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Drawing a german abacus as in the books of Adam Ries


Drawing complex integrationDrawing vertical hierarchical n-ary tree in tikztikz drawing a partitioned rectangleSpiral around cylinderDrawing cyclic quiverDraw diagram in TikZHow to draw the following pictures?How to draw the deformation of contour of integration in the complex plane?Drawing a model diagram in LaTeX using TikZHow to draw the following pictures in LaTex?













11















I am teaching a course in history of mathematics and would like to draw something like the following:



enter image description here



The bullet points should be possible to draw on the lines and in between. Can anyone help me? Thank you very much!










share|improve this question







New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 5





    Welcome to TeX.SE! Can you please add the code you have tried so far?

    – Kurt
    Apr 25 at 7:47






  • 2





    You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

    – sztruks
    Apr 25 at 7:49











  • Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

    – Andrew
    Apr 25 at 8:27











  • Just a random thought: You can tweak qcircuit

    – pushpen.paul
    Apr 25 at 17:33















11















I am teaching a course in history of mathematics and would like to draw something like the following:



enter image description here



The bullet points should be possible to draw on the lines and in between. Can anyone help me? Thank you very much!










share|improve this question







New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 5





    Welcome to TeX.SE! Can you please add the code you have tried so far?

    – Kurt
    Apr 25 at 7:47






  • 2





    You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

    – sztruks
    Apr 25 at 7:49











  • Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

    – Andrew
    Apr 25 at 8:27











  • Just a random thought: You can tweak qcircuit

    – pushpen.paul
    Apr 25 at 17:33













11












11








11


3






I am teaching a course in history of mathematics and would like to draw something like the following:



enter image description here



The bullet points should be possible to draw on the lines and in between. Can anyone help me? Thank you very much!










share|improve this question







New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am teaching a course in history of mathematics and would like to draw something like the following:



enter image description here



The bullet points should be possible to draw on the lines and in between. Can anyone help me? Thank you very much!







tikz-pgf






share|improve this question







New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Apr 25 at 7:33









rkrapfrkrapf

563




563




New contributor




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New contributor





rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






rkrapf is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 5





    Welcome to TeX.SE! Can you please add the code you have tried so far?

    – Kurt
    Apr 25 at 7:47






  • 2





    You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

    – sztruks
    Apr 25 at 7:49











  • Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

    – Andrew
    Apr 25 at 8:27











  • Just a random thought: You can tweak qcircuit

    – pushpen.paul
    Apr 25 at 17:33












  • 5





    Welcome to TeX.SE! Can you please add the code you have tried so far?

    – Kurt
    Apr 25 at 7:47






  • 2





    You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

    – sztruks
    Apr 25 at 7:49











  • Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

    – Andrew
    Apr 25 at 8:27











  • Just a random thought: You can tweak qcircuit

    – pushpen.paul
    Apr 25 at 17:33







5




5





Welcome to TeX.SE! Can you please add the code you have tried so far?

– Kurt
Apr 25 at 7:47





Welcome to TeX.SE! Can you please add the code you have tried so far?

– Kurt
Apr 25 at 7:47




2




2





You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

– sztruks
Apr 25 at 7:49





You will find a tutorial for such shapes at the beginning of TikZ manual (the one dedicated to drawing algorithm). It is very well explained. All you have to do is to turn the white circles of its example into black.

– sztruks
Apr 25 at 7:49













Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

– Andrew
Apr 25 at 8:27





Are the grid sizes fixed as in your MWE (4 horizontal lines and 2 vertical), or are they also variable?

– Andrew
Apr 25 at 8:27













Just a random thought: You can tweak qcircuit

– pushpen.paul
Apr 25 at 17:33





Just a random thought: You can tweak qcircuit

– pushpen.paul
Apr 25 at 17:33










2 Answers
2






active

oldest

votes


















24














As you intend to draw "quite a few" of these you'll need a reasonable interface, so how about using code like this



 abacus2,1,1,1,3,3,2,,4,2,1
qquad
abacus1,,,,2,1


to produce something like this:



enter image description here



The way that this works is that the abacus command accepts a comma separated list of "abacus rows", which start from the bottom of the abacus and climb upwards. Each "abacus row" is itself a comma separated list that gives the number of balls in each column of the abacus, from left to right.



