Dynamic filling of a region of a polar plot Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How to plot filling under a curve?Filling only part of a plotFilling between ParametricPlot and PlotGenerating hatched filling using Region functionalityFilling a Manipulate PlotHow can I increase the font size in PlotLabel?Filling under plotFilling the region under a lineFilling in parametric plotHow to shade a region using Filling function
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Dynamic filling of a region of a polar plot
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?How to plot filling under a curve?Filling only part of a plotFilling between ParametricPlot and PlotGenerating hatched filling using Region functionalityFilling a Manipulate PlotHow can I increase the font size in PlotLabel?Filling under plotFilling the region under a lineFilling in parametric plotHow to shade a region using Filling function
$begingroup$
I would like to shade area of region as a function of angle using PolarPlot
.
Here is my attempt.
With[
pts =
Cases[PolarPlot[1 + 2 Sin[θ], θ, 0, 2 π], _Line, 0, Infinity][[1, 1]],
Manipulate[
Show[
ListLinePlot[0, 0, pts[[n]], pts[[1 ;; n]],
Filling -> 2 -> Axis, LightBlue, 1 -> Axis, LightBlue,
PlotRange -> -2, 2, -0.5, 3.2, AspectRatio -> 1,
PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
ImageSize -> 500, AxesStyle -> Directive[Black, 18],
PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
PolarPlot[1 + 2 Sin[θ], θ, 0, 2.2 π,
AspectRatio -> 1, PlotStyle -> Black, AbsoluteThickness@3]],
n, 1, Length @ pts, 1]]
Two thing I would like to achieve:
- I don't want to see the yellow highlited region.
- When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.
Any suggestion..
plotting filling
$endgroup$
add a comment |
$begingroup$
I would like to shade area of region as a function of angle using PolarPlot
.
Here is my attempt.
With[
pts =
Cases[PolarPlot[1 + 2 Sin[θ], θ, 0, 2 π], _Line, 0, Infinity][[1, 1]],
Manipulate[
Show[
ListLinePlot[0, 0, pts[[n]], pts[[1 ;; n]],
Filling -> 2 -> Axis, LightBlue, 1 -> Axis, LightBlue,
PlotRange -> -2, 2, -0.5, 3.2, AspectRatio -> 1,
PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
ImageSize -> 500, AxesStyle -> Directive[Black, 18],
PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
PolarPlot[1 + 2 Sin[θ], θ, 0, 2.2 π,
AspectRatio -> 1, PlotStyle -> Black, AbsoluteThickness@3]],
n, 1, Length @ pts, 1]]
Two thing I would like to achieve:
- I don't want to see the yellow highlited region.
- When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.
Any suggestion..
plotting filling
$endgroup$
add a comment |
$begingroup$
I would like to shade area of region as a function of angle using PolarPlot
.
Here is my attempt.
With[
pts =
Cases[PolarPlot[1 + 2 Sin[θ], θ, 0, 2 π], _Line, 0, Infinity][[1, 1]],
Manipulate[
Show[
ListLinePlot[0, 0, pts[[n]], pts[[1 ;; n]],
Filling -> 2 -> Axis, LightBlue, 1 -> Axis, LightBlue,
PlotRange -> -2, 2, -0.5, 3.2, AspectRatio -> 1,
PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
ImageSize -> 500, AxesStyle -> Directive[Black, 18],
PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
PolarPlot[1 + 2 Sin[θ], θ, 0, 2.2 π,
AspectRatio -> 1, PlotStyle -> Black, AbsoluteThickness@3]],
n, 1, Length @ pts, 1]]
Two thing I would like to achieve:
- I don't want to see the yellow highlited region.
- When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.
Any suggestion..
plotting filling
$endgroup$
I would like to shade area of region as a function of angle using PolarPlot
.
Here is my attempt.
With[
pts =
Cases[PolarPlot[1 + 2 Sin[θ], θ, 0, 2 π], _Line, 0, Infinity][[1, 1]],
Manipulate[
Show[
ListLinePlot[0, 0, pts[[n]], pts[[1 ;; n]],
Filling -> 2 -> Axis, LightBlue, 1 -> Axis, LightBlue,
PlotRange -> -2, 2, -0.5, 3.2, AspectRatio -> 1,
PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
ImageSize -> 500, AxesStyle -> Directive[Black, 18],
PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
PolarPlot[1 + 2 Sin[θ], θ, 0, 2.2 π,
AspectRatio -> 1, PlotStyle -> Black, AbsoluteThickness@3]],
n, 1, Length @ pts, 1]]
Two thing I would like to achieve:
- I don't want to see the yellow highlited region.
- When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.
Any suggestion..
plotting filling
plotting filling
edited Apr 20 at 1:56
Okkes Dulgerci
asked Apr 19 at 23:46
Okkes DulgerciOkkes Dulgerci
5,5261919
5,5261919
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This is what you need:
Manipulate[ParametricPlot[
r (1 + 2 Sin[θ]) Cos[θ], Sin[θ],
θ, 0, thmax,
r, 0, 1,
PlotRange -> -2.25, 2.25, -0.5, 3.5,
PerformanceGoal -> "Quality"
], thmax, 0.01, 2 Pi]
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is what you need:
Manipulate[ParametricPlot[
r (1 + 2 Sin[θ]) Cos[θ], Sin[θ],
θ, 0, thmax,
r, 0, 1,
PlotRange -> -2.25, 2.25, -0.5, 3.5,
PerformanceGoal -> "Quality"
], thmax, 0.01, 2 Pi]
$endgroup$
add a comment |
$begingroup$
This is what you need:
Manipulate[ParametricPlot[
r (1 + 2 Sin[θ]) Cos[θ], Sin[θ],
θ, 0, thmax,
r, 0, 1,
PlotRange -> -2.25, 2.25, -0.5, 3.5,
PerformanceGoal -> "Quality"
], thmax, 0.01, 2 Pi]
$endgroup$
add a comment |
$begingroup$
This is what you need:
Manipulate[ParametricPlot[
r (1 + 2 Sin[θ]) Cos[θ], Sin[θ],
θ, 0, thmax,
r, 0, 1,
PlotRange -> -2.25, 2.25, -0.5, 3.5,
PerformanceGoal -> "Quality"
], thmax, 0.01, 2 Pi]
$endgroup$
This is what you need:
Manipulate[ParametricPlot[
r (1 + 2 Sin[θ]) Cos[θ], Sin[θ],
θ, 0, thmax,
r, 0, 1,
PlotRange -> -2.25, 2.25, -0.5, 3.5,
PerformanceGoal -> "Quality"
], thmax, 0.01, 2 Pi]
edited 2 days ago
m_goldberg
89k873200
89k873200
answered 2 days ago
C. E.C. E.
51.4k3101207
51.4k3101207
add a comment |
add a comment |
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