How can I obtain a complete list of the kinds of atomic expressions in the Wolfram Language using only the language itself?List of atomic expressionsHow can I ask the Wolfram Language to tell me if a hypothetical expression with a particular head would be atomic or not?Comparing Mathematica expressions like diffList of atomic expressionsList of Coefficients of Expression with symbolic TermsHow to get a list of all expressions in a notebook matching a certain pattern?Custom atomic expressions - modern tutorialGroupings over non-atomic elementsGrouping expressions by associative equivalence for a single operationApplying functions to leaves of nested list structure, when these leaves are more complex expression treesWhat's the difference between 56 and Integer[56]?How can I ask the Wolfram Language to tell me if a hypothetical expression with a particular head would be atomic or not?
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How can I obtain a complete list of the kinds of atomic expressions in the Wolfram Language using only the language itself?
List of atomic expressionsHow can I ask the Wolfram Language to tell me if a hypothetical expression with a particular head would be atomic or not?Comparing Mathematica expressions like diffList of atomic expressionsList of Coefficients of Expression with symbolic TermsHow to get a list of all expressions in a notebook matching a certain pattern?Custom atomic expressions - modern tutorialGroupings over non-atomic elementsGrouping expressions by associative equivalence for a single operationApplying functions to leaves of nested list structure, when these leaves are more complex expression treesWhat's the difference between 56 and Integer[56]?How can I ask the Wolfram Language to tell me if a hypothetical expression with a particular head would be atomic or not?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I mean, Wolfram is a language--it's words are infinitely combinable. According to answers to my last question, the only way I can find out if an expression is atomic is actually use the expression.
But I can hardly test an infinity of expressions to find all the ones that are atoms and all the ones that are not. And I'm not interested in complete list of all expressions that are atomic. I just want a list of the kinds of atoms. Like, I know integers are atomic, and strings too. But what else?
expression-manipulation symbols expression-form
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
$endgroup$
add a comment |
$begingroup$
I mean, Wolfram is a language--it's words are infinitely combinable. According to answers to my last question, the only way I can find out if an expression is atomic is actually use the expression.
But I can hardly test an infinity of expressions to find all the ones that are atoms and all the ones that are not. And I'm not interested in complete list of all expressions that are atomic. I just want a list of the kinds of atoms. Like, I know integers are atomic, and strings too. But what else?
expression-manipulation symbols expression-form
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
$endgroup$
$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24
add a comment |
$begingroup$
I mean, Wolfram is a language--it's words are infinitely combinable. According to answers to my last question, the only way I can find out if an expression is atomic is actually use the expression.
But I can hardly test an infinity of expressions to find all the ones that are atoms and all the ones that are not. And I'm not interested in complete list of all expressions that are atomic. I just want a list of the kinds of atoms. Like, I know integers are atomic, and strings too. But what else?
expression-manipulation symbols expression-form
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
$endgroup$
I mean, Wolfram is a language--it's words are infinitely combinable. According to answers to my last question, the only way I can find out if an expression is atomic is actually use the expression.
But I can hardly test an infinity of expressions to find all the ones that are atoms and all the ones that are not. And I'm not interested in complete list of all expressions that are atomic. I just want a list of the kinds of atoms. Like, I know integers are atomic, and strings too. But what else?
expression-manipulation symbols expression-form
expression-manipulation symbols expression-form
