Correct spacing in the alignat*-environmentAlignement in columns and spacing between columns of an equations environmentHyperref, amsmath, and horizontal spacing at start of a numbered equationwhat is the correct way to typeset equations with a leading indicator/marker on eachDefining new split environment with reduced spacingIncorrect spacing after minus sign with combination of amsmath and hyperrefIs there a cleaner way to get the proper spacing in this alignedat?Number equations and preserving alignment of equal signsSplit an equation into two linesDifferent alignments in alignat environmentInserting spacing between the plus sign and a number
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Correct spacing in the alignat*-environment
Alignement in columns and spacing between columns of an equations environmentHyperref, amsmath, and horizontal spacing at start of a numbered equationwhat is the correct way to typeset equations with a leading indicator/marker on eachDefining new split environment with reduced spacingIncorrect spacing after minus sign with combination of amsmath and hyperrefIs there a cleaner way to get the proper spacing in this alignedat?Number equations and preserving alignment of equal signsSplit an equation into two linesDifferent alignments in alignat environmentInserting spacing between the plus sign and a number
The following code is given:
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
which outputs
The output however should have the same spacing between each number like the first equation h(x) = g_s(x) - g_s(x - 1) has. (In other words, the spacing between the minus sign is too small.) How will I obtain this result?
math-mode equations amsmath alignat
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
add a comment |
The following code is given:
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
which outputs
The output however should have the same spacing between each number like the first equation h(x) = g_s(x) - g_s(x - 1) has. (In other words, the spacing between the minus sign is too small.) How will I obtain this result?
math-mode equations amsmath alignat
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
1
as always it's easier to test if you provide a test document not a fragment, but use=
– David Carlisle
Jun 22 at 20:43
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15
add a comment |
The following code is given:
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
which outputs
The output however should have the same spacing between each number like the first equation h(x) = g_s(x) - g_s(x - 1) has. (In other words, the spacing between the minus sign is too small.) How will I obtain this result?
math-mode equations amsmath alignat
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
The following code is given:
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
which outputs
The output however should have the same spacing between each number like the first equation h(x) = g_s(x) - g_s(x - 1) has. (In other words, the spacing between the minus sign is too small.) How will I obtain this result?
math-mode equations amsmath alignat
math-mode equations amsmath alignat
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
asked Jun 22 at 20:39
DoesbaddelDoesbaddel
1578 bronze badges
1578 bronze badges
1
as always it's easier to test if you provide a test document not a fragment, but use=
– David Carlisle
Jun 22 at 20:43
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15
add a comment |
1
as always it's easier to test if you provide a test document not a fragment, but use=
– David Carlisle
Jun 22 at 20:43
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15
1
1
as always it's easier to test if you provide a test document not a fragment, but use
=– David Carlisle
Jun 22 at 20:43
as always it's easier to test if you provide a test document not a fragment, but use
=– David Carlisle
Jun 22 at 20:43
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15
add a comment |
3 Answers
3
active
oldest
votes
Two ways depending how you think of it - forces a binary - but you could view the form as only having right hand sides of the second and third groups so if you mark the empty lhs with && then the - at the start of the right hand sides get the usual space.
documentclassarticle
usepackageamsmath,nicefrac
begindocument
aaa
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
bbb
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
ccc
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 && - 0.00 && = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 && - 0.25 && = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 && - 0.50 && = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 && - 0.75 && = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 && - 1.00 && = 0
endalignat*
enddocument
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
@Doesbaddel same result here as your numbers are same width but change the0.75to0.7and you will see the&&version keeps them left aligned wehereas your original and the-version right aligns them. I think&&is better actually but...
– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
add a comment |
Using = solves the spacing issue:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
enddocument
(I do not have the package nicefrac installed. I would recommend to use tfrac instead of nicefrac. Most mathematicians prefer a horizontal fraction bar.)
Edit
Here is another version that might make more sense with respect to the structure of the content:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) && = 0.25 - 0.00 && = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) && = 0.50 - 0.25 && = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) && = 0.75 - 0.50 && = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) && = 1.00 - 0.75 && = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) && = 1.00 - 1.00 && = 0
endalignat*
enddocument
David Carlisle shows yet another version for placing the delimiters in his answer to this question. All versions have pros and cons, and it depends, e.g., on the format of the numbers and the other content, which one is best.
