Sum letters are not two different Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Product and SumA mysterious property of 17 US-statesA fellowship of nine wordsAnother Company of ThirteenDetermine $X$ and $Y$: sum, difference and ratioWhen logic problems require “yes-no” questions, are there conventions for questions that might get an “I don't know”?Three mathematicians are forever in PrisonAn Only Connect WallWhat is the next integer in this sequence?Why is this sequence of images correct?

Is there public access to the Meteor Crater in Arizona?

How were pictures turned from film to a big picture in a picture frame before digital scanning?

What does 丫 mean? 丫是什么意思?

How many morphisms from 1 to 1+1 can there be?

What does the writing on Poe's helmet say?

What is the difference between a "ranged attack" and a "ranged weapon attack"?

If Windows 7 doesn't support WSL, then what is "Subsystem for UNIX-based Applications"?

What order were files/directories output in dir?

Is there hard evidence that the grant peer review system performs significantly better than random?

What is the role of と after a noun when it doesn't appear to count or list anything?

Why is a lens darker than other ones when applying the same settings?

Should a wizard buy fine inks every time he want to copy spells into his spellbook?

Delete free apps from library

Can two people see the same photon?

Google .dev domain strangely redirects to https

Caught masturbating at work

What is a more techy Technical Writer job title that isn't cutesy or confusing?

How to ask rejected full-time candidates to apply to teach individual courses?

Why not use the yoke to control yaw, as well as pitch and roll?

Most effective melee weapons for arboreal combat? (pre-gunpowder technology)

Is multiple magic items in one inherently imbalanced?

Sally's older brother

Trying to understand entropy as a novice in thermodynamics

i2c bus hangs in master RPi access to MSP430G uC ~1 in 1000 accesses



Sum letters are not two different



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Product and SumA mysterious property of 17 US-statesA fellowship of nine wordsAnother Company of ThirteenDetermine $X$ and $Y$: sum, difference and ratioWhen logic problems require “yes-no” questions, are there conventions for questions that might get an “I don't know”?Three mathematicians are forever in PrisonAn Only Connect WallWhat is the next integer in this sequence?Why is this sequence of images correct?










10












$begingroup$


The following letters all have something in common which may not be obvious at a first glance:



A B D H P


No other letters share this attribute.



Hint




There are no misspellings or typos in the title of this question. Maybe a clue though.




More hints may follow if the question is not answered.



Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.



Hint 2




The number 0 and the character ( also have the same property. I only said no other letters share it ;-)




Hint 3




As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.











share|improve this question











$endgroup$







  • 5




    $begingroup$
    Are you sure B shouldn't be included too?
    $endgroup$
    – Deusovi
    2 days ago










  • $begingroup$
    @Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    Does a ! also share this property?
    $endgroup$
    – Eagle
    2 days ago










  • $begingroup$
    @Akari Yes it does. I have not listed them all.
    $endgroup$
    – ElPedro
    2 days ago















10












$begingroup$


The following letters all have something in common which may not be obvious at a first glance:



A B D H P


No other letters share this attribute.



Hint




There are no misspellings or typos in the title of this question. Maybe a clue though.




More hints may follow if the question is not answered.



Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.



Hint 2




The number 0 and the character ( also have the same property. I only said no other letters share it ;-)




Hint 3




As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.











share|improve this question











$endgroup$







  • 5




    $begingroup$
    Are you sure B shouldn't be included too?
    $endgroup$
    – Deusovi
    2 days ago










  • $begingroup$
    @Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    Does a ! also share this property?
    $endgroup$
    – Eagle
    2 days ago










  • $begingroup$
    @Akari Yes it does. I have not listed them all.
    $endgroup$
    – ElPedro
    2 days ago













10












10








10





$begingroup$


The following letters all have something in common which may not be obvious at a first glance:



A B D H P


No other letters share this attribute.



Hint




There are no misspellings or typos in the title of this question. Maybe a clue though.




More hints may follow if the question is not answered.



Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.



Hint 2




The number 0 and the character ( also have the same property. I only said no other letters share it ;-)




Hint 3




As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.











share|improve this question











$endgroup$




The following letters all have something in common which may not be obvious at a first glance:



A B D H P


No other letters share this attribute.



