I'm thinking of a number Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?
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I'm thinking of a number
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?systematic number removalWhat is a Voluminous Number™?Ten-digit number that satisfy divisibilty rules for 2,3,4,5,6,7,8,9,10&11What mysterious whole number am I?
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
add a comment |
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday
add a comment |
$begingroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
$endgroup$
The unusual thing about this number is that the most common phrases that use it are wrong. That is, while someone may often say there are X As in a B, the actual number is not X.
What number am I thinking of?
Hint 1:
"There are X As in a B", but almost every B contains at least X + 2 As.
Hint 2:
"There are X Cs in a D" but a D always contains between X + 0.1 and X + 0.3 Cs
number-property
number-property
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
asked yesterday
Rupert MorrishRupert Morrish
3,6851935
3,6851935
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday
add a comment |
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered yesterday
TomTom
36.4k3132209
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered yesterday
TomTom
36.4k3132209
$endgroup$
add a comment |
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered yesterday
TomTom
36.4k3132209
$endgroup$
add a comment |
$begingroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered yesterday
TomTom
36.4k3132209
$endgroup$
A number which fits is
$52$
Hint 1:
There are $52$ cards in a deck, but almost all standard decks are sold with an extra two or three jokers, as some card games need these.
Hint 2:
It's said there are $52$ weeks in a year, but a year has 365 or 366 days and,
$365/7 approx 52.14...$ and $366/7 approx 52.28...$
answered yesterday
TomTom
36.4k3132209
answered yesterday
TomTom
36.4k3132209
answered yesterday
TomTom
36.4k3132209
answered yesterday
TomTom
36.4k3132209
36.4k3132209
add a comment |
add a comment |
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$begingroup$
It looks like the hints are necessary for the actual puzzle here. Otherwise I could just answer rot13(n pbhcyr, fvapr jura jr fnl "n pbhcyr guvatf" jr hfhnyyl qba'g zrna rknpgyl gjb).
$endgroup$
– EKons
yesterday
$begingroup$
@EKons But rot13(n zneevrq pbhcyr) is correct.
$endgroup$
– Rupert Morrish
yesterday