What is the temperature of the black night sky, outside the atmosphere?What is the temperature of the clear night sky from the surface of Earth?Temperature of a black-body in LEO on the dark side of the EarthIf quantum gas goes below 0K, is calling 0K absolute zero irrelevant?What do the line segments on the BICEP2 B-mode polarization map mean?Why is the sky dark at night?How do we filter out radiation from galaxies from the cosmic background radiation?At any given point in the universe, are there a huge number of photons crossing paths?By how much does starlight heat the Earth?Would time dilation affect temperature?How much does temperature affect the time of sunrise?How did Edwin Hubble estimate the velocity of distant stars?
To kill a cuckoo
How to pass hash as password to ssh server
Are there terms in German for different skull shapes?
A factorization game
Start job from another SQL server instance
Would a small hole in a Faraday cage drastically reduce its effectiveness at blocking interference?
Will 700 more planes a day fly because of the Heathrow expansion?
Would you use "llamarse" for an animal's name?
How do I, as a DM, handle a party that decides to set up an ambush in a dungeon?
How to deal with employer who keeps me at work after working hours
What is a common way to tell if an academic is "above average," or outstanding in their field? Is their h-index (Hirsh index) one of them?
Is disk brake effectiveness mitigated by tyres losing traction under strong braking?
If all diagonals are drawn in a regular polygon from a vertex, the angles formed in that vertex are equal
My first c++ game (snake console game)
Why is "breaking the mould" positively connoted?
Find magical solution to magical equation
Has the United States ever had a non-Christian President?
Python 3 - simple temperature program
What to use instead of cling film to wrap pastry
What do I do if my advisor made a mistake?
Out of scope work duties and resignation
Mug and wireframe entirely disappeared
Trigonometry substitution issue with sign
Has a commercial or military jet bi-plane ever been manufactured?
What is the temperature of the black night sky, outside the atmosphere?
What is the temperature of the clear night sky from the surface of Earth?Temperature of a black-body in LEO on the dark side of the EarthIf quantum gas goes below 0K, is calling 0K absolute zero irrelevant?What do the line segments on the BICEP2 B-mode polarization map mean?Why is the sky dark at night?How do we filter out radiation from galaxies from the cosmic background radiation?At any given point in the universe, are there a huge number of photons crossing paths?By how much does starlight heat the Earth?Would time dilation affect temperature?How much does temperature affect the time of sunrise?How did Edwin Hubble estimate the velocity of distant stars?
$begingroup$
The sky at night is rather black. If it were completely black, it would correspond to a black body at absolute zero. But the sky is not completely black. Is there a way to assign a temperature value to the actual black night sky?
The question is not about the temperature of the air of the atmosphere, nor that of the stars in the sky. The question is about the the temperature that corresponds to the blackness seen by, say, the Hubble telescope; the question is about the pure blackness of the night sky, between the stars, outside the atmosphere of the Earth.
Nela
cosmology temperature cosmic-microwave-background
New contributor
$endgroup$
add a comment |
$begingroup$
The sky at night is rather black. If it were completely black, it would correspond to a black body at absolute zero. But the sky is not completely black. Is there a way to assign a temperature value to the actual black night sky?
The question is not about the temperature of the air of the atmosphere, nor that of the stars in the sky. The question is about the the temperature that corresponds to the blackness seen by, say, the Hubble telescope; the question is about the pure blackness of the night sky, between the stars, outside the atmosphere of the Earth.
Nela
cosmology temperature cosmic-microwave-background
New contributor
$endgroup$
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago
add a comment |
$begingroup$
The sky at night is rather black. If it were completely black, it would correspond to a black body at absolute zero. But the sky is not completely black. Is there a way to assign a temperature value to the actual black night sky?
The question is not about the temperature of the air of the atmosphere, nor that of the stars in the sky. The question is about the the temperature that corresponds to the blackness seen by, say, the Hubble telescope; the question is about the pure blackness of the night sky, between the stars, outside the atmosphere of the Earth.
Nela
cosmology temperature cosmic-microwave-background
New contributor
$endgroup$
The sky at night is rather black. If it were completely black, it would correspond to a black body at absolute zero. But the sky is not completely black. Is there a way to assign a temperature value to the actual black night sky?
The question is not about the temperature of the air of the atmosphere, nor that of the stars in the sky. The question is about the the temperature that corresponds to the blackness seen by, say, the Hubble telescope; the question is about the pure blackness of the night sky, between the stars, outside the atmosphere of the Earth.
Nela
cosmology temperature cosmic-microwave-background
cosmology temperature cosmic-microwave-background
New contributor
New contributor
edited 2 days ago
Nela
New contributor
asked Apr 30 at 20:03
NelaNela
184
184
New contributor
New contributor
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago
add a comment |
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
It depends on what you mean by “sky”. The Earth’s atmosphere has a large range of temperatures at various altitudes, generally getting colder and colder from the surface temperature as you go up.