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
asked Jul 17 at 20:06
MadEmperorYuriMadEmperorYuri
1478 bronze badges
1478 bronze badges
$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24
add a comment |
$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24
$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24
$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can use EntityValue to find out what symbols can be atomic:
EntityValue[EntityClass["WolframLanguageSymbol", "Atomic"], "CanonicalName"]
"AggregationLayer", "Association", "Audio", "BasicRecurrentLayer",
"BatchNormalizationLayer", "BooleanFunction", "BoundaryMeshRegion",
"ByteArray", "CatenateLayer", "ColorProfileData", "Complex",
"ConstantArrayLayer", "ConstantPlusLayer", "ConstantTimesLayer",
"ContrastiveLossLayer", "ConvolutionLayer", "CrossEntropyLossLayer",
"Dataset", "DeconvolutionLayer", "Dispatch", "DotLayer", "DropoutLayer",
"ElementwiseLayer", "EmbeddingLayer", "FlattenLayer", "GatedRecurrentLayer",
"Graph", "Image", "Image3D", "ImageAugmentationLayer", "Integer",
"LinearLayer", "LocalResponseNormalizationLayer", "LongShortTermMemoryLayer",
"MeanAbsoluteLossLayer", "MeanSquaredLossLayer", "MeshRegion", "NetChain",
"NetDecoder", "NetEncoder", "NetEvaluationMode", "NetExtract",
"NetFoldOperator", "NetGraph", "NetInitialize", "NetMapOperator", "NetModel",
"NetNestOperator", "NetPairEmbeddingOperator", "NetPort", "NetPortGradient",
"NetReplacePart", "PaddingLayer", "PartLayer", "PoolingLayer", "Rational",
"RawData", "Real", "ReplicateLayer", "ReshapeLayer", "ResizeLayer",
"SequenceLastLayer", "SequenceMostLayer", "SequenceRestLayer",
"SequenceReverseLayer", "SoftmaxLayer", "SparseArray",
"SpatialTransformationLayer", "String", "StructuredArray", "SummationLayer",
"ThreadingLayer", "TotalLayer", "TransposeLayer", "UnitVectorLayer"
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
$endgroup$
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use EntityValue to find out what symbols can be atomic:
EntityValue[EntityClass["WolframLanguageSymbol", "Atomic"], "CanonicalName"]
"AggregationLayer", "Association", "Audio", "BasicRecurrentLayer",
"BatchNormalizationLayer", "BooleanFunction", "BoundaryMeshRegion",
"ByteArray", "CatenateLayer", "ColorProfileData", "Complex",
"ConstantArrayLayer", "ConstantPlusLayer", "ConstantTimesLayer",
"ContrastiveLossLayer", "ConvolutionLayer", "CrossEntropyLossLayer",
"Dataset", "DeconvolutionLayer", "Dispatch", "DotLayer", "DropoutLayer",
"ElementwiseLayer", "EmbeddingLayer", "FlattenLayer", "GatedRecurrentLayer",
"Graph", "Image", "Image3D", "ImageAugmentationLayer", "Integer",
"LinearLayer", "LocalResponseNormalizationLayer", "LongShortTermMemoryLayer",
"MeanAbsoluteLossLayer", "MeanSquaredLossLayer", "MeshRegion", "NetChain",
"NetDecoder", "NetEncoder", "NetEvaluationMode", "NetExtract",
"NetFoldOperator", "NetGraph", "NetInitialize", "NetMapOperator", "NetModel",
"NetNestOperator", "NetPairEmbeddingOperator", "NetPort", "NetPortGradient",
"NetReplacePart", "PaddingLayer", "PartLayer", "PoolingLayer", "Rational",
"RawData", "Real", "ReplicateLayer", "ReshapeLayer", "ResizeLayer",
"SequenceLastLayer", "SequenceMostLayer", "SequenceRestLayer",
"SequenceReverseLayer", "SoftmaxLayer", "SparseArray",
"SpatialTransformationLayer", "String", "StructuredArray", "SummationLayer",
"ThreadingLayer", "TotalLayer", "TransposeLayer", "UnitVectorLayer"
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
$endgroup$
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
add a comment |
$begingroup$
You can use EntityValue to find out what symbols can be atomic:
EntityValue[EntityClass["WolframLanguageSymbol", "Atomic"], "CanonicalName"]
"AggregationLayer", "Association", "Audio", "BasicRecurrentLayer",
"BatchNormalizationLayer", "BooleanFunction", "BoundaryMeshRegion",
"ByteArray", "CatenateLayer", "ColorProfileData", "Complex",
"ConstantArrayLayer", "ConstantPlusLayer", "ConstantTimesLayer",
"ContrastiveLossLayer", "ConvolutionLayer", "CrossEntropyLossLayer",
"Dataset", "DeconvolutionLayer", "Dispatch", "DotLayer", "DropoutLayer",
"ElementwiseLayer", "EmbeddingLayer", "FlattenLayer", "GatedRecurrentLayer",
"Graph", "Image", "Image3D", "ImageAugmentationLayer", "Integer",
"LinearLayer", "LocalResponseNormalizationLayer", "LongShortTermMemoryLayer",
"MeanAbsoluteLossLayer", "MeanSquaredLossLayer", "MeshRegion", "NetChain",
