Grandpa has another non math questionA simple association between letters and numbersNon-puzzling nephewsAnother Next Number QuestionGrandpa and numbers: Another Grandpa Mystery3 = 6 ? Another non math question. Another Grandpa Mystery$6$ is prime? Another Grandpa Mystery (not made by @DEEM, this time)Alphabets and Numbers? : Another Grandpa MysteryA silly silly questionAre these numbers unique?Can 4 = 6 and 10 = 1000? : Another Grandpa Question“Thinking of ” question for Comics readers

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Fantasy game inventory — Ch. 5 Automate the Boring Stuff

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Does cooling a potato change the nature of its carbohydrates?

Why swap space doesn't get filesystem check at boot time?

Is it a bad idea to have a pen name with only an initial for a surname?

What is the context for Napoleon's quote "[the Austrians] did not know the value of five minutes"?

How do credit card companies know what type of business I'm paying for?

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Boundaries and Buddhism

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Would a 7805 5v regulator drain a 9v battery?

Scaling an object to change its key

What is the precise meaning of "подсел на мак"?



Grandpa has another non math question


A simple association between letters and numbersNon-puzzling nephewsAnother Next Number QuestionGrandpa and numbers: Another Grandpa Mystery3 = 6 ? Another non math question. Another Grandpa Mystery$6$ is prime? Another Grandpa Mystery (not made by @DEEM, this time)Alphabets and Numbers? : Another Grandpa MysteryA silly silly questionAre these numbers unique?Can 4 = 6 and 10 = 1000? : Another Grandpa Question“Thinking of ” question for Comics readers













15












$begingroup$


Grandpa says, " This is not algebra or may be it is!



IF




X = 2



R + C = 6



B + P = 5 or 6



Then



What is



I + T ?




There are, with my logic, three different answers!"










share|improve this question









$endgroup$











  • $begingroup$
    Yay! Another one of these! +1 and favorite.
    $endgroup$
    – Duck
    Jun 9 at 20:23







  • 2




    $begingroup$
    Grandpa seems like a troublemaker.
    $endgroup$
    – Rubio
    Jun 9 at 20:24






  • 2




    $begingroup$
    That he is @Rubio that he is. (Ask Grandma)
    $endgroup$
    – DEEM
    Jun 9 at 20:25










  • $begingroup$
    Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
    $endgroup$
    – Duck
    Jun 9 at 20:26











  • $begingroup$
    not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
    $endgroup$
    – DEEM
    Jun 9 at 20:39















15












$begingroup$


Grandpa says, " This is not algebra or may be it is!



IF




X = 2



R + C = 6



B + P = 5 or 6



Then



What is



I + T ?




There are, with my logic, three different answers!"










share|improve this question









$endgroup$











  • $begingroup$
    Yay! Another one of these! +1 and favorite.
    $endgroup$
    – Duck
    Jun 9 at 20:23







  • 2




    $begingroup$
    Grandpa seems like a troublemaker.
    $endgroup$
    – Rubio
    Jun 9 at 20:24






  • 2




    $begingroup$
    That he is @Rubio that he is. (Ask Grandma)
    $endgroup$
    – DEEM
    Jun 9 at 20:25










  • $begingroup$
    Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
    $endgroup$
    – Duck
    Jun 9 at 20:26











  • $begingroup$
    not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
    $endgroup$
    – DEEM
    Jun 9 at 20:39













15












15








15


1



$begingroup$


Grandpa says, " This is not algebra or may be it is!



IF




X = 2



R + C = 6



B + P = 5 or 6



Then



What is



I + T ?




There are, with my logic, three different answers!"










share|improve this question









$endgroup$




Grandpa says, " This is not algebra or may be it is!



IF




X = 2



R + C = 6



B + P = 5 or 6



Then



What is



I + T ?




