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how to plot complicated function


pgfplots: Plot inverse function (function of y)How to plot the function f(x) = sin(1/x)How to draw one smooth plot taking into account intervals of some functionPlot function with discontinuitycomplicated surface plot (projection and cut)How can I limit the length of a plotted function?pgfplots can not plot this function correctlyPlot a function of logarithm with PGFplotsWant to plot curve from points and want to remove axis valueshow to plot function from multiple points






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















i know how to draw axis and everything else except the function here , please give me hint to plot this function



enter image description here



Thanks for the help










share|improve this question

















  • 2





    Could you please add a minimal example of what you managed to do?

    – CarLaTeX
    Jun 19 at 5:03

















3















i know how to draw axis and everything else except the function here , please give me hint to plot this function



enter image description here



Thanks for the help










share|improve this question

















  • 2





    Could you please add a minimal example of what you managed to do?

    – CarLaTeX
    Jun 19 at 5:03













3












3








3


1






i know how to draw axis and everything else except the function here , please give me hint to plot this function



enter image description here



Thanks for the help










share|improve this question














i know how to draw axis and everything else except the function here , please give me hint to plot this function



enter image description here



Thanks for the help







tikz-pgf pgfplots tikz-graphs






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jun 19 at 4:59









QuintisQuintis

594 bronze badges




594 bronze badges







  • 2





    Could you please add a minimal example of what you managed to do?

    – CarLaTeX
    Jun 19 at 5:03












  • 2





    Could you please add a minimal example of what you managed to do?

    – CarLaTeX
    Jun 19 at 5:03







2




2





Could you please add a minimal example of what you managed to do?

– CarLaTeX
Jun 19 at 5:03





Could you please add a minimal example of what you managed to do?

– CarLaTeX
Jun 19 at 5:03










2 Answers
2






active

oldest

votes


















5














Is this what you want?



enter image description here



documentclass[tikz,border=1mm]standalone
usepackageamsmath,amssymb
begindocument
begintikzpicture[x=4cm,y=5cm]
beginscope
clip (-.2,-.2) rectangle (1.6,1.2);
draw[dashed,magenta]
(0,0) .. controls +(0:.3) and +(181:1.75) .. (1.5,.97);
draw[blue] (0,0) .. controls +(0:.25) and +(180:1.8) ..
(1.5,.97);
endscope

foreach i in .1,.2,...,1.5
draw (i,0)--+(90:1mm);
foreach i in 0.3,0.6,0.9,1.2,1.5
draw (i,0) node[below]$i$--+(90:2mm);

foreach j in .1,.2,...,1.1
draw (0,j)--+(0:1mm);
foreach j in 0.2,0.4,0.6,0.8,1
draw (0,j) node[left]$j$--+(0:2mm);

draw (0,1.1)--(0,0)--(1.5,0);
draw[red,dotted,thick] (0,1)--+(0:1.5);
path (0,0) node[below]$0$ node[left]$0$;

draw[blue] (.7,.7)--++(0:.4) node[right]Debye;
draw[magenta,dashed]
(.7,.6)--++(0:.4) node[right]Einstein;

path
(current bounding box.west) coordinate (W)
(current bounding box.south) coordinate (S);
path
(W)++(90:.1) node[left=5mm,rotate=90]$dfracC_V3NK$
(S) node[below=-4mm]$T/theta$;

endtikzpicture
enddocument





share|improve this answer























  • thanks a lot , i just needed to see how to plot these functions

    – Quintis
    Jun 19 at 15:19











  • btw how did u exactly draw this picture without using the function ?

