Next date with distinct digitsCan you find my friends' birthdayThe directions from another language?So how did the date go?Logic-grid puzzle. How do I have to interpret the clue?The Recruitment Office PuzzleFind the equality with all digitsMastermind with an errorPawns and DiscsWhat is the canonical age?Unlock an answering machine using minimum number of digits
What things do I only get a limited opportunity to take photos of?
How did the European Union reach the figure of 3% as a maximum allowed deficit?
How to remove multiple elements from Set/Map AND knowing which ones were removed?
Will users know a CardView is clickable
Looking for an iPhone app for working out chess problems
How can I detect if I'm in a subshell?
Threading data on TimeSeries
Why is Skinner so awkward in Hot Fuzz?
Is it possible to have battery technology that can't be duplicated?
How to avoid offending original culture when making conculture inspired from original
Must a CPU have a GPU if the motherboard provides a display port (when there isn't any separate video card)?
How do you translate “talk shit”?
How can Caller ID be faked?
Is there a risk to write an invitation letter for a stranger to obtain a Czech (Schengen) visa?
What is the difference between state-based effects and effects on the stack?
How long would it take for sucrose to undergo hydrolysis in boiling water?
Jam with honey & without pectin has a saucy consistency always
The last tree in the Universe
My parents claim they cannot pay for my college education; what are my options?
Someone who is granted access to information but not expected to read it
How to address players struggling with simple controls?
Background for black and white chart
The title "Mord mit Aussicht" explained
How many possible starting positions are uniquely solvable for a nonogram puzzle?
Next date with distinct digits
Can you find my friends' birthdayThe directions from another language?So how did the date go?Logic-grid puzzle. How do I have to interpret the clue?The Recruitment Office PuzzleFind the equality with all digitsMastermind with an errorPawns and DiscsWhat is the canonical age?Unlock an answering machine using minimum number of digits
$begingroup$
The date today is 7th June 2019, or 07/06/2019 (using the English DD/MM/YYYY ordering).
When is the next date that when written in this way has all eight digits different?
logical-deduction
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
$endgroup$
add a comment |
$begingroup$
The date today is 7th June 2019, or 07/06/2019 (using the English DD/MM/YYYY ordering).
When is the next date that when written in this way has all eight digits different?
logical-deduction
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
$endgroup$
add a comment |
$begingroup$
The date today is 7th June 2019, or 07/06/2019 (using the English DD/MM/YYYY ordering).
When is the next date that when written in this way has all eight digits different?
logical-deduction
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
$endgroup$
The date today is 7th June 2019, or 07/06/2019 (using the English DD/MM/YYYY ordering).
When is the next date that when written in this way has all eight digits different?
logical-deduction
logical-deduction
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
edited Jun 7 at 15:29
rnaylor
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
asked Jun 7 at 13:30
rnaylorrnaylor
1,2711922
1,2711922
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Rather remarkably, I wrote down this exact puzzle in my notebook a couple of years ago to which I think the answer is
17/06/2345 in DD/MM/YYYY format.
Reasoning
Notice that the first M will either be $0$ or $1$.
If it is $0$ then the first D will either be $1$ or $2$ or DD will be $31$.
If it is $1$ then either the second M will be $0$ or the second M will be $2$ and the day will contain a $0$.
Overall, this means that $0$ and either $1$ or $2$ must be used in the DD/MM part. If we don't want to skip to the next millenium, we need the $2$ for the beginning of the year.
Hence the DD/MM part requires both $0$ and $1$.
After that, we focus on the nearest year possible which comes from assigning the digits $3,4,5$ in order to century, decade and digit of the year.
It makes more sense to assign the $0$ to the month instead of $1$ but we cannot assign both since we cannot have a day without any of $0$, $1$ or $2$. Hence, we assign $6$ to the month and then $7$ to create the day.
answered Jun 7 at 13:36
hexominohexomino
53k4156248
$endgroup$
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "559"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f84795%2fnext-date-with-distinct-digits%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Rather remarkably, I wrote down this exact puzzle in my notebook a couple of years ago to which I think the answer is
17/06/2345 in DD/MM/YYYY format.
Reasoning
Notice that the first M will either be $0$ or $1$.
If it is $0$ then the first D will either be $1$ or $2$ or DD will be $31$.
If it is $1$ then either the second M will be $0$ or the second M will be $2$ and the day will contain a $0$.
