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SafeCracker #3 - We've Been Blocked [on hold]
What are the features of a well-written puzzle?I've been everywhere, manCircuit DiagramA riddle that has been killing me the whole daySafeCracker #1 - Look who's talkingSafeCracker #2 - The Mission Continues
$begingroup$
Our Last Safe To Conquer
Ok, team, this one might give us a little trouble. Nothing we can't handle though... let's go...
This safe model is "The NevaCrak 9000" - the most secure safe there is.
Our only way in is to look at our puzzle, and simply find the block that doesn't belong.
A couple blocks are blank and are to be ignored. Only concern yourself with blocks with numbers and letters. Also disregard any of the flaire going on in the background.
THAT's IT
Everything is riding on you... go open that bad boy!
And here is the NevaCrak 9000
Which block does not belong??
( only one correct answer, no tricks or worplay involved )
number-sequence formation-of-numbers grid-deduction algorithm algebra
asked May 2 at 15:29
John S.John S.
52412
$endgroup$
put on hold as too broad by noedne, PiIsNot3, Brandon_J, Peregrine Rook, Omega Krypton 2 days ago
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
|
show 17 more comments
$begingroup$
Our Last Safe To Conquer
Ok, team, this one might give us a little trouble. Nothing we can't handle though... let's go...
This safe model is "The NevaCrak 9000" - the most secure safe there is.
Our only way in is to look at our puzzle, and simply find the block that doesn't belong.
A couple blocks are blank and are to be ignored. Only concern yourself with blocks with numbers and letters. Also disregard any of the flaire going on in the background.
THAT's IT
Everything is riding on you... go open that bad boy!
And here is the NevaCrak 9000
Which block does not belong??
( only one correct answer, no tricks or worplay involved )
number-sequence formation-of-numbers grid-deduction algorithm algebra
asked May 2 at 15:29
John S.John S.
52412
$endgroup$
put on hold as too broad by noedne, PiIsNot3, Brandon_J, Peregrine Rook, Omega Krypton 2 days ago
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
5
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
3
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
5
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
6
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
4
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago
|
show 17 more comments
$begingroup$
Our Last Safe To Conquer
Ok, team, this one might give us a little trouble. Nothing we can't handle though... let's go...
This safe model is "The NevaCrak 9000" - the most secure safe there is.
Our only way in is to look at our puzzle, and simply find the block that doesn't belong.
A couple blocks are blank and are to be ignored. Only concern yourself with blocks with numbers and letters. Also disregard any of the flaire going on in the background.
THAT's IT
Everything is riding on you... go open that bad boy!
And here is the NevaCrak 9000
Which block does not belong??
( only one correct answer, no tricks or worplay involved )
number-sequence formation-of-numbers grid-deduction algorithm algebra
asked May 2 at 15:29
John S.John S.
52412
$endgroup$
Our Last Safe To Conquer
Ok, team, this one might give us a little trouble. Nothing we can't handle though... let's go...
This safe model is "The NevaCrak 9000" - the most secure safe there is.
Our only way in is to look at our puzzle, and simply find the block that doesn't belong.
A couple blocks are blank and are to be ignored. Only concern yourself with blocks with numbers and letters. Also disregard any of the flaire going on in the background.
THAT's IT
Everything is riding on you... go open that bad boy!
And here is the NevaCrak 9000
Which block does not belong??
( only one correct answer, no tricks or worplay involved )
number-sequence formation-of-numbers grid-deduction algorithm algebra
number-sequence formation-of-numbers grid-deduction algorithm algebra
asked May 2 at 15:29
John S.John S.
52412
asked May 2 at 15:29
John S.John S.
52412
edited May 2 at 17:51
John S.
asked May 2 at 15:29
John S.John S.
52412
asked May 2 at 15:29
John S.John S.
52412
asked May 2 at 15:29
John S.John S.