Hint




There are no misspellings or typos in the title of this question. Maybe a clue though.




More hints may follow if the question is not answered.



Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.



Hint 2




The number 0 and the character ( also have the same property. I only said no other letters share it ;-)




Hint 3




As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.








logical-deduction pattern






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago







ElPedro

















asked 2 days ago









ElPedroElPedro

303210




303210







  • 5




    $begingroup$
    Are you sure B shouldn't be included too?
    $endgroup$
    – Deusovi
    2 days ago










  • $begingroup$
    @Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    Does a ! also share this property?
    $endgroup$
    – Eagle
    2 days ago










  • $begingroup$
    @Akari Yes it does. I have not listed them all.
    $endgroup$
    – ElPedro
    2 days ago












  • 5




    $begingroup$
    Are you sure B shouldn't be included too?
    $endgroup$
    – Deusovi
    2 days ago










  • $begingroup$
    @Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    Does a ! also share this property?
    $endgroup$
    – Eagle
    2 days ago










  • $begingroup$
    @Akari Yes it does. I have not listed them all.
    $endgroup$
    – ElPedro
    2 days ago







5




5




$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi
2 days ago




$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi
2 days ago












$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago




$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago




1




1




$begingroup$
Does a ! also share this property?
$endgroup$
– Eagle
2 days ago




$begingroup$
Does a ! also share this property?
$endgroup$
– Eagle
2 days ago












$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago




$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago










5 Answers
5






active

oldest

votes


















11












$begingroup$

The property seems to be related to:




Binary equivalents of the symbols/alphabets etc.




Explanation:




Binary equivalents for the following can be written as:

A -- 01000001

B -- 01000010

D -- 01000100

H -- 01001000

P -- 01010000

0 -- 00110000

( -- 00101000




So the property is,




The sum of digits in the binary equivalents is two




Or




The binary equivalents of all these have two 1s and six 0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property




The title (Thanks to @trolley813):




Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]





Old (and wrong) answer



The property is:




The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.




And,




There is no other alphabet with the index 1+2+4+8+16+1 = 32







share|improve this answer











$endgroup$








  • 1




    $begingroup$
    You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
    $endgroup$
    – trolley813
    yesterday






  • 1




    $begingroup$
    Thanks a lot @trolley813 ! I've edited it
    $endgroup$
    – Eagle
    yesterday










  • $begingroup$
    @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
    $endgroup$
    – ElPedro
    yesterday











  • $begingroup$
    A bit contrived, I know, but left room for a couple of hints.
    $endgroup$
    – ElPedro
    yesterday


















18












$begingroup$

The property is that




each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.







share|improve this answer









$endgroup$








  • 2




    $begingroup$
    That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
    $endgroup$
    – ElPedro
    2 days ago







  • 2




    $begingroup$
    @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
    $endgroup$
    – Flater
    yesterday











  • $begingroup$
    @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
    $endgroup$
    – ElPedro
    yesterday


















8












$begingroup$

Is it




All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers




Thus we have




From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$




Other letters don't share this property because




64 + 32 = 96 which does not correspond to any letter. The letter a begins at 97




For the newer hints




$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$







share|improve this answer











$endgroup$








  • 1




    $begingroup$
    Obviously moving in the right direction with the ASCII table.
    $endgroup$
    – ElPedro
    2 days ago






  • 3




    $begingroup$
    @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
    $endgroup$
    – RedBaron
    2 days ago







  • 1




    $begingroup$
    Still a good answer though :)
    $endgroup$
    – ElPedro
    2 days ago






  • 1




    $begingroup$
    I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
    $endgroup$
    – Flater
    yesterday


















6












$begingroup$

I think it's:




Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter




This means that:




Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P







share|improve this answer








New contributor




Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$








  • 1




    $begingroup$
    Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
    $endgroup$
    – ElPedro
    2 days ago


















5












$begingroup$


Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.







share|improve this answer








New contributor




CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "559"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81925%2fsum-letters-are-not-two-different%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    11












    $begingroup$

    The property seems to be related to:




    Binary equivalents of the symbols/alphabets etc.




