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Variance vs standard deviation [closed]

Find standard deviation given standard deviationWhat makes standard deviation a good measure of dispersion from the mean?Standard deviation without squareRecalculate Standard DeviationConfirmation of the Variance and Standard Deviation resultsample standard deviation given population standard deviationCalculating Combined Standard DeviationHow is standard deviation different from average deviation?What is standard deviation?Does measuring the variance above the mean only give you a better indication of ceiling/potential?

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4

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If I wanted to measure a fantasy MLB player’s potential to outscore his average on a given night would variance or standard deviation be a better indicator?

statistics variance standard-deviation

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asked Jul 21 at 2:13

tintin

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closed as off-topic by YuiTo Cheng, verret, Daniele Tampieri, Lee David Chung Lin, Paul Frost Jul 25 at 7:32

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YuiTo Cheng, verret, Daniele Tampieri, Lee David Chung Lin, Paul Frost

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  variance is square of standard deviation, so they are essentially same measure
  $endgroup$
  – Barry Chau
  Jul 21 at 2:16
  

  
  
  
  

add a comment | 

4

$begingroup$

If I wanted to measure a fantasy MLB player’s potential to outscore his average on a given night would variance or standard deviation be a better indicator?

statistics variance standard-deviation

share|cite|improve this question

asked Jul 21 at 2:13

tintin

12888 bronze badges

$endgroup$

closed as off-topic by YuiTo Cheng, verret, Daniele Tampieri, Lee David Chung Lin, Paul Frost Jul 25 at 7:32

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – YuiTo Cheng, verret, Daniele Tampieri, Lee David Chung Lin, Paul Frost

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  variance is square of standard deviation, so they are essentially same measure
  $endgroup$
  – Barry Chau
  Jul 21 at 2:16
  

  
  
  
  

add a comment | 

$begingroup$

If I wanted to measure a fantasy MLB player’s potential to outscore his average on a given night would variance or standard deviation be a better indicator?

statistics variance standard-deviation

share|cite|improve this question

asked Jul 21 at 2:13

tintin

12888 bronze badges

$endgroup$

share|cite|improve this question

asked Jul 21 at 2:13

tintin

12888 bronze badges

share|cite|improve this question

asked Jul 21 at 2:13

tintin

12888 bronze badges

asked Jul 21 at 2:13

tintin

12888 bronze badges

asked Jul 21 at 2:13

tintin

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2 Answers
2

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oldest

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5

$begingroup$

The standard deviation is better for this computation.

You would be using the number of standard deviations above the average to compute the probability.

share|cite|improve this answer

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  What does this answer mean and how does it have 6 upvotes!?!?! Standard deviation and variance tell the exact same thing. What "number of standard deviations above the average" do you refer to; this question is asking about the probability of getting more than 0 <anything> above the average? What on earth is happening?
  $endgroup$
  – JiK
  Jul 21 at 18:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK computations in this sense, involving the behavior of a single normally distributed random variable use the standard deviation
  $endgroup$
  – Saketh Malyala
  Jul 22 at 2:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Did you read the question?
  $endgroup$
  – JiK
  Jul 22 at 8:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK "potential to outscore his average"
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  that's a classic application of standard deviation, as far as i know
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  

add a comment | 

4

$begingroup$

Let's check the units:

• Standard deviation: $textrmscore$
  


• Variance: $textrmscore^2$
  

It seems more appealing to predict scores in units of $textrmscore$, don't you think? :)

share|cite|improve this answer

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

$endgroup$

add a comment | 

5

$begingroup$

The standard deviation is better for this computation.

You would be using the number of standard deviations above the average to compute the probability.

share|cite|improve this answer

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  What does this answer mean and how does it have 6 upvotes!?!?! Standard deviation and variance tell the exact same thing. What "number of standard deviations above the average" do you refer to; this question is asking about the probability of getting more than 0 <anything> above the average? What on earth is happening?
  $endgroup$
  – JiK
  Jul 21 at 18:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK computations in this sense, involving the behavior of a single normally distributed random variable use the standard deviation
  $endgroup$
  – Saketh Malyala
  Jul 22 at 2:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Did you read the question?
  $endgroup$
  – JiK
  Jul 22 at 8:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK "potential to outscore his average"
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  that's a classic application of standard deviation, as far as i know
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  

add a comment | 

5

$begingroup$

The standard deviation is better for this computation.

You would be using the number of standard deviations above the average to compute the probability.

share|cite|improve this answer

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  What does this answer mean and how does it have 6 upvotes!?!?! Standard deviation and variance tell the exact same thing. What "number of standard deviations above the average" do you refer to; this question is asking about the probability of getting more than 0 <anything> above the average? What on earth is happening?
  $endgroup$
  – JiK
  Jul 21 at 18:19
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK computations in this sense, involving the behavior of a single normally distributed random variable use the standard deviation
  $endgroup$
  – Saketh Malyala
  Jul 22 at 2:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Did you read the question?
  $endgroup$
  – JiK
  Jul 22 at 8:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @JiK "potential to outscore his average"
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  that's a classic application of standard deviation, as far as i know
  $endgroup$
  – Saketh Malyala
  Jul 22 at 8:31
  

  
  
  
  

add a comment | 

$begingroup$

The standard deviation is better for this computation.

You would be using the number of standard deviations above the average to compute the probability.

share|cite|improve this answer

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

$endgroup$

share|cite|improve this answer

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

answered Jul 21 at 2:16

Saketh MalyalaSaketh Malyala

10.6k1717 silver badges3838 bronze badges

4

$begingroup$

Let's check the units:

• Standard deviation: $textrmscore$
  


• Variance: $textrmscore^2$
  

It seems more appealing to predict scores in units of $textrmscore$, don't you think? :)

share|cite|improve this answer

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

$endgroup$

add a comment | 

4

$begingroup$

Let's check the units:

• Standard deviation: $textrmscore$
  


• Variance: $textrmscore^2$
  

It seems more appealing to predict scores in units of $textrmscore$, don't you think? :)

share|cite|improve this answer

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

$endgroup$

add a comment | 

$begingroup$

Let's check the units:

• Standard deviation: $textrmscore$
  


• Variance: $textrmscore^2$
  

It seems more appealing to predict scores in units of $textrmscore$, don't you think? :)

share|cite|improve this answer

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

$endgroup$

share|cite|improve this answer

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges

answered Jul 21 at 10:55

Mateen UlhaqMateen Ulhaq

81522 gold badges1313 silver badges2929 bronze badges