52412
52412
put on hold as too broad by noedne, PiIsNot3, Brandon_J, Peregrine Rook, Omega Krypton 2 days ago
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as too broad by noedne, PiIsNot3, Brandon_J, Peregrine Rook, Omega Krypton 2 days ago
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
5
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
3
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
5
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
6
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
4
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago
|
show 17 more comments
5
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
3
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
5
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
6
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
4
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago
5
5
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
3
3
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
5
5
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
6
6
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
4
4
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago
|
show 17 more comments
10 Answers
10
active
oldest
votes
$begingroup$
The odd one out is the
green block with 5246.
This is because
for all the other numbers on the other blocks, combining the first and last digits and dividing by 2 gave the middle two digits. However, 5246 does not apply to that rule. To conform it to that rule, it would have to be 4248 (one of many possible fixes)...
Safe Cracked!
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
$endgroup$
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
|
show 3 more comments
$begingroup$
The
green block with the number 5246
doesn't belong, because
it is the only number not divisible by 3 where all the others are.
edited May 2 at 16:44
Invent Palooza
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
I'm going to guess the:
Black block.
It's the only one that isn't a tetris piece :P
answered May 2 at 16:09
SmockSmock
5988
$endgroup$
add a comment |
$begingroup$
I will guess that it is
Green block 5246
My reasoning is that
All other blocks have numbers that are divisible by 6, and it is the only block that has two prime factor other than 2 and 3. The prime factors of all other numbers are some number of 2s and 3s, and one other larger prime number. 5246 factorizes to 2, 43, and 61.
answered May 2 at 20:18
David KDavid K
24519
$endgroup$
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
My answer:
When arranging the numbers in the order of the word Stack Exchange, and then doing an absolute value of the difference between any number and the following number, I get a pattern that the difference value rises then drops alternatingly, except at the Black A where the value remains the same. (Differences: 4176,8214,8214,3150,5088,1950,5274,2152,4252,0,4224,3126 - rise fall neutral fall rise fall rise fall rise fall rise fall)
Below is Meant as comment, but alas
@John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039
[ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
It is missing data.
The last three are the orange blocks, the second to last three are the black blocks, the third to last three are the green blocks and the first 2 are only half of the yellow blocks, the x and k are missing.
However:
There are two pairs letters with same numbers, 9498 and 8412.
Also:
John stated elsewhere its just a numbers game...which makes sense because the letters spell out Stack Exchange
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
The answer is:
The green block with the number 9498.
because
The average of the numbers on the green blocks is not a whole, even number (as it is for the other sets of blocks) and the number 9498 here is a duplicate of another block. This block could be 9496 which would make it valid.
answered May 2 at 20:30
Amru E.Amru E.
1213
New contributor
Amru E. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Answer:
The Black A
Reason:
It's the only one that has 11 as a factor
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I would guess it is the:
Yellow block that has the E and the number 174
Why?
All other group of blocks follow the pattern of increasing/decreasing the number as the letters advance through the alphabet.
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
$endgroup$
add a comment |
$begingroup$
The answer might be:
The yellow one
Reasoning:
All the other blocks have only letters when looked at from a specific direction.
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
$endgroup$
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
add a comment |
$begingroup$
I noticed that
if you open out the net of each, centred on the side showing the letter, any numbers above, below and to the right are all aligned in the same direction as the letter; and the number on the left is on its side, with its top pointing to the left. The only exception is the Yellow K block, where the number on the right isn't aligned in the same direction as the letter.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
|
show 9 more comments
10 Answers
10
active
oldest
votes
10 Answers
10
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The odd one out is the
green block with 5246.
This is because
for all the other numbers on the other blocks, combining the first and last digits and dividing by 2 gave the middle two digits. However, 5246 does not apply to that rule. To conform it to that rule, it would have to be 4248 (one of many possible fixes)...
Safe Cracked!
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
$endgroup$
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
|
show 3 more comments
$begingroup$
The odd one out is the
green block with 5246.