Overall, this means that $0$ and either $1$ or $2$ must be used in the DD/MM part. If we don't want to skip to the next millenium, we need the $2$ for the beginning of the year.
Hence the DD/MM part requires both $0$ and $1$.
After that, we focus on the nearest year possible which comes from assigning the digits $3,4,5$ in order to century, decade and digit of the year.
It makes more sense to assign the $0$ to the month instead of $1$ but we cannot assign both since we cannot have a day without any of $0$, $1$ or $2$. Hence, we assign $6$ to the month and then $7$ to create the day.
answered Jun 7 at 13:36
hexominohexomino
53k4156248
$endgroup$
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
add a comment |
$begingroup$
Rather remarkably, I wrote down this exact puzzle in my notebook a couple of years ago to which I think the answer is
17/06/2345 in DD/MM/YYYY format.
Reasoning
Notice that the first M will either be $0$ or $1$.
If it is $0$ then the first D will either be $1$ or $2$ or DD will be $31$.
If it is $1$ then either the second M will be $0$ or the second M will be $2$ and the day will contain a $0$.
Overall, this means that $0$ and either $1$ or $2$ must be used in the DD/MM part. If we don't want to skip to the next millenium, we need the $2$ for the beginning of the year.
Hence the DD/MM part requires both $0$ and $1$.
After that, we focus on the nearest year possible which comes from assigning the digits $3,4,5$ in order to century, decade and digit of the year.
It makes more sense to assign the $0$ to the month instead of $1$ but we cannot assign both since we cannot have a day without any of $0$, $1$ or $2$. Hence, we assign $6$ to the month and then $7$ to create the day.
answered Jun 7 at 13:36
hexominohexomino
53k4156248
$endgroup$
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
add a comment |
$begingroup$
Rather remarkably, I wrote down this exact puzzle in my notebook a couple of years ago to which I think the answer is
17/06/2345 in DD/MM/YYYY format.
Reasoning
Notice that the first M will either be $0$ or $1$.
If it is $0$ then the first D will either be $1$ or $2$ or DD will be $31$.
If it is $1$ then either the second M will be $0$ or the second M will be $2$ and the day will contain a $0$.
Overall, this means that $0$ and either $1$ or $2$ must be used in the DD/MM part. If we don't want to skip to the next millenium, we need the $2$ for the beginning of the year.
Hence the DD/MM part requires both $0$ and $1$.
After that, we focus on the nearest year possible which comes from assigning the digits $3,4,5$ in order to century, decade and digit of the year.
It makes more sense to assign the $0$ to the month instead of $1$ but we cannot assign both since we cannot have a day without any of $0$, $1$ or $2$. Hence, we assign $6$ to the month and then $7$ to create the day.
answered Jun 7 at 13:36
hexominohexomino
53k4156248
$endgroup$
Rather remarkably, I wrote down this exact puzzle in my notebook a couple of years ago to which I think the answer is
17/06/2345 in DD/MM/YYYY format.
Reasoning
Notice that the first M will either be $0$ or $1$.
If it is $0$ then the first D will either be $1$ or $2$ or DD will be $31$.
If it is $1$ then either the second M will be $0$ or the second M will be $2$ and the day will contain a $0$.
Overall, this means that $0$ and either $1$ or $2$ must be used in the DD/MM part. If we don't want to skip to the next millenium, we need the $2$ for the beginning of the year.
Hence the DD/MM part requires both $0$ and $1$.
After that, we focus on the nearest year possible which comes from assigning the digits $3,4,5$ in order to century, decade and digit of the year.
It makes more sense to assign the $0$ to the month instead of $1$ but we cannot assign both since we cannot have a day without any of $0$, $1$ or $2$. Hence, we assign $6$ to the month and then $7$ to create the day.
answered Jun 7 at 13:36
hexominohexomino
53k4156248
edited Jun 7 at 13:52
answered Jun 7 at 13:36
hexominohexomino
53k4156248
answered Jun 7 at 13:36
hexominohexomino
53k4156248
answered Jun 7 at 13:36
hexominohexomino
53k4156248
53k4156248
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
add a comment |
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
8
8
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
$begingroup$
I can confirm that this is also the result of writing a dumb Python program to try future dates until it finds one satisfying the given condition.
$endgroup$
– Gareth McCaughan♦
Jun 7 at 15:04
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f84795%2fnext-date-with-distinct-digits%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
