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Field lines in a parallel plate capacitor with border effect


Drawing circular arrows in tikz to represent turns in a T-intersectionDecoration of (relative) segments of Bézier curvesRotate a node but not its content: the case of the ellipse decorationCustom shadow - border effect with TikZWrong effect with border of title pageConnect parallel lines to nodeTikz: Error “dimension too large” when decorating arcDraw dipole field linesNode with curved, parallel linesHow can I draw the capacitor smoothing effect?Place parallel line markers on parallel linesHow do I fill this area with inclined parallel lines













4















I am drawing qualitatively the field lines bending near the edges of a parallel plate capacitor with tikz. The code is:



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrary positioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
begin tikzpicture[thick, scale=0.9, every node/.style=transform
shape, decoration=
markings, mark=at position 0.5 with arrowlatex]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


The image I get is this:
enter image description here



I would like to improve the alignment of the arrow tips on the curved lines.
The arrow bases are off the lines. They should be aligned more symmetrically.
How could I fix/improve this? Perhaps just changing the arrow types will do it. The stealth style improves, but still a bit off.



Thanks in advance!










share|improve this question







New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

    – John Kormylo
    May 2 at 21:01















4















I am drawing qualitatively the field lines bending near the edges of a parallel plate capacitor with tikz. The code is:



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrary positioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
begin tikzpicture[thick, scale=0.9, every node/.style=transform
shape, decoration=
markings, mark=at position 0.5 with arrowlatex]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


The image I get is this:
enter image description here



I would like to improve the alignment of the arrow tips on the curved lines.
The arrow bases are off the lines. They should be aligned more symmetrically.
How could I fix/improve this? Perhaps just changing the arrow types will do it. The stealth style improves, but still a bit off.



Thanks in advance!










share|improve this question







New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

    – John Kormylo
    May 2 at 21:01













4












4








4


0






I am drawing qualitatively the field lines bending near the edges of a parallel plate capacitor with tikz. The code is:



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrary positioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
begin tikzpicture[thick, scale=0.9, every node/.style=transform
shape, decoration=
markings, mark=at position 0.5 with arrowlatex]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


The image I get is this:
enter image description here



I would like to improve the alignment of the arrow tips on the curved lines.
The arrow bases are off the lines. They should be aligned more symmetrically.
How could I fix/improve this? Perhaps just changing the arrow types will do it. The stealth style improves, but still a bit off.



Thanks in advance!










share|improve this question







New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am drawing qualitatively the field lines bending near the edges of a parallel plate capacitor with tikz. The code is:



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrary positioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
begin tikzpicture[thick, scale=0.9, every node/.style=transform
shape, decoration=
markings, mark=at position 0.5 with arrowlatex]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


The image I get is this:
enter image description here



I would like to improve the alignment of the arrow tips on the curved lines.
The arrow bases are off the lines. They should be aligned more symmetrically.
How could I fix/improve this? Perhaps just changing the arrow types will do it. The stealth style improves, but still a bit off.



Thanks in advance!







tikz-pgf






share|improve this question







New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked May 2 at 13:44









minmaxminmax

1233




1233




New contributor




minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






minmax is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

    – John Kormylo
    May 2 at 21:01

















  • I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

    – John Kormylo
    May 2 at 21:01
















I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

– John Kormylo
May 2 at 21:01





I've been puttng a lot of thought into computing field lines. First, field lines are the gradient of the potential (scalar) field. Second, conductors form equipotential volumes. The charge distribution is not even, but will migrate until all the potentials even out. Consequently, the equipotential lines are parallel between the plates all the way to the edge.

– John Kormylo
May 2 at 21:01










1 Answer
1






active

oldest

votes


















6














Welcome to TeX-SE! The issue is that you attach a straight arrow to a curved line. So the first step is to bend the arrow. But then the decorations do not know a priori the curvature at a given point, which can be fixed by recording some coordinates along the path and then draw a curved arrow through these coordinates.



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrarypositioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows.meta,bending
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
% from https://tex.stackexchange.com/a/430239/121799
tikzset% inspired by https://tex.stackexchange.com/a/316050/121799
arc arrow/.style args=%
to pos #1 with length #2
decoration=
markings,
mark=at position 0 with pgfextra%
pgfmathsetmacrotmpArrowTime#2/(pgfdecoratedpathlength)
xdeftmpArrowTimetmpArrowTime,
mark=at position #1-tmpArrowTime with coordinate(@1);,
mark=at position #1-2*tmpArrowTime/3 with coordinate(@2);,
mark=at position #1-tmpArrowTime/3 with coordinate(@3);,
mark=at position #1 with coordinate(@4);
draw[-Latex[length=#2,bend]]
(@1) .. controls (@2) and (@3) .. (@4);,
,



begintikzpicture[thick, scale=0.9, every node/.style=transform
shape, arc arrow=to pos 0.525 with length 2mm]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


enter image description here






share|improve this answer


















  • 1





    Worked very well. Very nice piece of tikz witchcraft! Thanks!