    Explanation:




    Binary equivalents for the following can be written as:

    A -- 01000001

    B -- 01000010

    D -- 01000100

    H -- 01001000

    P -- 01010000

    0 -- 00110000

    ( -- 00101000




    So the property is,




    The sum of digits in the binary equivalents is two




    Or




    The binary equivalents of all these have two 1s and six 0s.
    Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property




    The title (Thanks to @trolley813):




    Two might refer to the sum of the digits, which is indeed two!
    Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]





    Old (and wrong) answer



    The property is:




    The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.




    And,




    There is no other alphabet with the index 1+2+4+8+16+1 = 32







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
      $endgroup$
      – trolley813
      yesterday






    • 1




      $begingroup$
      Thanks a lot @trolley813 ! I've edited it
      $endgroup$
      – Eagle
      yesterday










    • $begingroup$
      @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
      $endgroup$
      – ElPedro
      yesterday











    • $begingroup$
      A bit contrived, I know, but left room for a couple of hints.
      $endgroup$
      – ElPedro
      yesterday















    11












    $begingroup$

    The property seems to be related to:




    Binary equivalents of the symbols/alphabets etc.




    Explanation:




    Binary equivalents for the following can be written as:

    A -- 01000001

    B -- 01000010

    D -- 01000100

    H -- 01001000

    P -- 01010000

    0 -- 00110000

    ( -- 00101000




    So the property is,




    The sum of digits in the binary equivalents is two




    Or




    The binary equivalents of all these have two 1s and six 0s.
    Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property




    The title (Thanks to @trolley813):




    Two might refer to the sum of the digits, which is indeed two!
    Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]





    Old (and wrong) answer



    The property is:




    The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.




    And,




    There is no other alphabet with the index 1+2+4+8+16+1 = 32







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
      $endgroup$
      – trolley813
      yesterday






    • 1




      $begingroup$
      Thanks a lot @trolley813 ! I've edited it
      $endgroup$
      – Eagle
      yesterday










    • $begingroup$
      @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
      $endgroup$
      – ElPedro
      yesterday











    • $begingroup$
      A bit contrived, I know, but left room for a couple of hints.
      $endgroup$
      – ElPedro
      yesterday













    11












    11








    11





    $begingroup$

    The property seems to be related to:




    Binary equivalents of the symbols/alphabets etc.




    Explanation:




    Binary equivalents for the following can be written as:

    A -- 01000001

    B -- 01000010

    D -- 01000100

    H -- 01001000

    P -- 01010000

    0 -- 00110000

    ( -- 00101000




    So the property is,




    The sum of digits in the binary equivalents is two




    Or




    The binary equivalents of all these have two 1s and six 0s.
    Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property




    The title (Thanks to @trolley813):




    Two might refer to the sum of the digits, which is indeed two!
    Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]





    Old (and wrong) answer



    The property is:




    The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.




    And,




    There is no other alphabet with the index 1+2+4+8+16+1 = 32







    share|improve this answer











    $endgroup$



    The property seems to be related to:




    Binary equivalents of the symbols/alphabets etc.




    Explanation:




    Binary equivalents for the following can be written as:

    A -- 01000001

    B -- 01000010

    D -- 01000100

    H -- 01001000

    P -- 01010000

    0 -- 00110000

    ( -- 00101000




    So the property is,




    The sum of digits in the binary equivalents is two




    Or




    The binary equivalents of all these have two 1s and six 0s.
    Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property




    The title (Thanks to @trolley813):




    Two might refer to the sum of the digits, which is indeed two!
    Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]





    Old (and wrong) answer



    The property is:




    The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.