There are, with my logic, three different answers!"







lateral-thinking






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jun 9 at 20:11









DEEMDEEM

6,917123125




6,917123125











  • $begingroup$
    Yay! Another one of these! +1 and favorite.
    $endgroup$
    – Duck
    Jun 9 at 20:23







  • 2




    $begingroup$
    Grandpa seems like a troublemaker.
    $endgroup$
    – Rubio
    Jun 9 at 20:24






  • 2




    $begingroup$
    That he is @Rubio that he is. (Ask Grandma)
    $endgroup$
    – DEEM
    Jun 9 at 20:25










  • $begingroup$
    Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
    $endgroup$
    – Duck
    Jun 9 at 20:26











  • $begingroup$
    not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
    $endgroup$
    – DEEM
    Jun 9 at 20:39
















  • $begingroup$
    Yay! Another one of these! +1 and favorite.
    $endgroup$
    – Duck
    Jun 9 at 20:23







  • 2




    $begingroup$
    Grandpa seems like a troublemaker.
    $endgroup$
    – Rubio
    Jun 9 at 20:24






  • 2




    $begingroup$
    That he is @Rubio that he is. (Ask Grandma)
    $endgroup$
    – DEEM
    Jun 9 at 20:25










  • $begingroup$
    Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
    $endgroup$
    – Duck
    Jun 9 at 20:26











  • $begingroup$
    not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
    $endgroup$
    – DEEM
    Jun 9 at 20:39















$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23





$begingroup$
Yay! Another one of these! +1 and favorite.
$endgroup$
– Duck
Jun 9 at 20:23





2




2




$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio
Jun 9 at 20:24




$begingroup$
Grandpa seems like a troublemaker.
$endgroup$
– Rubio
Jun 9 at 20:24




2




2




$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25




$begingroup$
That he is @Rubio that he is. (Ask Grandma)
$endgroup$
– DEEM
Jun 9 at 20:25












$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26





$begingroup$
Rot13 (Guerr nafjref, guerr jrveq fcnprf, naq guerr jrveq pncvgnyvmrq yrggref... Uzz... Fb gur nafjre vf 3?)
$endgroup$
– Duck
Jun 9 at 20:26













$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39




$begingroup$
not really @Duck But if you know Grandpa he has his weird logic he practices all the time.
$endgroup$
– DEEM
Jun 9 at 20:39










2 Answers
2






active

oldest

votes


















22












$begingroup$

Here’s a thought...



X = 2




X is said like the word “ex” = 2 letters




R + C = 6




“are” plus “cee” (or “see” or “sea”) = 6




B + P = 5 or 6




“be” or “bee” plus “pee” (or “pea”) = 5 or 6




Thus, I + T =




Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6




for three solutions using the same logic, as requested.




... and “ti” would actually allow four answers, 3 4 5 or 6 :)







share|improve this answer









$endgroup$












  • $begingroup$
    heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
    $endgroup$
    – Jonathan Allan
    Jun 10 at 12:17







  • 1




    $begingroup$
    I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
    $endgroup$
    – Bizhan
    Jun 10 at 15:34







  • 1




    $begingroup$
    @Bizhan ay me, you might be right. Er, wait ...
    $endgroup$
    – Rubio
    Jun 11 at 2:08










  • $begingroup$
    Oh! ay me! haha!
    $endgroup$
    – Bizhan
    Jun 11 at 7:27


















3












$begingroup$

X = 2




X is written in two strokes




R + C = 6




R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6




B + P = 5 or 6




B is 2 strokes, + is 2, P is 2 which will result in 6?




I + T




I will be 1 stroke + is 2, T is also 2 which will make 5







share|improve this answer









$endgroup$








  • 3




    $begingroup$
    How do you make B two? At least three, surely.
    $endgroup$
    – Rand al'Thor
    Jun 10 at 9:04










  • $begingroup$
    This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
    $endgroup$
    – Rubio
    Jun 10 at 9:50










  • $begingroup$
    @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
    $endgroup$
    – UKMonkey
    Jun 10 at 10:19











  • $begingroup$
    I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
    $endgroup$
    – Mario Garcia
    Jun 10 at 11:26










  • $begingroup$
    This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
    $endgroup$
    – Darrel Hoffman
    Jun 10 at 12:47











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









22












$begingroup$

Here’s a thought...



X = 2




X is said like the word “ex” = 2 letters




R + C = 6




“are” plus “cee” (or “see” or “sea”) = 6




B + P = 5 or 6




“be” or “bee” plus “pee” (or “pea”) = 5 or 6




Thus, I + T =




Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6




for three solutions using the same logic, as requested.




... and “ti” would actually allow four answers, 3 4 5 or 6 :)







share|improve this answer









$endgroup$












  • $begingroup$
    heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
    $endgroup$
    – Jonathan Allan
    Jun 10 at 12:17







  • 1




    $begingroup$
    I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
    $endgroup$
    – Bizhan
    Jun 10 at 15:34







  • 1




    $begingroup$
    @Bizhan ay me, you might be right. Er, wait ...
    $endgroup$
    – Rubio
    Jun 11 at 2:08










  • $begingroup$
    Oh! ay me! haha!
    $endgroup$
    – Bizhan
    Jun 11 at 7:27















22












$begingroup$

Here’s a thought...