Here's the full code:



documentclassarticle
usepackagetikz

tikzset
pics/abacus/.style =
code=
ifnum#1>0% have to treat 0 separately
foreach ball [evaluate=ball as x
using (ball-0.5-#1/2)*0.2] in 1,...,#1
fill[black] (x,0) circle (2.5pt);

fi

,
/tikz/abacus/.is family,% default values
/tikz/abacus,
xscale/.initial=1, % default xscale=1 (no scaling)
yscale/.initial=0.6,% default yscale=0.6
columns/.initial=2, % default of 2 vertical rules
rows/.initial=4 % default of 4 horizontal rules

% shortcut for accessing options
newcommandAbacusOption[1]pgfkeysvalueof/tikz/abacus/#1

newcommandabacus[2][]tikzsetabacus, #1%
begintikzpicture[
xscale=AbacusOptionxscale,
yscale=AbacusOptionyscale
]
foreach ypos in 1,...,AbacusOptionrows
draw(0,2*ypos-1)--++(2*AbacusOptioncolumns,0);

foreach xpos in 1,...,AbacusOptioncolumns
draw(2*xpos, 0)--++(0,2*AbacusOptionrows);

foreach row [count=ypos] in #2
foreach col [count=xpos] in row
draw (2*xpos-1,ypos) picabacus=col;


endtikzpicture%


begindocument

abacus2,1,1,1,3,3,2,,4,2,1
qquad
abacus1,,,,2,1

enddocument


The abacus command accepts an optional argument that accepts a comma separated list of key-value pairs for changing the default number of rows and columns and the x and y scaling. For example,



abacus[rows=2, columns=3, xscale=0.5, yscale=0.3]1,2,3,4,0,3,1


produces:



enter image description here






share|improve this answer
































    5














    Here I draw the first picture. You can draw the other based on this.



    documentclass[tikz]standalone
    begindocument
    begintikzpicture[x=1.5cm]
    foreach i in 1,2 draw (i,-.2) -- (i,3.2);
    foreach i in 0,1,2,3 draw (0,i) -- (3,i);
    foreach x/y in
    .5/0,
    .4/2,
    .6/2,
    .5/2.5
    fill (x,y) circle (2pt);
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer























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      2 Answers
      2






      active

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      2 Answers
      2






      active

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      active

      oldest

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      active

      oldest

      votes









      24














      As you intend to draw "quite a few" of these you'll need a reasonable interface, so how about using code like this



       abacus2,1,1,1,3,3,2,,4,2,1
      qquad
      abacus1,,,,2,1


      to produce something like this:



      enter image description here



      The way that this works is that the abacus command accepts a comma separated list of "abacus rows", which start from the bottom of the abacus and climb upwards. Each "abacus row" is itself a comma separated list that gives the number of balls in each column of the abacus, from left to right.



      Here's the full code:



      documentclassarticle
      usepackagetikz

      tikzset
      pics/abacus/.style =
      code=
      ifnum#1>0% have to treat 0 separately
      foreach ball [evaluate=ball as x
      using (ball-0.5-#1/2)*0.2] in 1,...,#1
      fill[black] (x,0) circle (2.5pt);

      fi

      ,
      /tikz/abacus/.is family,% default values
      /tikz/abacus,
      xscale/.initial=1, % default xscale=1 (no scaling)
      yscale/.initial=0.6,% default yscale=0.6
      columns/.initial=2, % default of 2 vertical rules
      rows/.initial=4 % default of 4 horizontal rules

      % shortcut for accessing options
      newcommandAbacusOption[1]pgfkeysvalueof/tikz/abacus/#1

      newcommandabacus[2][]tikzsetabacus, #1%
      begintikzpicture[
      xscale=AbacusOptionxscale,
      yscale=AbacusOptionyscale
      ]
      foreach ypos in 1,...,AbacusOptionrows
      draw(0,2*ypos-1)--++(2*AbacusOptioncolumns,0);

      foreach xpos in 1,...,AbacusOptioncolumns
      draw(2*xpos, 0)--++(0,2*AbacusOptionrows);

      foreach row [count=ypos] in #2
      foreach col [count=xpos] in row
      draw (2*xpos-1,ypos) picabacus=col;


      endtikzpicture%


      begindocument

      abacus2,1,1,1,3,3,2,,4,2,1
      qquad
      abacus1,,,,2,1

      enddocument


      The abacus command accepts an optional argument that accepts a comma separated list of key-value pairs for changing the default number of rows and columns and the x and y scaling. For example,



      abacus[rows=2, columns=3, xscale=0.5, yscale=0.3]1,2,3,4,0,3,1


      produces:



      enter image description here






      share|improve this answer





























        24














        As you intend to draw "quite a few" of these you'll need a reasonable interface, so how about using code like this



         abacus2,1,1,1,3,3,2,,4,2,1
        qquad
        abacus1,,,,2,1


        to produce something like this:



        enter image description here



        The way that this works is that the abacus command accepts a comma separated list of "abacus rows", which start from the bottom of the abacus and climb upwards. Each "abacus row" is itself a comma separated list that gives the number of balls in each column of the abacus, from left to right.