    And,




    There is no other alphabet with the index 1+2+4+8+16+1 = 32








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited yesterday

























    answered 2 days ago









    EagleEagle

    722226




    722226







    • 1




      $begingroup$
      You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
      $endgroup$
      – trolley813
      yesterday






    • 1




      $begingroup$
      Thanks a lot @trolley813 ! I've edited it
      $endgroup$
      – Eagle
      yesterday










    • $begingroup$
      @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
      $endgroup$
      – ElPedro
      yesterday











    • $begingroup$
      A bit contrived, I know, but left room for a couple of hints.
      $endgroup$
      – ElPedro
      yesterday












    • 1




      $begingroup$
      You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
      $endgroup$
      – trolley813
      yesterday






    • 1




      $begingroup$
      Thanks a lot @trolley813 ! I've edited it
      $endgroup$
      – Eagle
      yesterday










    • $begingroup$
      @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
      $endgroup$
      – ElPedro
      yesterday











    • $begingroup$
      A bit contrived, I know, but left room for a couple of hints.
      $endgroup$
      – ElPedro
      yesterday







    1




    1




    $begingroup$
    You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
    $endgroup$
    – ElPedro
    2 days ago




    $begingroup$
    You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
    $endgroup$
    – ElPedro
    2 days ago




    1




    1




    $begingroup$
    @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
    $endgroup$
    – trolley813
    yesterday




    $begingroup$
    @Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
    $endgroup$
    – trolley813
    yesterday




    1




    1




    $begingroup$
    Thanks a lot @trolley813 ! I've edited it
    $endgroup$
    – Eagle
    yesterday




    $begingroup$
    Thanks a lot @trolley813 ! I've edited it
    $endgroup$
    – Eagle
    yesterday












    $begingroup$
    @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
    $endgroup$
    – ElPedro
    yesterday





    $begingroup$
    @trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
    $endgroup$
    – ElPedro
    yesterday













    $begingroup$
    A bit contrived, I know, but left room for a couple of hints.
    $endgroup$
    – ElPedro
    yesterday




    $begingroup$
    A bit contrived, I know, but left room for a couple of hints.
    $endgroup$
    – ElPedro
    yesterday











    18












    $begingroup$

    The property is that




    each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.







    share|improve this answer









    $endgroup$








    • 2




      $begingroup$
      That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
      $endgroup$
      – ElPedro
      2 days ago







    • 2




      $begingroup$
      @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
      $endgroup$
      – Flater
      yesterday











    • $begingroup$
      @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
      $endgroup$
      – ElPedro
      yesterday















    18












    $begingroup$

    The property is that




    each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.







    share|improve this answer









    $endgroup$








    • 2




      $begingroup$
      That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
      $endgroup$
      – ElPedro
      2 days ago







    • 2




      $begingroup$
      @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
      $endgroup$
      – Flater
      yesterday











    • $begingroup$
      @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
      $endgroup$
      – ElPedro
      yesterday













    18












    18








    18





    $begingroup$

    The property is that




    each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.







    share|improve this answer









    $endgroup$



    The property is that




    each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.








    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 2 days ago









    DeusoviDeusovi

    63.3k6216273




    63.3k6216273







    • 2




      $begingroup$
      That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
      $endgroup$
      – ElPedro
      2 days ago







    • 2




      $begingroup$
      @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
      $endgroup$
      – Flater
      yesterday











    • $begingroup$
      @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
      $endgroup$
      – ElPedro
      yesterday












    • 2




      $begingroup$
      That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
      $endgroup$
      – ElPedro
      2 days ago







    • 2




      $begingroup$
      @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
      $endgroup$
      – Flater
      yesterday











    • $begingroup$
      @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
      $endgroup$
      – ElPedro
      yesterday







    2




    2




    $begingroup$
    That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
    $endgroup$
    – ElPedro
    2 days ago





    $begingroup$
    That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
    $endgroup$
    – ElPedro
    2 days ago





    2




    2




    $begingroup$
    @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
    $endgroup$
    – Flater
    yesterday





    $begingroup$
    @ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
    $endgroup$
    – Flater
    yesterday













    $begingroup$
    @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
    $endgroup$
    – ElPedro
    yesterday




    $begingroup$
    @Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
    $endgroup$
    – ElPedro
    yesterday











    8












    $begingroup$

    Is it




    All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers




    Thus we have




    From ascii code table,
    $A = 65 = 64 + 1 = 2^6 + 2^0$
    $B = 66 = 64 + 2 = 2^6 + 2^1$
    $D = 68 = 64 + 4 = 2^6 + 2^2$
    $H = 72 = 64 + 8 = 2^6 + 2^3$
    $P = 80 = 64 + 16 = 2^6 + 2^4$