This is because
for all the other numbers on the other blocks, combining the first and last digits and dividing by 2 gave the middle two digits. However, 5246 does not apply to that rule. To conform it to that rule, it would have to be 4248 (one of many possible fixes)...
Safe Cracked!
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
$endgroup$
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
|
show 3 more comments
$begingroup$
The odd one out is the
green block with 5246.
This is because
for all the other numbers on the other blocks, combining the first and last digits and dividing by 2 gave the middle two digits. However, 5246 does not apply to that rule. To conform it to that rule, it would have to be 4248 (one of many possible fixes)...
Safe Cracked!
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
$endgroup$
The odd one out is the
green block with 5246.
This is because
for all the other numbers on the other blocks, combining the first and last digits and dividing by 2 gave the middle two digits. However, 5246 does not apply to that rule. To conform it to that rule, it would have to be 4248 (one of many possible fixes)...
Safe Cracked!
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
edited May 2 at 23:24
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
answered May 2 at 16:47
Invent PaloozaInvent Palooza
21912
21912
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
|
show 3 more comments
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
The answer should be a single block (the ones that have a letter and number); not a complete group of blocks
$endgroup$
– Daniel Duque
May 2 at 17:52
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
$begingroup$
Yes. Ok, I am giving a very small , yet critical Hint: It's all a numbers game, it's allll a numbers game.
$endgroup$
– John S.
May 2 at 18:32
1
1
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
$begingroup$
@JohnS. Didn't Ak19 correctly identify this block in an earlier answer?
$endgroup$
– noedne
May 2 at 23:40
2
2
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
$begingroup$
@JohnS. While Invent's original answer (divisible by 3) is an accurate pattern and a good find, Ak19 posted it first. It's also not the same as your "correct" answer. At all. You just got tired of waiting for someone to discover your solution and decided to give it away to someone.
$endgroup$
– David K
2 days ago
1
1
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
$begingroup$
No, there are many correct answers, as I have been pointed out. I wlll never make a puzzle with multiple solutions again. Not intentional anyways. He got a correct answer, we can't take that away from him. I am new here, so this is a learning lesson. I will be more specific in the future if I submit more. Thank you for your comment, though.
$endgroup$
– John S.
2 days ago
|
show 3 more comments
$begingroup$
The
green block with the number 5246
doesn't belong, because
it is the only number not divisible by 3 where all the others are.
edited May 2 at 16:44
Invent Palooza
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
The
green block with the number 5246
doesn't belong, because
it is the only number not divisible by 3 where all the others are.
edited May 2 at 16:44
Invent Palooza
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
The
green block with the number 5246
doesn't belong, because
it is the only number not divisible by 3 where all the others are.
edited May 2 at 16:44
Invent Palooza
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
The
green block with the number 5246
doesn't belong, because
it is the only number not divisible by 3 where all the others are.
edited May 2 at 16:44
Invent Palooza
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited May 2 at 16:44
Invent Palooza
21912
edited May 2 at 16:44
Invent Palooza
21912
edited May 2 at 16:44
Invent Palooza
21912
21912
answered May 2 at 16:41
Ak19Ak19
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered May 2 at 16:41
Ak19Ak19
2689
answered May 2 at 16:41
Ak19Ak19
2689
2689
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ak19 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
Ak19, that is a very good suggested answer, however, it is not correct. You are thinking along the correct path, however.
$endgroup$
– John S.
May 2 at 16:48
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
$begingroup$
@Invent: 99.99999999%
$endgroup$
– John S.
May 2 at 17:55
1
1
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
This is the right answer, for a slightly weaker reason than the ‘‘official’’ one.
$endgroup$
– Peregrine Rook
May 3 at 2:20
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
all the numbers had exactly 3 prime factors. they were all (2,3,X) for mostly very large X (ranging from 11 to 1583). The only outlier is 5246 with prime factors of (2,43,61) once I saw this I couldn't look away!
