is
1000
because on M street:
the letter M is one thousand in Roman numerals
and on K street:
the letter K in lower case is the multiplier for one thousand in the metric system
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
$endgroup$
Converting my Aug 7 comment into an answer:
The house number is
1000
because on M street:
the letter M is one thousand in Roman numerals
and on K street:
the letter K in lower case is the multiplier for one thousand in the metric system
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
answered Aug 11 at 19:25
shoovershoover
2,4407 silver badges19 bronze badges
2,4407 silver badges19 bronze badges
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
add a comment |
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
$begingroup$
Then how do you explain the other house numbers @shoover? What pattern?
$endgroup$
– DEEM
Aug 11 at 20:11
add a comment |
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1
$begingroup$
You have to think laterally with respect to which street?
$endgroup$
– Arnaud Mortier
Aug 6 at 16:18
$begingroup$
That would be a clear hint @Arnaud Mortier
$endgroup$
– DEEM
Aug 6 at 17:25
$begingroup$
But a very good question none-the-less
$endgroup$
– DEEM
Aug 6 at 17:26
$begingroup$
rot13(gur yrggre rz vf bar gubhfnaq va Ebzna ahzrenyf, naq gur yrggre xnl va ybjre pnfr vf gur zhygvcyvre sbe bar gubhfnaq va gur zrgevp flfgrz), but I don't know what to do with that information.
$endgroup$
– shoover
Aug 7 at 2:53
1
$begingroup$
Judging by the correct answer, #1 K street should actually have no number at all...
$endgroup$
– Nuclear Wang
Aug 12 at 20:08