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
add a comment |
A tabstackengine approach. Here, the TABbinary forces the leading negatives to be considered binary, the setstackalingap allows the horizontal gap between align groups to be eliminated and the setsatckgapL allows for the baselineskip to be set.
documentclassarticle
usepackageamsmath,nicefrac,tabstackengine
TABstackMath
begindocument
[
TABbinary
setstackaligngap0pt
setstackgapL1.2baselineskip
alignCenterstack
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
]
enddocument
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
add a comment |
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3 Answers
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active
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votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Two ways depending how you think of it - forces a binary - but you could view the form as only having right hand sides of the second and third groups so if you mark the empty lhs with && then the - at the start of the right hand sides get the usual space.
documentclassarticle
usepackageamsmath,nicefrac
begindocument
aaa
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
bbb
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
ccc
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 && - 0.00 && = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 && - 0.25 && = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 && - 0.50 && = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 && - 0.75 && = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 && - 1.00 && = 0
endalignat*
enddocument
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
@Doesbaddel same result here as your numbers are same width but change the0.75to0.7and you will see the&&version keeps them left aligned wehereas your original and the-version right aligns them. I think&&is better actually but...
– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
add a comment |
Two ways depending how you think of it - forces a binary - but you could view the form as only having right hand sides of the second and third groups so if you mark the empty lhs with && then the - at the start of the right hand sides get the usual space.
documentclassarticle
usepackageamsmath,nicefrac
begindocument
aaa
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
bbb
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
ccc
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 && - 0.00 && = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 && - 0.25 && = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 && - 0.50 && = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 && - 0.75 && = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 && - 1.00 && = 0
endalignat*
enddocument
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
@Doesbaddel same result here as your numbers are same width but change the0.75to0.7and you will see the&&version keeps them left aligned wehereas your original and the-version right aligns them. I think&&is better actually but...
– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
add a comment |
Two ways depending how you think of it - forces a binary - but you could view the form as only having right hand sides of the second and third groups so if you mark the empty lhs with && then the - at the start of the right hand sides get the usual space.
documentclassarticle
usepackageamsmath,nicefrac
begindocument
aaa
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
bbb
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
ccc
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 && - 0.00 && = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 && - 0.25 && = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 && - 0.50 && = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 && - 0.75 && = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 && - 1.00 && = 0
endalignat*
enddocument
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
Two ways depending how you think of it - forces a binary - but you could view the form as only having right hand sides of the second and third groups so if you mark the empty lhs with && then the - at the start of the right hand sides get the usual space.
documentclassarticle
usepackageamsmath,nicefrac
begindocument
aaa
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
bbb
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
ccc
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 && - 0.00 && = nicefrac14\
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 && - 0.25 && = nicefrac14\
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 && - 0.50 && = nicefrac14\
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 && - 0.75 && = nicefrac14\
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 && - 1.00 && = 0
endalignat*
enddocument
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
513k44 gold badges1163 silver badges1927 bronze badges
answered Jun 22 at 20:51
David CarlisleDavid Carlisle
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513k44 gold badges1163 silver badges1927 bronze badges
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
@Doesbaddel same result here as your numbers are same width but change the0.75to0.7and you will see the&&version keeps them left aligned wehereas your original and the-version right aligns them. I think&&is better actually but...
– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
add a comment |
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
@Doesbaddel same result here as your numbers are same width but change the0.75to0.7and you will see the&&version keeps them left aligned wehereas your original and the-version right aligns them. I think&&is better actually but...
– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
Is there a difference between b) and c) or do both variants produce exactly the same result?
– Doesbaddel
Jun 22 at 21:17
1
1
@Doesbaddel same result here as your numbers are same width but change the
0.75 to 0.7 and you will see the && version keeps them left aligned wehereas your original and the - version right aligns them. I think && is better actually but...– David Carlisle
Jun 22 at 21:39
@Doesbaddel same result here as your numbers are same width but change the
0.75 to 0.7 and you will see the && version keeps them left aligned wehereas your original and the - version right aligns them. I think && is better actually but...– David Carlisle
Jun 22 at 21:39
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
Ok, thank you for clarification!
– Doesbaddel
Jun 22 at 22:07
add a comment |
Using = solves the spacing issue:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
enddocument
(I do not have the package nicefrac installed. I would recommend to use tfrac instead of nicefrac. Most mathematicians prefer a horizontal fraction bar.)
Edit
Here is another version that might make more sense with respect to the structure of the content:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) && = 0.25 - 0.00 && = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) && = 0.50 - 0.25 && = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) && = 0.75 - 0.50 && = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) && = 1.00 - 0.75 && = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) && = 1.00 - 1.00 && = 0
endalignat*
enddocument
David Carlisle shows yet another version for placing the delimiters in his answer to this question. All versions have pros and cons, and it depends, e.g., on the format of the numbers and the other content, which one is best.
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
add a comment |
Using = solves the spacing issue:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
enddocument
(I do not have the package nicefrac installed. I would recommend to use tfrac instead of nicefrac. Most mathematicians prefer a horizontal fraction bar.)
Edit
Here is another version that might make more sense with respect to the structure of the content:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) && = 0.25 - 0.00 && = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) && = 0.50 - 0.25 && = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) && = 0.75 - 0.50 && = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) && = 1.00 - 0.75 && = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) && = 1.00 - 1.00 && = 0
endalignat*
enddocument
David Carlisle shows yet another version for placing the delimiters in his answer to this question. All versions have pros and cons, and it depends, e.g., on the format of the numbers and the other content, which one is best.