$endgroup$
– stew
2 days ago
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
$begingroup$
@stew: Your comment is essentially the same as David K’s answer.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
I'm going to guess the:
Black block.
It's the only one that isn't a tetris piece :P
answered May 2 at 16:09
SmockSmock
5988
$endgroup$
add a comment |
$begingroup$
I'm going to guess the:
Black block.
It's the only one that isn't a tetris piece :P
answered May 2 at 16:09
SmockSmock
5988
$endgroup$
add a comment |
$begingroup$
I'm going to guess the:
Black block.
It's the only one that isn't a tetris piece :P
answered May 2 at 16:09
SmockSmock
5988
$endgroup$
I'm going to guess the:
Black block.
It's the only one that isn't a tetris piece :P
answered May 2 at 16:09
SmockSmock
5988
answered May 2 at 16:09
SmockSmock
5988
answered May 2 at 16:09
SmockSmock
5988
answered May 2 at 16:09
SmockSmock
5988
5988
add a comment |
add a comment |
$begingroup$
I will guess that it is
Green block 5246
My reasoning is that
All other blocks have numbers that are divisible by 6, and it is the only block that has two prime factor other than 2 and 3. The prime factors of all other numbers are some number of 2s and 3s, and one other larger prime number. 5246 factorizes to 2, 43, and 61.
answered May 2 at 20:18
David KDavid K
24519
$endgroup$
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
I will guess that it is
Green block 5246
My reasoning is that
All other blocks have numbers that are divisible by 6, and it is the only block that has two prime factor other than 2 and 3. The prime factors of all other numbers are some number of 2s and 3s, and one other larger prime number. 5246 factorizes to 2, 43, and 61.
answered May 2 at 20:18
David KDavid K
24519
$endgroup$
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
I will guess that it is
Green block 5246
My reasoning is that
All other blocks have numbers that are divisible by 6, and it is the only block that has two prime factor other than 2 and 3. The prime factors of all other numbers are some number of 2s and 3s, and one other larger prime number. 5246 factorizes to 2, 43, and 61.
answered May 2 at 20:18
David KDavid K
24519
$endgroup$
I will guess that it is
Green block 5246
My reasoning is that
All other blocks have numbers that are divisible by 6, and it is the only block that has two prime factor other than 2 and 3. The prime factors of all other numbers are some number of 2s and 3s, and one other larger prime number. 5246 factorizes to 2, 43, and 61.
answered May 2 at 20:18
David KDavid K
24519
answered May 2 at 20:18
David KDavid K
24519
answered May 2 at 20:18
David KDavid K
24519
answered May 2 at 20:18
David KDavid K
24519
24519
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
This is equivalent to Ak19’s answer, but worded in a more complicated way.
$endgroup$
– Peregrine Rook
May 3 at 2:21
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
$begingroup$
@PeregrineRook It is an expansion of Ak19's answer, but they are not equivalent. The OP indicated that Ak19 was thinking along the correct path, so I dug deeper in that direction.
$endgroup$
– David K
2 days ago
1
1
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
$begingroup$
Ah, I see. OK, you’re right. Your answer encompasses Ak19’s answer, but you found something more. (Now it turns out that Ak19’s answer was very close to what the OP was looking for, and yours was not, but that doesn’t reflect badly on your answer. It just goes to support the argument that the question is too broad, because it has too many different answers.) I would upvote you, but I already did.
$endgroup$
– Peregrine Rook
yesterday
add a comment |
$begingroup$
My answer:
When arranging the numbers in the order of the word Stack Exchange, and then doing an absolute value of the difference between any number and the following number, I get a pattern that the difference value rises then drops alternatingly, except at the Black A where the value remains the same. (Differences: 4176,8214,8214,3150,5088,1950,5274,2152,4252,0,4224,3126 - rise fall neutral fall rise fall rise fall rise fall rise fall)
Below is Meant as comment, but alas
@John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039
[ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
It is missing data.
The last three are the orange blocks, the second to last three are the black blocks, the third to last three are the green blocks and the first 2 are only half of the yellow blocks, the x and k are missing.