    – minmax
    May 2 at 19:58











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1 Answer
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active

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votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














Welcome to TeX-SE! The issue is that you attach a straight arrow to a curved line. So the first step is to bend the arrow. But then the decorations do not know a priori the curvature at a given point, which can be fixed by recording some coordinates along the path and then draw a curved arrow through these coordinates.



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrarypositioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows.meta,bending
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
% from https://tex.stackexchange.com/a/430239/121799
tikzset% inspired by https://tex.stackexchange.com/a/316050/121799
arc arrow/.style args=%
to pos #1 with length #2
decoration=
markings,
mark=at position 0 with pgfextra%
pgfmathsetmacrotmpArrowTime#2/(pgfdecoratedpathlength)
xdeftmpArrowTimetmpArrowTime,
mark=at position #1-tmpArrowTime with coordinate(@1);,
mark=at position #1-2*tmpArrowTime/3 with coordinate(@2);,
mark=at position #1-tmpArrowTime/3 with coordinate(@3);,
mark=at position #1 with coordinate(@4);
draw[-Latex[length=#2,bend]]
(@1) .. controls (@2) and (@3) .. (@4);,
,



begintikzpicture[thick, scale=0.9, every node/.style=transform
shape, arc arrow=to pos 0.525 with length 2mm]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


enter image description here






share|improve this answer


















  • 1





    Worked very well. Very nice piece of tikz witchcraft! Thanks!

    – minmax
    May 2 at 19:58















6














Welcome to TeX-SE! The issue is that you attach a straight arrow to a curved line. So the first step is to bend the arrow. But then the decorations do not know a priori the curvature at a given point, which can be fixed by recording some coordinates along the path and then draw a curved arrow through these coordinates.



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrarypositioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows.meta,bending
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
% from https://tex.stackexchange.com/a/430239/121799
tikzset% inspired by https://tex.stackexchange.com/a/316050/121799
arc arrow/.style args=%
to pos #1 with length #2
decoration=
markings,
mark=at position 0 with pgfextra%
pgfmathsetmacrotmpArrowTime#2/(pgfdecoratedpathlength)
xdeftmpArrowTimetmpArrowTime,
mark=at position #1-tmpArrowTime with coordinate(@1);,
mark=at position #1-2*tmpArrowTime/3 with coordinate(@2);,
mark=at position #1-tmpArrowTime/3 with coordinate(@3);,
mark=at position #1 with coordinate(@4);
draw[-Latex[length=#2,bend]]
(@1) .. controls (@2) and (@3) .. (@4);,
,



begintikzpicture[thick, scale=0.9, every node/.style=transform
shape, arc arrow=to pos 0.525 with length 2mm]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


enter image description here






share|improve this answer


















  • 1





    Worked very well. Very nice piece of tikz witchcraft! Thanks!

    – minmax
    May 2 at 19:58













6












6








6







Welcome to TeX-SE! The issue is that you attach a straight arrow to a curved line. So the first step is to bend the arrow. But then the decorations do not know a priori the curvature at a given point, which can be fixed by recording some coordinates along the path and then draw a curved arrow through these coordinates.



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrarypositioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows.meta,bending
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
% from https://tex.stackexchange.com/a/430239/121799
tikzset% inspired by https://tex.stackexchange.com/a/316050/121799
arc arrow/.style args=%
to pos #1 with length #2
decoration=
markings,
mark=at position 0 with pgfextra%
pgfmathsetmacrotmpArrowTime#2/(pgfdecoratedpathlength)
xdeftmpArrowTimetmpArrowTime,
mark=at position #1-tmpArrowTime with coordinate(@1);,
mark=at position #1-2*tmpArrowTime/3 with coordinate(@2);,
mark=at position #1-tmpArrowTime/3 with coordinate(@3);,
mark=at position #1 with coordinate(@4);
draw[-Latex[length=#2,bend]]
(@1) .. controls (@2) and (@3) .. (@4);,
,



begintikzpicture[thick, scale=0.9, every node/.style=transform
shape, arc arrow=to pos 0.525 with length 2mm]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


enter image description here






share|improve this answer













Welcome to TeX-SE! The issue is that you attach a straight arrow to a curved line. So the first step is to bend the arrow. But then the decorations do not know a priori the curvature at a given point, which can be fixed by recording some coordinates along the path and then draw a curved arrow through these coordinates.