"NetDecoder", "NetEncoder", "NetEvaluationMode", "NetExtract",
"NetFoldOperator", "NetGraph", "NetInitialize", "NetMapOperator", "NetModel",
"NetNestOperator", "NetPairEmbeddingOperator", "NetPort", "NetPortGradient",
"NetReplacePart", "PaddingLayer", "PartLayer", "PoolingLayer", "Rational",
"RawData", "Real", "ReplicateLayer", "ReshapeLayer", "ResizeLayer",
"SequenceLastLayer", "SequenceMostLayer", "SequenceRestLayer",
"SequenceReverseLayer", "SoftmaxLayer", "SparseArray",
"SpatialTransformationLayer", "String", "StructuredArray", "SummationLayer",
"ThreadingLayer", "TotalLayer", "TransposeLayer", "UnitVectorLayer"
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
$endgroup$
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
add a comment |
$begingroup$
You can use EntityValue to find out what symbols can be atomic:
EntityValue[EntityClass["WolframLanguageSymbol", "Atomic"], "CanonicalName"]
"AggregationLayer", "Association", "Audio", "BasicRecurrentLayer",
"BatchNormalizationLayer", "BooleanFunction", "BoundaryMeshRegion",
"ByteArray", "CatenateLayer", "ColorProfileData", "Complex",
"ConstantArrayLayer", "ConstantPlusLayer", "ConstantTimesLayer",
"ContrastiveLossLayer", "ConvolutionLayer", "CrossEntropyLossLayer",
"Dataset", "DeconvolutionLayer", "Dispatch", "DotLayer", "DropoutLayer",
"ElementwiseLayer", "EmbeddingLayer", "FlattenLayer", "GatedRecurrentLayer",
"Graph", "Image", "Image3D", "ImageAugmentationLayer", "Integer",
"LinearLayer", "LocalResponseNormalizationLayer", "LongShortTermMemoryLayer",
"MeanAbsoluteLossLayer", "MeanSquaredLossLayer", "MeshRegion", "NetChain",
"NetDecoder", "NetEncoder", "NetEvaluationMode", "NetExtract",
"NetFoldOperator", "NetGraph", "NetInitialize", "NetMapOperator", "NetModel",
"NetNestOperator", "NetPairEmbeddingOperator", "NetPort", "NetPortGradient",
"NetReplacePart", "PaddingLayer", "PartLayer", "PoolingLayer", "Rational",
"RawData", "Real", "ReplicateLayer", "ReshapeLayer", "ResizeLayer",
"SequenceLastLayer", "SequenceMostLayer", "SequenceRestLayer",
"SequenceReverseLayer", "SoftmaxLayer", "SparseArray",
"SpatialTransformationLayer", "String", "StructuredArray", "SummationLayer",
"ThreadingLayer", "TotalLayer", "TransposeLayer", "UnitVectorLayer"
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
$endgroup$
You can use EntityValue to find out what symbols can be atomic:
EntityValue[EntityClass["WolframLanguageSymbol", "Atomic"], "CanonicalName"]
"AggregationLayer", "Association", "Audio", "BasicRecurrentLayer",
"BatchNormalizationLayer", "BooleanFunction", "BoundaryMeshRegion",
"ByteArray", "CatenateLayer", "ColorProfileData", "Complex",
"ConstantArrayLayer", "ConstantPlusLayer", "ConstantTimesLayer",
"ContrastiveLossLayer", "ConvolutionLayer", "CrossEntropyLossLayer",
"Dataset", "DeconvolutionLayer", "Dispatch", "DotLayer", "DropoutLayer",
"ElementwiseLayer", "EmbeddingLayer", "FlattenLayer", "GatedRecurrentLayer",
"Graph", "Image", "Image3D", "ImageAugmentationLayer", "Integer",
"LinearLayer", "LocalResponseNormalizationLayer", "LongShortTermMemoryLayer",
"MeanAbsoluteLossLayer", "MeanSquaredLossLayer", "MeshRegion", "NetChain",
"NetDecoder", "NetEncoder", "NetEvaluationMode", "NetExtract",
"NetFoldOperator", "NetGraph", "NetInitialize", "NetMapOperator", "NetModel",
"NetNestOperator", "NetPairEmbeddingOperator", "NetPort", "NetPortGradient",
"NetReplacePart", "PaddingLayer", "PartLayer", "PoolingLayer", "Rational",
"RawData", "Real", "ReplicateLayer", "ReshapeLayer", "ResizeLayer",
"SequenceLastLayer", "SequenceMostLayer", "SequenceRestLayer",
"SequenceReverseLayer", "SoftmaxLayer", "SparseArray",
"SpatialTransformationLayer", "String", "StructuredArray", "SummationLayer",
"ThreadingLayer", "TotalLayer", "TransposeLayer", "UnitVectorLayer"
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
answered Jul 17 at 20:11
Carl WollCarl Woll
88.3k3 gold badges117 silver badges227 bronze badges
88.3k3 gold badges117 silver badges227 bronze badges
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
add a comment |
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
$begingroup$
Wow. That's a lot of atoms. Thank you, this is what I needed!
$endgroup$
– MadEmperorYuri
Jul 17 at 20:23
add a comment |
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$begingroup$
Would be a dupe of an old question: mathematica.stackexchange.com/q/46850/61597 if the answer wasn't a bit out of date.
$endgroup$
– lirtosiast
Jul 17 at 20:24