However:
There are two pairs letters with same numbers, 9498 and 8412.
Also:
John stated elsewhere its just a numbers game...which makes sense because the letters spell out Stack Exchange
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
My answer:
When arranging the numbers in the order of the word Stack Exchange, and then doing an absolute value of the difference between any number and the following number, I get a pattern that the difference value rises then drops alternatingly, except at the Black A where the value remains the same. (Differences: 4176,8214,8214,3150,5088,1950,5274,2152,4252,0,4224,3126 - rise fall neutral fall rise fall rise fall rise fall rise fall)
Below is Meant as comment, but alas
@John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039
[ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
It is missing data.
The last three are the orange blocks, the second to last three are the black blocks, the third to last three are the green blocks and the first 2 are only half of the yellow blocks, the x and k are missing.
However:
There are two pairs letters with same numbers, 9498 and 8412.
Also:
John stated elsewhere its just a numbers game...which makes sense because the letters spell out Stack Exchange
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
My answer:
When arranging the numbers in the order of the word Stack Exchange, and then doing an absolute value of the difference between any number and the following number, I get a pattern that the difference value rises then drops alternatingly, except at the Black A where the value remains the same. (Differences: 4176,8214,8214,3150,5088,1950,5274,2152,4252,0,4224,3126 - rise fall neutral fall rise fall rise fall rise fall rise fall)
Below is Meant as comment, but alas
@John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039
[ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
It is missing data.
The last three are the orange blocks, the second to last three are the black blocks, the third to last three are the green blocks and the first 2 are only half of the yellow blocks, the x and k are missing.
However:
There are two pairs letters with same numbers, 9498 and 8412.
Also:
John stated elsewhere its just a numbers game...which makes sense because the letters spell out Stack Exchange
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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My answer:
When arranging the numbers in the order of the word Stack Exchange, and then doing an absolute value of the difference between any number and the following number, I get a pattern that the difference value rises then drops alternatingly, except at the Black A where the value remains the same. (Differences: 4176,8214,8214,3150,5088,1950,5274,2152,4252,0,4224,3126 - rise fall neutral fall rise fall rise fall rise fall rise fall)
Below is Meant as comment, but alas
@John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039
[ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
It is missing data.
The last three are the orange blocks, the second to last three are the black blocks, the third to last three are the green blocks and the first 2 are only half of the yellow blocks, the x and k are missing.
However:
There are two pairs letters with same numbers, 9498 and 8412.
Also:
John stated elsewhere its just a numbers game...which makes sense because the letters spell out Stack Exchange
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
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edited May 2 at 20:39
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
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answered May 2 at 20:16
wolfsshieldwolfsshield
2186
answered May 2 at 20:16
wolfsshieldwolfsshield
2186
2186
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New contributor
wolfsshield is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
add a comment |
$begingroup$
The answer is:
The green block with the number 9498.
because
The average of the numbers on the green blocks is not a whole, even number (as it is for the other sets of blocks) and the number 9498 here is a duplicate of another block. This block could be 9496 which would make it valid.
answered May 2 at 20:30
Amru E.Amru E.
1213
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add a comment |
$begingroup$
The answer is:
The green block with the number 9498.
because
The average of the numbers on the green blocks is not a whole, even number (as it is for the other sets of blocks) and the number 9498 here is a duplicate of another block. This block could be 9496 which would make it valid.
answered May 2 at 20:30
Amru E.Amru E.
1213
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add a comment |
$begingroup$
The answer is:
The green block with the number 9498.
because
The average of the numbers on the green blocks is not a whole, even number (as it is for the other sets of blocks) and the number 9498 here is a duplicate of another block. This block could be 9496 which would make it valid.
answered May 2 at 20:30
Amru E.Amru E.
