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Magento2.3 : How do I programmatically submit a form generated via a UIComponent?


Right way to create butons in uiComponent form in Magento 2uiComponent Form. How to show data from DB tableuiComponent Form Save Button Not workingMagento 2.1 UI Component Image upload formDisplay an array of Jquery data in HTMLSubmit Form Button uiComponent Magento2Magento 2 Form UiComponent ExplainationSubmit Button in UIComponentCreate attribute programmatically in magento2.3Image Uploader throws Uncaught type Error in Ui Component






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I created a UI Component form, but I am unable to find the element in the source.



I would like to click a button and then inspect a field in the form and dependent on what value is selected submit the form to a specific url.



In my uiComponent I have,



 <argument name="data" xsi:type="array">
<item name="js_config" xsi:type="array">
<item name="component" xsi:type="string">Vendor_Module/js/ui/form/new_form</item>
</item>


Then I have the following code in Vendor_Module/js/ui/form/new_form:



define(
[
'jquery',
'Magento_Ui/js/form/form',
'mage/url'
],
function ($, form, url) {
'use strict';

return form.extend({
initialize: function ()
this._super();

$('#new_button').click(this.new_button);

return this;
,
new_button: function (redirect, data)
this.validate();

if (!this.additionalInvalid && !this.source.get('params.invalid'))

// CUSTOM CODE HERE BEFORE SUBMIT

this.setAdditionalData(data)
.submit(redirect);
else
this.focusInvalid();




I am currently getting,




Uncaught TypeError: this.validate is not a function











share|improve this question









New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Can you please paste your code here? Thanks

    – Shankar
    May 18 at 5:47











  • @Shankar I have added the code as requested.

    – Eugene Louw
    May 19 at 18:57

















1















I created a UI Component form, but I am unable to find the element in the source.



I would like to click a button and then inspect a field in the form and dependent on what value is selected submit the form to a specific url.



In my uiComponent I have,



 <argument name="data" xsi:type="array">
<item name="js_config" xsi:type="array">
<item name="component" xsi:type="string">Vendor_Module/js/ui/form/new_form</item>
</item>


Then I have the following code in Vendor_Module/js/ui/form/new_form:



define(
[
'jquery',
'Magento_Ui/js/form/form',
'mage/url'
],
function ($, form, url) {
'use strict';

return form.extend({
initialize: function ()
this._super();

$('#new_button').click(this.new_button);

return this;
,
new_button: function (redirect, data)
this.validate();

if (!this.additionalInvalid && !this.source.get('params.invalid'))

// CUSTOM CODE HERE BEFORE SUBMIT

this.setAdditionalData(data)
.submit(redirect);
else
this.focusInvalid();




I am currently getting,




Uncaught TypeError: this.validate is not a function











share|improve this question









New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Can you please paste your code here? Thanks

    – Shankar
    May 18 at 5:47











  • @Shankar I have added the code as requested.

    – Eugene Louw
    May 19 at 18:57













1












1








1


1






I created a UI Component form, but I am unable to find the element in the source.



I would like to click a button and then inspect a field in the form and dependent on what value is selected submit the form to a specific url.



In my uiComponent I have,



 <argument name="data" xsi:type="array">
<item name="js_config" xsi:type="array">
<item name="component" xsi:type="string">Vendor_Module/js/ui/form/new_form</item>
</item>


Then I have the following code in Vendor_Module/js/ui/form/new_form:



define(
[
'jquery',
'Magento_Ui/js/form/form',
'mage/url'
],
function ($, form, url) {
'use strict';

return form.extend({
initialize: function ()
this._super();

$('#new_button').click(this.new_button);

return this;
,
new_button: function (redirect, data)
this.validate();

if (!this.additionalInvalid && !this.source.get('params.invalid'))

// CUSTOM CODE HERE BEFORE SUBMIT

this.setAdditionalData(data)
.submit(redirect);
else
this.focusInvalid();




I am currently getting,




Uncaught TypeError: this.validate is not a function











share|improve this question









New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I created a UI Component form, but I am unable to find the element in the source.



I would like to click a button and then inspect a field in the form and dependent on what value is selected submit the form to a specific url.



In my uiComponent I have,



 <argument name="data" xsi:type="array">
<item name="js_config" xsi:type="array">
<item name="component" xsi:type="string">Vendor_Module/js/ui/form/new_form</item>
</item>


Then I have the following code in Vendor_Module/js/ui/form/new_form:



define(
[
'jquery',
'Magento_Ui/js/form/form',
'mage/url'
],
function ($, form, url) {
'use strict';

return form.extend({
initialize: function ()
this._super();

$('#new_button').click(this.new_button);

return this;
,
new_button: function (redirect, data)
this.validate();

if (!this.additionalInvalid && !this.source.get('params.invalid'))

// CUSTOM CODE HERE BEFORE SUBMIT

this.setAdditionalData(data)
.submit(redirect);
else
this.focusInvalid();




I am currently getting,




Uncaught TypeError: this.validate is not a function








php javascript magento2.3 uicomponent ui-form






share|improve this question









New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 2 days ago









Sarfaraj

414518




414518






New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked May 17 at 21:20









Eugene LouwEugene Louw

63




63




New contributor



Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Eugene Louw is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • Can you please paste your code here? Thanks

    – Shankar
    May 18 at 5:47











  • @Shankar I have added the code as requested.

    – Eugene Louw
    May 19 at 18:57

















  • Can you please paste your code here? Thanks

    – Shankar
    May 18 at 5:47











  • @Shankar I have added the code as requested.

    – Eugene Louw
    May 19 at 18:57
















Can you please paste your code here? Thanks

– Shankar
May 18 at 5:47





Can you please paste your code here? Thanks

– Shankar
May 18 at 5:47













@Shankar I have added the code as requested.

– Eugene Louw
May 19 at 18:57





@Shankar I have added the code as requested.

– Eugene Louw
May 19 at 18:57










0






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