        Here's the full code:



        documentclassarticle
        usepackagetikz

        tikzset
        pics/abacus/.style =
        code=
        ifnum#1>0% have to treat 0 separately
        foreach ball [evaluate=ball as x
        using (ball-0.5-#1/2)*0.2] in 1,...,#1
        fill[black] (x,0) circle (2.5pt);

        fi

        ,
        /tikz/abacus/.is family,% default values
        /tikz/abacus,
        xscale/.initial=1, % default xscale=1 (no scaling)
        yscale/.initial=0.6,% default yscale=0.6
        columns/.initial=2, % default of 2 vertical rules
        rows/.initial=4 % default of 4 horizontal rules

        % shortcut for accessing options
        newcommandAbacusOption[1]pgfkeysvalueof/tikz/abacus/#1

        newcommandabacus[2][]tikzsetabacus, #1%
        begintikzpicture[
        xscale=AbacusOptionxscale,
        yscale=AbacusOptionyscale
        ]
        foreach ypos in 1,...,AbacusOptionrows
        draw(0,2*ypos-1)--++(2*AbacusOptioncolumns,0);

        foreach xpos in 1,...,AbacusOptioncolumns
        draw(2*xpos, 0)--++(0,2*AbacusOptionrows);

        foreach row [count=ypos] in #2
        foreach col [count=xpos] in row
        draw (2*xpos-1,ypos) picabacus=col;


        endtikzpicture%


        begindocument

        abacus2,1,1,1,3,3,2,,4,2,1
        qquad
        abacus1,,,,2,1

        enddocument


        The abacus command accepts an optional argument that accepts a comma separated list of key-value pairs for changing the default number of rows and columns and the x and y scaling. For example,



        abacus[rows=2, columns=3, xscale=0.5, yscale=0.3]1,2,3,4,0,3,1


        produces:



        enter image description here






        share|improve this answer



























          24












          24








          24







          As you intend to draw "quite a few" of these you'll need a reasonable interface, so how about using code like this



           abacus2,1,1,1,3,3,2,,4,2,1
          qquad
          abacus1,,,,2,1


          to produce something like this:



          enter image description here



          The way that this works is that the abacus command accepts a comma separated list of "abacus rows", which start from the bottom of the abacus and climb upwards. Each "abacus row" is itself a comma separated list that gives the number of balls in each column of the abacus, from left to right.



          Here's the full code:



          documentclassarticle
          usepackagetikz

          tikzset
          pics/abacus/.style =
          code=
          ifnum#1>0% have to treat 0 separately
          foreach ball [evaluate=ball as x
          using (ball-0.5-#1/2)*0.2] in 1,...,#1
          fill[black] (x,0) circle (2.5pt);

          fi

          ,
          /tikz/abacus/.is family,% default values
          /tikz/abacus,
          xscale/.initial=1, % default xscale=1 (no scaling)
          yscale/.initial=0.6,% default yscale=0.6
          columns/.initial=2, % default of 2 vertical rules
          rows/.initial=4 % default of 4 horizontal rules

          % shortcut for accessing options
          newcommandAbacusOption[1]pgfkeysvalueof/tikz/abacus/#1

          newcommandabacus[2][]tikzsetabacus, #1%
          begintikzpicture[
          xscale=AbacusOptionxscale,
          yscale=AbacusOptionyscale
          ]
          foreach ypos in 1,...,AbacusOptionrows
          draw(0,2*ypos-1)--++(2*AbacusOptioncolumns,0);

          foreach xpos in 1,...,AbacusOptioncolumns
          draw(2*xpos, 0)--++(0,2*AbacusOptionrows);

          foreach row [count=ypos] in #2
          foreach col [count=xpos] in row
          draw (2*xpos-1,ypos) picabacus=col;


          endtikzpicture%


          begindocument

          abacus2,1,1,1,3,3,2,,4,2,1
          qquad
          abacus1,,,,2,1

          enddocument


          The abacus command accepts an optional argument that accepts a comma separated list of key-value pairs for changing the default number of rows and columns and the x and y scaling. For example,



          abacus[rows=2, columns=3, xscale=0.5, yscale=0.3]1,2,3,4,0,3,1


          produces:



          enter image description here






          share|improve this answer















          As you intend to draw "quite a few" of these you'll need a reasonable interface, so how about using code like this



           abacus2,1,1,1,3,3,2,,4,2,1
          qquad
          abacus1,,,,2,1


          to produce something like this:



          enter image description here



          The way that this works is that the abacus command accepts a comma separated list of "abacus rows", which start from the bottom of the abacus and climb upwards. Each "abacus row" is itself a comma separated list that gives the number of balls in each column of the abacus, from left to right.