    – Quintis
    Jun 19 at 15:24











  • I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

    – Black Mild
    Jun 19 at 16:00







  • 5





    One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

    – marmot
    Jun 19 at 16:19


















11














You could declare a function and plot it. The relevant function is well known, see e.g. this Wikipedia article.



documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[
declare function=
cV(T,TD,a,b) =
(a/(T/TD))^2 * exp(b/(T/TD)) / (exp(b/(T/TD))-1)^2;
,
]
beginaxis[
xlabel=$T/T_mathrmD$,
ylabel=$c_V/(3Nk_mathrmB)$,
legend style=at=(0.9,0.6),
domain=0.001:1.5,
samples=101,
smooth,
]
addplot [black] cV(x,1,1,1);
addplot [dashed] cV(x,(pi/6)^(-1/3),1,1);
addplot [densely dotted,red,samples=2] 1;

legend
Debye,
Einstein,

endaxis
endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Oh i see so declaring function would solve everything huh ? , i appreciate a lot

    – Quintis
    Jun 19 at 5:22






  • 1





    @Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

    – marmot
    Jun 19 at 5:25











  • Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

    – manooooh
    Jun 19 at 16:36







  • 1





    @manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

    – marmot
    Jun 19 at 16:41













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














Is this what you want?



enter image description here



documentclass[tikz,border=1mm]standalone
usepackageamsmath,amssymb
begindocument
begintikzpicture[x=4cm,y=5cm]
beginscope
clip (-.2,-.2) rectangle (1.6,1.2);
draw[dashed,magenta]
(0,0) .. controls +(0:.3) and +(181:1.75) .. (1.5,.97);
draw[blue] (0,0) .. controls +(0:.25) and +(180:1.8) ..
(1.5,.97);
endscope

foreach i in .1,.2,...,1.5
draw (i,0)--+(90:1mm);
foreach i in 0.3,0.6,0.9,1.2,1.5
draw (i,0) node[below]$i$--+(90:2mm);

foreach j in .1,.2,...,1.1
draw (0,j)--+(0:1mm);
foreach j in 0.2,0.4,0.6,0.8,1
draw (0,j) node[left]$j$--+(0:2mm);

draw (0,1.1)--(0,0)--(1.5,0);
draw[red,dotted,thick] (0,1)--+(0:1.5);
path (0,0) node[below]$0$ node[left]$0$;

draw[blue] (.7,.7)--++(0:.4) node[right]Debye;
draw[magenta,dashed]
(.7,.6)--++(0:.4) node[right]Einstein;

path
(current bounding box.west) coordinate (W)
(current bounding box.south) coordinate (S);
path
(W)++(90:.1) node[left=5mm,rotate=90]$dfracC_V3NK$
(S) node[below=-4mm]$T/theta$;

endtikzpicture
enddocument





share|improve this answer























  • thanks a lot , i just needed to see how to plot these functions

    – Quintis
    Jun 19 at 15:19











  • btw how did u exactly draw this picture without using the function ?

    – Quintis
    Jun 19 at 15:24











  • I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

    – Black Mild
    Jun 19 at 16:00







  • 5





    One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

    – marmot
    Jun 19 at 16:19















5














Is this what you want?



enter image description here



documentclass[tikz,border=1mm]standalone
usepackageamsmath,amssymb
begindocument
begintikzpicture[x=4cm,y=5cm]
beginscope
clip (-.2,-.2) rectangle (1.6,1.2);
draw[dashed,magenta]
(0,0) .. controls +(0:.3) and +(181:1.75) .. (1.5,.97);
draw[blue] (0,0) .. controls +(0:.25) and +(180:1.8) ..
(1.5,.97);
endscope

foreach i in .1,.2,...,1.5
draw (i,0)--+(90:1mm);
foreach i in 0.3,0.6,0.9,1.2,1.5
draw (i,0) node[below]$i$--+(90:2mm);

foreach j in .1,.2,...,1.1
draw (0,j)--+(0:1mm);
foreach j in 0.2,0.4,0.6,0.8,1
draw (0,j) node[left]$j$--+(0:2mm);