X = 2




X is said like the word “ex” = 2 letters




R + C = 6




“are” plus “cee” (or “see” or “sea”) = 6




B + P = 5 or 6




“be” or “bee” plus “pee” (or “pea”) = 5 or 6




Thus, I + T =




Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6




for three solutions using the same logic, as requested.




... and “ti” would actually allow four answers, 3 4 5 or 6 :)







share|improve this answer









$endgroup$












  • $begingroup$
    heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
    $endgroup$
    – Jonathan Allan
    Jun 10 at 12:17







  • 1




    $begingroup$
    I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
    $endgroup$
    – Bizhan
    Jun 10 at 15:34







  • 1




    $begingroup$
    @Bizhan ay me, you might be right. Er, wait ...
    $endgroup$
    – Rubio
    Jun 11 at 2:08










  • $begingroup$
    Oh! ay me! haha!
    $endgroup$
    – Bizhan
    Jun 11 at 7:27













22












22








22





$begingroup$

Here’s a thought...



X = 2




X is said like the word “ex” = 2 letters




R + C = 6




“are” plus “cee” (or “see” or “sea”) = 6




B + P = 5 or 6




“be” or “bee” plus “pee” (or “pea”) = 5 or 6




Thus, I + T =




Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6




for three solutions using the same logic, as requested.




... and “ti” would actually allow four answers, 3 4 5 or 6 :)







share|improve this answer









$endgroup$



Here’s a thought...



X = 2




X is said like the word “ex” = 2 letters




R + C = 6




“are” plus “cee” (or “see” or “sea”) = 6




B + P = 5 or 6




“be” or “bee” plus “pee” (or “pea”) = 5 or 6




Thus, I + T =




Any of “I”, “ai”, “ay”, “aye” or “eye”, plus “tee” (or “tea”) = 4,5, or 6




for three solutions using the same logic, as requested.




... and “ti” would actually allow four answers, 3 4 5 or 6 :)








share|improve this answer












share|improve this answer



share|improve this answer










answered Jun 9 at 23:59









RubioRubio

32.2k669196




32.2k669196











  • $begingroup$
    heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
    $endgroup$
    – Jonathan Allan
    Jun 10 at 12:17







  • 1




    $begingroup$
    I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
    $endgroup$
    – Bizhan
    Jun 10 at 15:34







  • 1




    $begingroup$
    @Bizhan ay me, you might be right. Er, wait ...
    $endgroup$
    – Rubio
    Jun 11 at 2:08










  • $begingroup$
    Oh! ay me! haha!
    $endgroup$
    – Bizhan
    Jun 11 at 7:27
















  • $begingroup$
    heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
    $endgroup$
    – Jonathan Allan
    Jun 10 at 12:17







  • 1




    $begingroup$
    I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
    $endgroup$
    – Bizhan
    Jun 10 at 15:34







  • 1




    $begingroup$
    @Bizhan ay me, you might be right. Er, wait ...
    $endgroup$
    – Rubio
    Jun 11 at 2:08










  • $begingroup$
    Oh! ay me! haha!
    $endgroup$
    – Bizhan
    Jun 11 at 7:27















$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17





$begingroup$
heh I thought of this when I saw the puzzle, but Had "R+C" = 5 or 6 and four answers for "I+T", so thought it must be wrong. (rot13 nu)
$endgroup$
– Jonathan Allan
Jun 10 at 12:17





1




1




$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34





$begingroup$
I would exclude "ay" from the answers. "ay" is just "aye" the same way "X" is "ex". (unless it means somethings else) but your answer is still valid.
$endgroup$
– Bizhan
Jun 10 at 15:34





1




1




$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio
Jun 11 at 2:08




$begingroup$
@Bizhan ay me, you might be right. Er, wait ...
$endgroup$
– Rubio
Jun 11 at 2:08












$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27




$begingroup$
Oh! ay me! haha!
$endgroup$
– Bizhan
Jun 11 at 7:27











3












$begingroup$

X = 2




X is written in two strokes




R + C = 6




R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6




B + P = 5 or 6




B is 2 strokes, + is 2, P is 2 which will result in 6?