1213
New contributor
Amru E. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
The answer is:
The green block with the number 9498.
because
The average of the numbers on the green blocks is not a whole, even number (as it is for the other sets of blocks) and the number 9498 here is a duplicate of another block. This block could be 9496 which would make it valid.
answered May 2 at 20:30
Amru E.Amru E.
1213
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edited May 2 at 20:36
answered May 2 at 20:30
Amru E.Amru E.
1213
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answered May 2 at 20:30
Amru E.Amru E.
1213
answered May 2 at 20:30
Amru E.Amru E.
1213
1213
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add a comment |
add a comment |
$begingroup$
Answer:
The Black A
Reason:
It's the only one that has 11 as a factor
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
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add a comment |
$begingroup$
Answer:
The Black A
Reason:
It's the only one that has 11 as a factor
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
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add a comment |
$begingroup$
Answer:
The Black A
Reason:
It's the only one that has 11 as a factor
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
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Answer:
The Black A
Reason:
It's the only one that has 11 as a factor
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
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answered May 2 at 21:20
wolfsshieldwolfsshield
2186
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answered May 2 at 21:20
wolfsshieldwolfsshield
2186
answered May 2 at 21:20
wolfsshieldwolfsshield
2186
2186
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New contributor
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add a comment |
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$begingroup$
I would guess it is the:
Yellow block that has the E and the number 174
Why?
All other group of blocks follow the pattern of increasing/decreasing the number as the letters advance through the alphabet.
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
$endgroup$
add a comment |
$begingroup$
I would guess it is the:
Yellow block that has the E and the number 174
Why?
All other group of blocks follow the pattern of increasing/decreasing the number as the letters advance through the alphabet.
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
$endgroup$
add a comment |
$begingroup$
I would guess it is the:
Yellow block that has the E and the number 174
Why?
All other group of blocks follow the pattern of increasing/decreasing the number as the letters advance through the alphabet.
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
$endgroup$
I would guess it is the:
Yellow block that has the E and the number 174
Why?
All other group of blocks follow the pattern of increasing/decreasing the number as the letters advance through the alphabet.
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
answered May 2 at 17:47
Daniel DuqueDaniel Duque
1565
1565
add a comment |
add a comment |
$begingroup$
The answer might be:
The yellow one
Reasoning:
All the other blocks have only letters when looked at from a specific direction.
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
$endgroup$
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
add a comment |
$begingroup$
The answer might be:
The yellow one
Reasoning:
All the other blocks have only letters when looked at from a specific direction.
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
$endgroup$
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
add a comment |
$begingroup$
The answer might be:
The yellow one
Reasoning:
All the other blocks have only letters when looked at from a specific direction.
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
$endgroup$
The answer might be:
The yellow one
Reasoning:
All the other blocks have only letters when looked at from a specific direction.
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
answered May 2 at 15:39
Krad CigolKrad Cigol
1,096212
1,096212
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
add a comment |
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
No, sorry. We are looking for an individual block that just doesn't fit the criteria of all the others. - But that was a reasonable guess!
$endgroup$
– John S.
May 2 at 15:40
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
HERE IS THE DATA SET FOR THIS PUZZLE... Now, we are back to our regularly scheduled "What doesn't belong in this pattern?" puzzle. [ C, 8412, E, 174,H, 5246,C, 7398,A, 9498,S, 4236,A, 198,T, 8412,N, 9498,G, 5274,E, 2148 ]
$endgroup$
– John S.
May 2 at 19:06
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
$begingroup$
Delete this question. Not editing it. ANSWER WAS SIMPLE: take first number and last number , combine. Divide by 2. will give you middle number. ONLY ONE block doesn't fit criteria. People had fun trying, you can delete. Thanks.
$endgroup$
– John S.