draw (0,1.1)--(0,0)--(1.5,0);
draw[red,dotted,thick] (0,1)--+(0:1.5);
path (0,0) node[below]$0$ node[left]$0$;

draw[blue] (.7,.7)--++(0:.4) node[right]Debye;
draw[magenta,dashed]
(.7,.6)--++(0:.4) node[right]Einstein;

path
(current bounding box.west) coordinate (W)
(current bounding box.south) coordinate (S);
path
(W)++(90:.1) node[left=5mm,rotate=90]$dfracC_V3NK$
(S) node[below=-4mm]$T/theta$;

endtikzpicture
enddocument





share|improve this answer























  • thanks a lot , i just needed to see how to plot these functions

    – Quintis
    Jun 19 at 15:19











  • btw how did u exactly draw this picture without using the function ?

    – Quintis
    Jun 19 at 15:24











  • I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

    – Black Mild
    Jun 19 at 16:00







  • 5





    One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

    – marmot
    Jun 19 at 16:19













5












5








5







Is this what you want?



enter image description here



documentclass[tikz,border=1mm]standalone
usepackageamsmath,amssymb
begindocument
begintikzpicture[x=4cm,y=5cm]
beginscope
clip (-.2,-.2) rectangle (1.6,1.2);
draw[dashed,magenta]
(0,0) .. controls +(0:.3) and +(181:1.75) .. (1.5,.97);
draw[blue] (0,0) .. controls +(0:.25) and +(180:1.8) ..
(1.5,.97);
endscope

foreach i in .1,.2,...,1.5
draw (i,0)--+(90:1mm);
foreach i in 0.3,0.6,0.9,1.2,1.5
draw (i,0) node[below]$i$--+(90:2mm);

foreach j in .1,.2,...,1.1
draw (0,j)--+(0:1mm);
foreach j in 0.2,0.4,0.6,0.8,1
draw (0,j) node[left]$j$--+(0:2mm);

draw (0,1.1)--(0,0)--(1.5,0);
draw[red,dotted,thick] (0,1)--+(0:1.5);
path (0,0) node[below]$0$ node[left]$0$;

draw[blue] (.7,.7)--++(0:.4) node[right]Debye;
draw[magenta,dashed]
(.7,.6)--++(0:.4) node[right]Einstein;

path
(current bounding box.west) coordinate (W)
(current bounding box.south) coordinate (S);
path
(W)++(90:.1) node[left=5mm,rotate=90]$dfracC_V3NK$
(S) node[below=-4mm]$T/theta$;

endtikzpicture
enddocument





share|improve this answer













Is this what you want?



enter image description here



documentclass[tikz,border=1mm]standalone
usepackageamsmath,amssymb
begindocument
begintikzpicture[x=4cm,y=5cm]
beginscope
clip (-.2,-.2) rectangle (1.6,1.2);
draw[dashed,magenta]
(0,0) .. controls +(0:.3) and +(181:1.75) .. (1.5,.97);
draw[blue] (0,0) .. controls +(0:.25) and +(180:1.8) ..
(1.5,.97);
endscope

foreach i in .1,.2,...,1.5
draw (i,0)--+(90:1mm);
foreach i in 0.3,0.6,0.9,1.2,1.5
draw (i,0) node[below]$i$--+(90:2mm);

foreach j in .1,.2,...,1.1
draw (0,j)--+(0:1mm);
foreach j in 0.2,0.4,0.6,0.8,1
draw (0,j) node[left]$j$--+(0:2mm);

draw (0,1.1)--(0,0)--(1.5,0);
draw[red,dotted,thick] (0,1)--+(0:1.5);
path (0,0) node[below]$0$ node[left]$0$;

draw[blue] (.7,.7)--++(0:.4) node[right]Debye;
draw[magenta,dashed]
(.7,.6)--++(0:.4) node[right]Einstein;

path
(current bounding box.west) coordinate (W)
(current bounding box.south) coordinate (S);
path
(W)++(90:.1) node[left=5mm,rotate=90]$dfracC_V3NK$
(S) node[below=-4mm]$T/theta$;

endtikzpicture
enddocument






share|improve this answer












share|improve this answer



share|improve this answer










answered Jun 19 at 10:53









Black MildBlack Mild

9337 silver badges12 bronze badges




9337 silver badges12 bronze badges












  • thanks a lot , i just needed to see how to plot these functions

    – Quintis
    Jun 19 at 15:19











  • btw how did u exactly draw this picture without using the function ?