          Here's the full code:



          documentclassarticle
          usepackagetikz

          tikzset
          pics/abacus/.style =
          code=
          ifnum#1>0% have to treat 0 separately
          foreach ball [evaluate=ball as x
          using (ball-0.5-#1/2)*0.2] in 1,...,#1
          fill[black] (x,0) circle (2.5pt);

          fi

          ,
          /tikz/abacus/.is family,% default values
          /tikz/abacus,
          xscale/.initial=1, % default xscale=1 (no scaling)
          yscale/.initial=0.6,% default yscale=0.6
          columns/.initial=2, % default of 2 vertical rules
          rows/.initial=4 % default of 4 horizontal rules

          % shortcut for accessing options
          newcommandAbacusOption[1]pgfkeysvalueof/tikz/abacus/#1

          newcommandabacus[2][]tikzsetabacus, #1%
          begintikzpicture[
          xscale=AbacusOptionxscale,
          yscale=AbacusOptionyscale
          ]
          foreach ypos in 1,...,AbacusOptionrows
          draw(0,2*ypos-1)--++(2*AbacusOptioncolumns,0);

          foreach xpos in 1,...,AbacusOptioncolumns
          draw(2*xpos, 0)--++(0,2*AbacusOptionrows);

          foreach row [count=ypos] in #2
          foreach col [count=xpos] in row
          draw (2*xpos-1,ypos) picabacus=col;


          endtikzpicture%


          begindocument

          abacus2,1,1,1,3,3,2,,4,2,1
          qquad
          abacus1,,,,2,1

          enddocument


          The abacus command accepts an optional argument that accepts a comma separated list of key-value pairs for changing the default number of rows and columns and the x and y scaling. For example,



          abacus[rows=2, columns=3, xscale=0.5, yscale=0.3]1,2,3,4,0,3,1


          produces:



          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 26 at 0:27

























          answered Apr 25 at 10:47









          AndrewAndrew

          31.6k34483




          31.6k34483





















              5














              Here I draw the first picture. You can draw the other based on this.



              documentclass[tikz]standalone
              begindocument
              begintikzpicture[x=1.5cm]
              foreach i in 1,2 draw (i,-.2) -- (i,3.2);
              foreach i in 0,1,2,3 draw (0,i) -- (3,i);
              foreach x/y in
              .5/0,
              .4/2,
              .6/2,
              .5/2.5
              fill (x,y) circle (2pt);
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer



























                5














                Here I draw the first picture. You can draw the other based on this.



                documentclass[tikz]standalone
                begindocument
                begintikzpicture[x=1.5cm]
                foreach i in 1,2 draw (i,-.2) -- (i,3.2);
                foreach i in 0,1,2,3 draw (0,i) -- (3,i);
                foreach x/y in
                .5/0,
                .4/2,
                .6/2,
                .5/2.5
                fill (x,y) circle (2pt);
                endtikzpicture
                enddocument


                enter image description here






                share|improve this answer

























                  5












                  5








                  5







                  Here I draw the first picture. You can draw the other based on this.



                  documentclass[tikz]standalone
                  begindocument
                  begintikzpicture[x=1.5cm]
                  foreach i in 1,2 draw (i,-.2) -- (i,3.2);
                  foreach i in 0,1,2,3 draw (0,i) -- (3,i);
                  foreach x/y in
                  .5/0,
                  .4/2,
                  .6/2,
                  .5/2.5
                  fill (x,y) circle (2pt);
                  endtikzpicture
                  enddocument


                  enter image description here






                  share|improve this answer













                  Here I draw the first picture. You can draw the other based on this.



                  documentclass[tikz]standalone
                  begindocument
                  begintikzpicture[x=1.5cm]
                  foreach i in 1,2 draw (i,-.2) -- (i,3.2);
                  foreach i in 0,1,2,3 draw (0,i) -- (3,i);
                  foreach x/y in
                  .5/0,
                  .4/2,
                  .6/2,
                  .5/2.5
                  fill (x,y) circle (2pt);
                  endtikzpicture
                  enddocument


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Apr 25 at 9:45









                  JouleVJouleV

                  16.1k22667




                  16.1k22667




















                      rkrapf is a new contributor. Be nice, and check out our Code of Conduct.









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