    Other letters don't share this property because




    64 + 32 = 96 which does not correspond to any letter. The letter a begins at 97




    For the newer hints




    $0 = 48 = 32 + 16 = 2^5 + 2^4$
    $( = 40 = 32 + 8 = 2^5 + 2^3$







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Obviously moving in the right direction with the ASCII table.
      $endgroup$
      – ElPedro
      2 days ago






    • 3




      $begingroup$
      @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
      $endgroup$
      – RedBaron
      2 days ago







    • 1




      $begingroup$
      Still a good answer though :)
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
      $endgroup$
      – Flater
      yesterday















    8












    $begingroup$

    Is it




    All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers




    Thus we have




    From ascii code table,
    $A = 65 = 64 + 1 = 2^6 + 2^0$
    $B = 66 = 64 + 2 = 2^6 + 2^1$
    $D = 68 = 64 + 4 = 2^6 + 2^2$
    $H = 72 = 64 + 8 = 2^6 + 2^3$
    $P = 80 = 64 + 16 = 2^6 + 2^4$




    Other letters don't share this property because




    64 + 32 = 96 which does not correspond to any letter. The letter a begins at 97




    For the newer hints




    $0 = 48 = 32 + 16 = 2^5 + 2^4$
    $( = 40 = 32 + 8 = 2^5 + 2^3$







    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      Obviously moving in the right direction with the ASCII table.
      $endgroup$
      – ElPedro
      2 days ago






    • 3




      $begingroup$
      @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
      $endgroup$
      – RedBaron
      2 days ago







    • 1




      $begingroup$
      Still a good answer though :)
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
      $endgroup$
      – Flater
      yesterday













    8












    8








    8





    $begingroup$

    Is it




    All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers




    Thus we have




    From ascii code table,
    $A = 65 = 64 + 1 = 2^6 + 2^0$
    $B = 66 = 64 + 2 = 2^6 + 2^1$
    $D = 68 = 64 + 4 = 2^6 + 2^2$
    $H = 72 = 64 + 8 = 2^6 + 2^3$
    $P = 80 = 64 + 16 = 2^6 + 2^4$




    Other letters don't share this property because




    64 + 32 = 96 which does not correspond to any letter. The letter a begins at 97




    For the newer hints




    $0 = 48 = 32 + 16 = 2^5 + 2^4$
    $( = 40 = 32 + 8 = 2^5 + 2^3$







    share|improve this answer











    $endgroup$



    Is it




    All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers




    Thus we have




    From ascii code table,
    $A = 65 = 64 + 1 = 2^6 + 2^0$
    $B = 66 = 64 + 2 = 2^6 + 2^1$
    $D = 68 = 64 + 4 = 2^6 + 2^2$
    $H = 72 = 64 + 8 = 2^6 + 2^3$
    $P = 80 = 64 + 16 = 2^6 + 2^4$




    Other letters don't share this property because




    64 + 32 = 96 which does not correspond to any letter. The letter a begins at 97




    For the newer hints




    $0 = 48 = 32 + 16 = 2^5 + 2^4$
    $( = 40 = 32 + 8 = 2^5 + 2^3$








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago









    Eagle

    722226




    722226










    answered 2 days ago









    RedBaronRedBaron

    42636




    42636







    • 1




      $begingroup$
      Obviously moving in the right direction with the ASCII table.
      $endgroup$
      – ElPedro
      2 days ago






    • 3




      $begingroup$
      @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
      $endgroup$
      – RedBaron
      2 days ago







    • 1




      $begingroup$
      Still a good answer though :)
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
      $endgroup$
      – Flater
      yesterday












    • 1




      $begingroup$
      Obviously moving in the right direction with the ASCII table.
      $endgroup$
      – ElPedro
      2 days ago






    • 3




      $begingroup$
      @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
      $endgroup$
      – RedBaron
      2 days ago







    • 1




      $begingroup$
      Still a good answer though :)
      $endgroup$
      – ElPedro
      2 days ago