    – Quintis
    Jun 19 at 15:24











  • I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

    – Black Mild
    Jun 19 at 16:00







  • 5





    One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

    – marmot
    Jun 19 at 16:19

















  • thanks a lot , i just needed to see how to plot these functions

    – Quintis
    Jun 19 at 15:19











  • btw how did u exactly draw this picture without using the function ?

    – Quintis
    Jun 19 at 15:24











  • I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

    – Black Mild
    Jun 19 at 16:00







  • 5





    One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

    – marmot
    Jun 19 at 16:19
















thanks a lot , i just needed to see how to plot these functions

– Quintis
Jun 19 at 15:19





thanks a lot , i just needed to see how to plot these functions

– Quintis
Jun 19 at 15:19













btw how did u exactly draw this picture without using the function ?

– Quintis
Jun 19 at 15:24





btw how did u exactly draw this picture without using the function ?

– Quintis
Jun 19 at 15:24













I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

– Black Mild
Jun 19 at 16:00






I simply looked at you figure and use 'draw controls', controlling curve until getting similar to your figure

– Black Mild
Jun 19 at 16:00





5




5





One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

– marmot
Jun 19 at 16:19





One should mention that this function is known, see e.g. en.wikipedia.org/wiki/Debye_model. In the case when the function is known I personally prefer to plot it and not to reconstruct it with curves, which is fine for unknown functions.

– marmot
Jun 19 at 16:19













11














You could declare a function and plot it. The relevant function is well known, see e.g. this Wikipedia article.



documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[
declare function=
cV(T,TD,a,b) =
(a/(T/TD))^2 * exp(b/(T/TD)) / (exp(b/(T/TD))-1)^2;
,
]
beginaxis[
xlabel=$T/T_mathrmD$,
ylabel=$c_V/(3Nk_mathrmB)$,
legend style=at=(0.9,0.6),
domain=0.001:1.5,
samples=101,
smooth,
]
addplot [black] cV(x,1,1,1);
addplot [dashed] cV(x,(pi/6)^(-1/3),1,1);
addplot [densely dotted,red,samples=2] 1;

legend
Debye,
Einstein,

endaxis
endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Oh i see so declaring function would solve everything huh ? , i appreciate a lot

    – Quintis
    Jun 19 at 5:22






  • 1





    @Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

    – marmot
    Jun 19 at 5:25











  • Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

    – manooooh
    Jun 19 at 16:36







  • 1





    @manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

    – marmot
    Jun 19 at 16:41















11














You could declare a function and plot it. The relevant function is well known, see e.g. this Wikipedia article.



documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[
declare function=
cV(T,TD,a,b) =
(a/(T/TD))^2 * exp(b/(T/TD)) / (exp(b/(T/TD))-1)^2;
,
]
beginaxis[
xlabel=$T/T_mathrmD$,
ylabel=$c_V/(3Nk_mathrmB)$,
legend style=at=(0.9,0.6),
domain=0.001:1.5,
samples=101,
smooth,
]
addplot [black] cV(x,1,1,1);
addplot [dashed] cV(x,(pi/6)^(-1/3),1,1);
addplot [densely dotted,red,samples=2] 1;

legend
Debye,
Einstein,

endaxis
endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Oh i see so declaring function would solve everything huh ? , i appreciate a lot

