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Here is a practice exercise — Fantasy Game Inventory $-$

You are creating a fantasy video game. The data structure to model the
player’s inventory will be a dictionary where the keys are string
values describing the item in the inventory and the value is an
integer value detailing how many of that item the player has. For
example, the dictionary value 'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12 means the player has 1 rope, 6 torches,
42 gold coins, and so on.

Write a function named display_inventory() that would take any
possible “inventory” and display it like the following -

Inventory:
12 arrows
42 gold coins
1 rope
6 torches
1 dagger
Total number of items: 62

Hint - You can use a for loop to loop through all the keys in a
dictionary.

I have written the following code. Any feedback is highly appreciated.

stuff = 'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12

def display_inventory(inventory):
 total_items = 0
 print ("Inventory:")
 for item in inventory:
 print(str(inventory[item]) + ' ' + item)
 total_items += inventory[item]
 print("Total number of items: " + str(total_items))

if __name__ == '__main__':
 display_inventory(stuff)

I am suggesting to use fstrings and the dictionary items() method.

The

print(f'value key')

instead of

print(str(inventory[item]) + ' ' + item)

is more neatly:

def display_inventory(inventory):
 total_items = 0 
 print ("Inventory:")

 for key, value in inventory.items():
 print(f'value key')
 total_items += value

 print(f'Total number of items: total_items')

Also, you can just calculate the total number in the needed place by the sum() function and the dictionary values() method. Then, you are not needing the total_items variable.

def display_inventory(inventory):
 print ("Inventory:")

 for key, value in inventory.items():
 print(f'value key')

 print(f'Total number of items: sum(inventory.values())')

As mentioned in a comment by Roland Illig, I missed the interesting part of generating the correct plural forms from the singulars.

Here's a module which supports Python 3 - Inflect.

# Initialization
import inflect
p = inflect.engine()

Examples -

word = "torch"
print(f"The plural of 'word' is 'p.plural(word)'.")

>>> The plural of 'torch' is 'torches'.

word = "torches"
print(f"The singular of 'word' is 'p.singular_noun(word)'.")

>>> The singular of 'torches' is 'torch'.

My updated code, expanding on MiniMax's answer, is:

import inflect
p = inflect.engine()

stuff = 'rope': 0, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12

def display_inventory(inventory):

 print ("Inventory:")
 for key, value in inventory.items():

 if value != 1:
 key = p.plural(key)

 print(f'value key')
 print(f'Total number of items: sum(inventory.values())')

if __name__ == '__main__':
 display_inventory(stuff)

This will give the following output -

Inventory:
0 ropes
6 torches
42 gold coins
1 dagger
12 arrows
Total number of items: 61

OR

In cases like this -

stuff = 'ropes': 1, 'torches': 1, 'gold coin': 42, 'daggers': 1, 'arrow': 0

where -

'ropes': 1, 'torches': 1, 'daggers': 1

you will need to generate the correct singular forms from the plurals.

Therefore, expanding more on the previous code, I get -

import inflect
p = inflect.engine()

stuff = stuff = 'ropes': 1, 'torches': 1, 'gold coin': 42, 'daggers': 1, 'arrow': 0

def display_inventory(inventory):
 print ("Inventory:")
 for key, value in inventory.items():

 if value != 1:
 key = p.plural(key)
 else:
 key = p.singular_noun(key)

 print(f'value key')
 print(f'Total number of items: sum(inventory.values())')

if __name__ == '__main__':
 display_inventory(stuff)

This will give the following output:

Inventory:
1 rope
1 torch
42 gold coins
1 dagger
0 arrows
Total number of items: 45