    • 1




      $begingroup$
      I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
      $endgroup$
      – Flater
      yesterday







    1




    1




    $begingroup$
    Obviously moving in the right direction with the ASCII table.
    $endgroup$
    – ElPedro
    2 days ago




    $begingroup$
    Obviously moving in the right direction with the ASCII table.
    $endgroup$
    – ElPedro
    2 days ago




    3




    3




    $begingroup$
    @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
    $endgroup$
    – RedBaron
    2 days ago





    $begingroup$
    @ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
    $endgroup$
    – RedBaron
    2 days ago





    1




    1




    $begingroup$
    Still a good answer though :)
    $endgroup$
    – ElPedro
    2 days ago




    $begingroup$
    Still a good answer though :)
    $endgroup$
    – ElPedro
    2 days ago




    1




    1




    $begingroup$
    I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
    $endgroup$
    – Flater
    yesterday




    $begingroup$
    I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
    $endgroup$
    – Flater
    yesterday











    6












    $begingroup$

    I think it's:




    Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter




    This means that:




    Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P







    share|improve this answer








    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$








    • 1




      $begingroup$
      Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
      $endgroup$
      – ElPedro
      2 days ago















    6












    $begingroup$

    I think it's:




    Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter




    This means that:




    Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P







    share|improve this answer








    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$








    • 1




      $begingroup$
      Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
      $endgroup$
      – ElPedro
      2 days ago













    6












    6








    6





    $begingroup$

    I think it's:




    Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter




    This means that:




    Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P







    share|improve this answer








    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$



    I think it's:




    Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter




    This means that:




    Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P








    share|improve this answer








    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    share|improve this answer



    share|improve this answer






    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    answered 2 days ago









    SaeleasSaeleas

    1612




    1612




    New contributor




    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    New contributor





    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    • 1




      $begingroup$
      Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
      $endgroup$
      – ElPedro
      2 days ago












    • 1




      $begingroup$
      Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
      $endgroup$
      – ElPedro
      2 days ago







    1




    1




    $begingroup$
    Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
    $endgroup$
    – ElPedro
    2 days ago




    $begingroup$
    Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
    $endgroup$
    – ElPedro
    2 days ago











    5












    $begingroup$


    Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
    Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.







    share|improve this answer








    New contributor




    CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$

















      5












      $begingroup$


      Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
      Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.







      share|improve this answer








      New contributor




      CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$















        5












        5








        5





        $begingroup$


        Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
        Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.







        share|improve this answer








        New contributor




        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        $endgroup$




        Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
        Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.








        share|improve this answer








        New contributor




        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer






        New contributor




        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered 2 days ago









        CStafford-14CStafford-14

        16510




        16510




        New contributor




        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Puzzling Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81925%2fsum-letters-are-not-two-different%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Get product attribute by attribute group code in magento 2get product attribute by product attribute group in magento 2Magento 2 Log Bundle Product Data in List Page?How to get all product attribute of a attribute group of Default attribute set?Magento 2.1 Create a filter in the product grid by new attributeMagento 2 : Get Product Attribute values By GroupMagento 2 How to get all existing values for one attributeMagento 2 get custom attribute of a single product inside a pluginMagento 2.3 How to get all the Multi Source Inventory (MSI) locations collection in custom module?Magento2: how to develop rest API to get new productsGet product attribute by attribute group code ( [attribute_group_code] ) in magento 2

            Category:9 (number) SubcategoriesMedia in category "9 (number)"Navigation menuUpload mediaGND ID: 4485639-8Library of Congress authority ID: sh85091979ReasonatorScholiaStatistics

            Magento 2.3: How do i solve this, Not registered handle, on custom form?How can i rewrite TierPrice Block in Magento2magento 2 captcha not rendering if I override layout xmlmain.CRITICAL: Plugin class doesn't existMagento 2 : Problem while adding custom button order view page?Magento 2.2.5: Overriding Admin Controller sales/orderMagento 2.2.5: Add, Update and Delete existing products Custom OptionsMagento 2.3 : File Upload issue in UI Component FormMagento2 Not registered handleHow to configured Form Builder Js in my custom magento 2.3.0 module?Magento 2.3. How to create image upload field in an admin form