documentclass[margin=10pt]standalone
usepackagetikz
usepackagebm
%usepackagepgfmath
usetikzlibrarypositioning
usetikzlibrarycalc,fadings,decorations.pathreplacing, arrows.meta,bending
usetikzlibrarydecorations.pathmorphing,patterns
usetikzlibrarydecorations.markings
begindocument
% from https://tex.stackexchange.com/a/430239/121799
tikzset% inspired by https://tex.stackexchange.com/a/316050/121799
arc arrow/.style args=%
to pos #1 with length #2
decoration=
markings,
mark=at position 0 with pgfextra%
pgfmathsetmacrotmpArrowTime#2/(pgfdecoratedpathlength)
xdeftmpArrowTimetmpArrowTime,
mark=at position #1-tmpArrowTime with coordinate(@1);,
mark=at position #1-2*tmpArrowTime/3 with coordinate(@2);,
mark=at position #1-tmpArrowTime/3 with coordinate(@3);,
mark=at position #1 with coordinate(@4);
draw[-Latex[length=#2,bend]]
(@1) .. controls (@2) and (@3) .. (@4);,
,



begintikzpicture[thick, scale=0.9, every node/.style=transform
shape, arc arrow=to pos 0.525 with length 2mm]
defLx5.0
defxi0.25
defdx0.5
defdy0.35
defhh2.0
% top plate
filldraw[opacity=0.2] (0, 0) -- (Lx, 0) -- (Lx, dy) -- (0, dy);
draw (Lx/2, hh+2.*dy) node[] $bm -Q$;
% bottom plate
filldraw[opacity=0.2] (0, hh) -- (Lx, hh) -- (Lx, hh+dy) -- (0, hh+dy);
draw (Lx/2, -dy) node[] $bm +Q$;
% left curved lines
draw[postaction=decorate] (xi, dy) node[below= -0.14, red] $bm +$ to
[bend left=15] (xi, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (0, dy) .. controls (-dx, 0.35*(hh+dy)) and (-dx,0.65*(hh+dy)) .. (0, hh);
draw[postaction=decorate] (0, 0.7*dy) .. controls (-3*dx, 0.1*(hh+dy))
and (-3*dx,0.9*(hh+dy)) .. (0, hh+0.3*dy);
draw[postaction=decorate] (0, 0.2*dy) .. controls (-6*dx, 0.0*(hh+dy))
and (-6*dx,(hh+dy)) .. (0, hh+0.8*dy);
% Middle lines
foreach nL in 1, 2, ..., 8
draw[red] (xi+nL*dx, 0.65*dy) node[] $bm +$;
draw[blue] (xi+nL*dx, hh+0.1*dy) node[] $bm -$;
draw[postaction=decorate] (xi+nL*dx, dy) --++ (0, hh-dy);

% right curved lines
draw[postaction=decorate] (xi+9*dx, dy) node[below= -0.14, red] $bm +$
to [bend right=15] (xi+9*dx, hh) node[above=-0.24, blue] $bm -$;
draw[postaction=decorate] (Lx, dy) .. controls (Lx+dx, 0.35*(hh+dy)) and (Lx+dx,0.65*(hh+dy)) .. (Lx, hh);
draw[postaction=decorate] (Lx, 0.7*dy) .. controls (Lx+3*dx,
0.1*(hh+dy)) and (Lx+3*dx,0.90*(hh+dy)) .. (Lx, hh+0.3*dy);
draw[postaction=decorate] (Lx, 0.2*dy) .. controls (Lx+6*dx,
0.0*(hh+dy)) and (Lx+6*dx,(hh+dy)) .. (Lx, hh+0.8*dy);

endtikzpicture
enddocument


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered May 2 at 15:36









marmotmarmot

124k6161304




124k6161304







  • 1





    Worked very well. Very nice piece of tikz witchcraft! Thanks!

    – minmax
    May 2 at 19:58












  • 1





    Worked very well. Very nice piece of tikz witchcraft! Thanks!

    – minmax
    May 2 at 19:58







1




1





Worked very well. Very nice piece of tikz witchcraft! Thanks!

– minmax
May 2 at 19:58





Worked very well. Very nice piece of tikz witchcraft! Thanks!

– minmax
May 2 at 19:58










minmax is a new contributor. Be nice, and check out our Code of Conduct.









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minmax is a new contributor. Be nice, and check out our Code of Conduct.












minmax is a new contributor. Be nice, and check out our Code of Conduct.











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