    – Quintis
    Jun 19 at 5:22






  • 1





    @Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

    – marmot
    Jun 19 at 5:25











  • Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

    – manooooh
    Jun 19 at 16:36







  • 1





    @manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

    – marmot
    Jun 19 at 16:41













11












11








11







You could declare a function and plot it. The relevant function is well known, see e.g. this Wikipedia article.



documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[
declare function=
cV(T,TD,a,b) =
(a/(T/TD))^2 * exp(b/(T/TD)) / (exp(b/(T/TD))-1)^2;
,
]
beginaxis[
xlabel=$T/T_mathrmD$,
ylabel=$c_V/(3Nk_mathrmB)$,
legend style=at=(0.9,0.6),
domain=0.001:1.5,
samples=101,
smooth,
]
addplot [black] cV(x,1,1,1);
addplot [dashed] cV(x,(pi/6)^(-1/3),1,1);
addplot [densely dotted,red,samples=2] 1;

legend
Debye,
Einstein,

endaxis
endtikzpicture
enddocument


enter image description here






share|improve this answer















You could declare a function and plot it. The relevant function is well known, see e.g. this Wikipedia article.



documentclass[tikz,border=3.14mm]standalone
usepackagepgfplots
pgfplotssetcompat=1.16
begindocument
begintikzpicture[
declare function=
cV(T,TD,a,b) =
(a/(T/TD))^2 * exp(b/(T/TD)) / (exp(b/(T/TD))-1)^2;
,
]
beginaxis[
xlabel=$T/T_mathrmD$,
ylabel=$c_V/(3Nk_mathrmB)$,
legend style=at=(0.9,0.6),
domain=0.001:1.5,
samples=101,
smooth,
]
addplot [black] cV(x,1,1,1);
addplot [dashed] cV(x,(pi/6)^(-1/3),1,1);
addplot [densely dotted,red,samples=2] 1;

legend
Debye,
Einstein,

endaxis
endtikzpicture
enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Jun 19 at 16:24

























answered Jun 19 at 5:19









marmotmarmot

139k6 gold badges184 silver badges336 bronze badges




139k6 gold badges184 silver badges336 bronze badges







  • 1





    Oh i see so declaring function would solve everything huh ? , i appreciate a lot

    – Quintis
    Jun 19 at 5:22






  • 1





    @Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

    – marmot
    Jun 19 at 5:25











  • Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

    – manooooh
    Jun 19 at 16:36







  • 1





    @manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

    – marmot
    Jun 19 at 16:41












  • 1





    Oh i see so declaring function would solve everything huh ? , i appreciate a lot

    – Quintis
    Jun 19 at 5:22






  • 1





    @Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

    – marmot
    Jun 19 at 5:25











  • Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

    – manooooh
    Jun 19 at 16:36







  • 1





    @manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

    – marmot
    Jun 19 at 16:41







1




1





Oh i see so declaring function would solve everything huh ? , i appreciate a lot

– Quintis
Jun 19 at 5:22





Oh i see so declaring function would solve everything huh ? , i appreciate a lot

– Quintis
Jun 19 at 5:22




1




1





@Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

– marmot
Jun 19 at 5:25





@Quintis You do not have to declare it. But in this case it is worthwhile because you plot the same function twice with slightly different parameters.

– marmot
Jun 19 at 5:25













Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

– manooooh
Jun 19 at 16:36






Woow, thanks marmot! Is legend a new command of the version 1.16? Because I've never heard about it (I always use addlegendentry, pros, cons?).

– manooooh
Jun 19 at 16:36





1




1





@manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

– marmot
Jun 19 at 16:41





@manooooh legend is slightly shorter. (Actually this was added by Stefan Pinnow, whom I thank for all edits except for the removal of tikz in documentclass[tikz,border=3.14mm]standalone since this does not only load tikz but also declares tikz to be a standalone environment, which is important when doing e.g. animations).

– marmot
Jun 19 at 16:41

















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