If what you are actually asking is the temperature of deep space, then it is 2.725 K, the temperature of the cosmic microwave background (CMB), a remnant of the Big Bang that permeates the entire universe. Every cubic centimeter of space has about 400 microwave-frequency photons with the spectrum of a 2.725 K blackbody. This radiation from about 380,000 years after the Big Bang is now very cold (just three degrees above abdolute zero) because the universe has expanded tremendously since then.
The CMB was predicted in 1948 and detected in 1964 by scientists who didn’t know about the prediction and weren’t looking for it.
$endgroup$
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "151"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Nela is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f477031%2fwhat-is-the-temperature-of-the-black-night-sky-outside-the-atmosphere%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It depends on what you mean by “sky”. The Earth’s atmosphere has a large range of temperatures at various altitudes, generally getting colder and colder from the surface temperature as you go up.
If what you are actually asking is the temperature of deep space, then it is 2.725 K, the temperature of the cosmic microwave background (CMB), a remnant of the Big Bang that permeates the entire universe. Every cubic centimeter of space has about 400 microwave-frequency photons with the spectrum of a 2.725 K blackbody. This radiation from about 380,000 years after the Big Bang is now very cold (just three degrees above abdolute zero) because the universe has expanded tremendously since then.
The CMB was predicted in 1948 and detected in 1964 by scientists who didn’t know about the prediction and weren’t looking for it.
$endgroup$
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
add a comment |
$begingroup$
It depends on what you mean by “sky”. The Earth’s atmosphere has a large range of temperatures at various altitudes, generally getting colder and colder from the surface temperature as you go up.
If what you are actually asking is the temperature of deep space, then it is 2.725 K, the temperature of the cosmic microwave background (CMB), a remnant of the Big Bang that permeates the entire universe. Every cubic centimeter of space has about 400 microwave-frequency photons with the spectrum of a 2.725 K blackbody. This radiation from about 380,000 years after the Big Bang is now very cold (just three degrees above abdolute zero) because the universe has expanded tremendously since then.
The CMB was predicted in 1948 and detected in 1964 by scientists who didn’t know about the prediction and weren’t looking for it.
$endgroup$
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
add a comment |
$begingroup$
It depends on what you mean by “sky”. The Earth’s atmosphere has a large range of temperatures at various altitudes, generally getting colder and colder from the surface temperature as you go up.
If what you are actually asking is the temperature of deep space, then it is 2.725 K, the temperature of the cosmic microwave background (CMB), a remnant of the Big Bang that permeates the entire universe. Every cubic centimeter of space has about 400 microwave-frequency photons with the spectrum of a 2.725 K blackbody. This radiation from about 380,000 years after the Big Bang is now very cold (just three degrees above abdolute zero) because the universe has expanded tremendously since then.
The CMB was predicted in 1948 and detected in 1964 by scientists who didn’t know about the prediction and weren’t looking for it.
$endgroup$
It depends on what you mean by “sky”. The Earth’s atmosphere has a large range of temperatures at various altitudes, generally getting colder and colder from the surface temperature as you go up.
If what you are actually asking is the temperature of deep space, then it is 2.725 K, the temperature of the cosmic microwave background (CMB), a remnant of the Big Bang that permeates the entire universe. Every cubic centimeter of space has about 400 microwave-frequency photons with the spectrum of a 2.725 K blackbody. This radiation from about 380,000 years after the Big Bang is now very cold (just three degrees above abdolute zero) because the universe has expanded tremendously since then.
The CMB was predicted in 1948 and detected in 1964 by scientists who didn’t know about the prediction and weren’t looking for it.
edited Apr 30 at 20:24
answered Apr 30 at 20:11
G. SmithG. Smith
11.6k11837
11.6k11837
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
add a comment |
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– ACuriousMind♦
2 days ago
add a comment |
Nela is a new contributor. Be nice, and check out our Code of Conduct.
Nela is a new contributor. Be nice, and check out our Code of Conduct.
Nela is a new contributor. Be nice, and check out our Code of Conduct.
Nela is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Physics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f477031%2fwhat-is-the-temperature-of-the-black-night-sky-outside-the-atmosphere%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Sort of related: physics.stackexchange.com/questions/153839/…
$endgroup$
– PM 2Ring
2 days ago
$begingroup$
The question title also needs editing to make it clear that this is not a duplicate of physics.stackexchange.com/questions/153839/…
$endgroup$
– Rob Jeffries
2 days ago
$begingroup$
Done as you wanted.
$endgroup$
– Nela
2 days ago