I + T




I will be 1 stroke + is 2, T is also 2 which will make 5







share|improve this answer









$endgroup$








  • 3




    $begingroup$
    How do you make B two? At least three, surely.
    $endgroup$
    – Rand al'Thor
    Jun 10 at 9:04










  • $begingroup$
    This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
    $endgroup$
    – Rubio
    Jun 10 at 9:50










  • $begingroup$
    @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
    $endgroup$
    – UKMonkey
    Jun 10 at 10:19











  • $begingroup$
    I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
    $endgroup$
    – Mario Garcia
    Jun 10 at 11:26










  • $begingroup$
    This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
    $endgroup$
    – Darrel Hoffman
    Jun 10 at 12:47















3












$begingroup$

X = 2




X is written in two strokes




R + C = 6




R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6




B + P = 5 or 6




B is 2 strokes, + is 2, P is 2 which will result in 6?




I + T




I will be 1 stroke + is 2, T is also 2 which will make 5







share|improve this answer









$endgroup$








  • 3




    $begingroup$
    How do you make B two? At least three, surely.
    $endgroup$
    – Rand al'Thor
    Jun 10 at 9:04










  • $begingroup$
    This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
    $endgroup$
    – Rubio
    Jun 10 at 9:50










  • $begingroup$
    @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
    $endgroup$
    – UKMonkey
    Jun 10 at 10:19











  • $begingroup$
    I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
    $endgroup$
    – Mario Garcia
    Jun 10 at 11:26










  • $begingroup$
    This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
    $endgroup$
    – Darrel Hoffman
    Jun 10 at 12:47













3












3








3





$begingroup$

X = 2




X is written in two strokes




R + C = 6




R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6




B + P = 5 or 6




B is 2 strokes, + is 2, P is 2 which will result in 6?




I + T




I will be 1 stroke + is 2, T is also 2 which will make 5







share|improve this answer









$endgroup$



X = 2




X is written in two strokes




R + C = 6




R is 3 strokes and + is 2 stroke, C is 1, combine that will be 6




B + P = 5 or 6




B is 2 strokes, + is 2, P is 2 which will result in 6?




I + T




I will be 1 stroke + is 2, T is also 2 which will make 5








share|improve this answer












share|improve this answer



share|improve this answer










answered Jun 10 at 7:26









MichaelMichael

692




692







  • 3




    $begingroup$
    How do you make B two? At least three, surely.
    $endgroup$
    – Rand al'Thor
    Jun 10 at 9:04










  • $begingroup$
    This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
    $endgroup$
    – Rubio
    Jun 10 at 9:50










  • $begingroup$
    @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
    $endgroup$
    – UKMonkey
    Jun 10 at 10:19











  • $begingroup$
    I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
    $endgroup$
    – Mario Garcia
    Jun 10 at 11:26










  • $begingroup$
    This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
    $endgroup$
    – Darrel Hoffman
    Jun 10 at 12:47












  • 3




    $begingroup$
    How do you make B two? At least three, surely.
    $endgroup$
    – Rand al'Thor
    Jun 10 at 9:04










  • $begingroup$
    This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
    $endgroup$
    – Rubio
    Jun 10 at 9:50










  • $begingroup$
    @Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
    $endgroup$
    – UKMonkey
    Jun 10 at 10:19











  • $begingroup$
    I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
    $endgroup$
    – Mario Garcia
    Jun 10 at 11:26










  • $begingroup$
    This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
    $endgroup$
    – Darrel Hoffman
    Jun 10 at 12:47







3




3




$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04




$begingroup$
How do you make B two? At least three, surely.
$endgroup$
– Rand al'Thor
Jun 10 at 9:04












$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio
Jun 10 at 9:50




$begingroup$
This was my first thought, but immediately discarded for the reason @Randal'Thor stated.
$endgroup$
– Rubio
Jun 10 at 9:50












$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
$endgroup$
– UKMonkey
Jun 10 at 10:19





$begingroup$
@Randal'Thor Rather than print spoilers in the comments - the answer is "the word used is wrong; but the concept is I 3"
$endgroup$
– UKMonkey
Jun 10 at 10:19













$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26




$begingroup$
I agree with this one, plus P can be made in 1 stroke, which makes sense for 5 or 6
$endgroup$
– Mario Garcia
Jun 10 at 11:26












$begingroup$
This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47




$begingroup$
This also fails to have 3 possible answers. You can debate how many there are for B or P, but I + T is pretty unambiguous by these rules.
$endgroup$
– Darrel Hoffman
Jun 10 at 12:47

















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