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
add a comment |
Using = solves the spacing issue:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
enddocument
(I do not have the package nicefrac installed. I would recommend to use tfrac instead of nicefrac. Most mathematicians prefer a horizontal fraction bar.)
Edit
Here is another version that might make more sense with respect to the structure of the content:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) && = 0.25 - 0.00 && = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) && = 0.50 - 0.25 && = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) && = 0.75 - 0.50 && = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) && = 1.00 - 0.75 && = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) && = 1.00 - 1.00 && = 0
endalignat*
enddocument
David Carlisle shows yet another version for placing the delimiters in his answer to this question. All versions have pros and cons, and it depends, e.g., on the format of the numbers and the other content, which one is best.
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
Using = solves the spacing issue:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
endalignat*
enddocument
(I do not have the package nicefrac installed. I would recommend to use tfrac instead of nicefrac. Most mathematicians prefer a horizontal fraction bar.)
Edit
Here is another version that might make more sense with respect to the structure of the content:
documentclassarticle
usepackageamsmath
usepackagenicefrac
begindocument
beginalignat*3
h(0) & = g_s(0) - g_s(0 - 1) && = 0.25 - 0.00 && = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) && = 0.50 - 0.25 && = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) && = 0.75 - 0.50 && = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) && = 1.00 - 0.75 && = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) && = 1.00 - 1.00 && = 0
endalignat*
enddocument
David Carlisle shows yet another version for placing the delimiters in his answer to this question. All versions have pros and cons, and it depends, e.g., on the format of the numbers and the other content, which one is best.
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
edited Jun 23 at 6:46
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
answered Jun 22 at 20:45
MatthiasMatthias
9755 silver badges16 bronze badges
9755 silver badges16 bronze badges
add a comment |
add a comment |
A tabstackengine approach. Here, the TABbinary forces the leading negatives to be considered binary, the setstackalingap allows the horizontal gap between align groups to be eliminated and the setsatckgapL allows for the baselineskip to be set.
documentclassarticle
usepackageamsmath,nicefrac,tabstackengine
TABstackMath
begindocument
[
TABbinary
setstackaligngap0pt
setstackgapL1.2baselineskip
alignCenterstack
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
]
enddocument
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
add a comment |
A tabstackengine approach. Here, the TABbinary forces the leading negatives to be considered binary, the setstackalingap allows the horizontal gap between align groups to be eliminated and the setsatckgapL allows for the baselineskip to be set.
documentclassarticle
usepackageamsmath,nicefrac,tabstackengine
TABstackMath
begindocument
[
TABbinary
setstackaligngap0pt
setstackgapL1.2baselineskip
alignCenterstack
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
]
enddocument
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
add a comment |
A tabstackengine approach. Here, the TABbinary forces the leading negatives to be considered binary, the setstackalingap allows the horizontal gap between align groups to be eliminated and the setsatckgapL allows for the baselineskip to be set.
documentclassarticle
usepackageamsmath,nicefrac,tabstackengine
TABstackMath
begindocument
[
TABbinary
setstackaligngap0pt
setstackgapL1.2baselineskip
alignCenterstack
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
]
enddocument
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
A tabstackengine approach. Here, the TABbinary forces the leading negatives to be considered binary, the setstackalingap allows the horizontal gap between align groups to be eliminated and the setsatckgapL allows for the baselineskip to be set.
documentclassarticle
usepackageamsmath,nicefrac,tabstackengine
TABstackMath
begindocument
[
TABbinary
setstackaligngap0pt
setstackgapL1.2baselineskip
alignCenterstack
h(0) & = g_s(0) - g_s(0 - 1) = 0.25 & - 0.00 & = nicefrac14 \
h(1) & = g_s(1) - g_s(1 - 1) = 0.50 & - 0.25 & = nicefrac14 \
h(2) & = g_s(2) - g_s(2 - 1) = 0.75 & - 0.50 & = nicefrac14 \
h(3) & = g_s(3) - g_s(3 - 1) = 1.00 & - 0.75 & = nicefrac14 \
h(4) & = g_s(4) - g_s(4 - 1) = 1.00 & - 1.00 & = 0
]
enddocument
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
answered Jun 22 at 20:55
Steven B. SegletesSteven B. Segletes
167k9 gold badges210 silver badges429 bronze badges
167k9 gold badges210 silver badges429 bronze badges
add a comment |
add a comment |
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1
as always it's easier to test if you provide a test document not a fragment, but use
=– David Carlisle
Jun 22 at 20:43
I will take this into consideration for my next posts, thanks for pointing that out.
– Doesbaddel
Jun 22 at 21:15