2 days ago
add a comment |
$begingroup$
I noticed that
if you open out the net of each, centred on the side showing the letter, any numbers above, below and to the right are all aligned in the same direction as the letter; and the number on the left is on its side, with its top pointing to the left. The only exception is the Yellow K block, where the number on the right isn't aligned in the same direction as the letter.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
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MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
|
show 9 more comments
$begingroup$
I noticed that
if you open out the net of each, centred on the side showing the letter, any numbers above, below and to the right are all aligned in the same direction as the letter; and the number on the left is on its side, with its top pointing to the left. The only exception is the Yellow K block, where the number on the right isn't aligned in the same direction as the letter.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
|
show 9 more comments
$begingroup$
I noticed that
if you open out the net of each, centred on the side showing the letter, any numbers above, below and to the right are all aligned in the same direction as the letter; and the number on the left is on its side, with its top pointing to the left. The only exception is the Yellow K block, where the number on the right isn't aligned in the same direction as the letter.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I noticed that
if you open out the net of each, centred on the side showing the letter, any numbers above, below and to the right are all aligned in the same direction as the letter; and the number on the left is on its side, with its top pointing to the left. The only exception is the Yellow K block, where the number on the right isn't aligned in the same direction as the letter.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
answered May 2 at 16:39
MichaelMaggsMichaelMaggs
19311
19311
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
MichaelMaggs is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
|
show 9 more comments
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
1
1
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
$begingroup$
Looks like there is more than one valid solution :(
$endgroup$
– MichaelMaggs
May 2 at 16:51
5
5
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
$begingroup$
If there's more than one block that's different from the others in a notable way and the challenge is to figure out what specific difference you had in mind, then the puzzle is basically "read the puzzle author's mind". Let's hope it turns out that the odd-one-out property John S intends is much more compelling than the two other perfectly plausible ones suggested so far...
$endgroup$
– Gareth McCaughan♦
May 2 at 17:42
1
1
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
$begingroup$
It is the other way around >! This is a hint.
$endgroup$
– Daniel Duque
May 2 at 18:33
1
1
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
$begingroup$
@JohnS. typically we use Rot13 to hide hints or spoilers in comments. But I’d strongly recommend you put the hints in the original post, since they would be considered part of the overall puzzle
$endgroup$
– PiIsNot3
May 2 at 19:12
1
1
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
$begingroup$
@JohnS. A "What's next?" like you describe should also be closed for being too broad...
$endgroup$
– noedne
May 2 at 21:24
|
show 9 more comments
5
$begingroup$
@JohnS. "What comes next number puzzles" can also have many correct answers...
$endgroup$
– noedne
May 2 at 17:25
3
$begingroup$
@JohnS. Also, I’m not sure that insulting the puzzle solver’s intelligence will suddenly make them figure out the answer...
$endgroup$
– PiIsNot3
May 2 at 22:57
5
$begingroup$
@JohnS. This has nothing to do with being a new member but rather the content of the puzzle itself. We’re all trying to provide guidance on how you can improve your questions and what’s considered on-topic here. I sincerely hope you don’t take any of our criticism personally! :)
$endgroup$
– PiIsNot3
May 2 at 23:32
6
$begingroup$
@JohnS. I understand your frustration. You wrote a puzzle with a solution that clearly works when you find it. But I encourage you to think for a moment from the puzzle solver's perspective. Ak19 came up with a rule that works perfectly well to find an odd block out. From their perspective, they have no way of knowing that this is not the solution you intended. When you tell them it's not what you had in mind, it may feel unfair that their valid solution is deemed incorrect. It's important for puzzles to have unique solutions, but it's easy to miss things no matter how good your intentions.
$endgroup$
– noedne
May 3 at 3:13
4
$begingroup$
@JohnS. Compare the current question to a similar one: "What is the odd one out among the values 1, 2, 3, 4, 5?" Without any additional specifications from the author, any number of answers would be equally valid (5, because it's the only multiple of 5; 4, because it's the only composite number; etc. etc.), and thus the "correct" answer becomes a subjective choice. It's not the task itself that is problematic, but rather determining whether a possible answer is right or not. Also, I'm not sure how being a paid member of SE is relevant to this conversation.
$endgroup$
– PiIsNot3
2 days ago