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SQL Server (JOIN) all from first with NULLs from 2nd


SQL Server Query: Inefficient where clauseSQL join query to show rows with non-existent rows in one tableOUTER JOIN with join condition causes unexpected resultsCheck for existing matches to find the field their grouped-bystats_date is nullPerformance gap between WHERE IN (1,2,3,4) vs IN (select * from STRING_SPLIT('1,2,3,4',','))Difference between two tablesSQL Server 2016 ISNULL Returning 1900-01-01How to perform JOIN and only use single record for each instance on 2nd tableDynamic SQL - How can you use it to run a SELECT against all schema's and Tables?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















I have 2 tables (Reps and DailyStartTimes).
the Rep Table returns 37 rows, but when I Join it with the 2nd table I get 36 rows as the 2nd table only has 36 rows that match the first table. How do I go about getting the 37 rows back with a Null result for the row that was not matched?



Here is the query that I have so far



SELECT 
tblReps.[sName] AS 'RepName',
tblReps.sNote AS 'Type',
RIGHT(CAST(tblDaily.sDateAndTimeStart AS smalldatetime), 8) AS 'DayStarted'

FROM
[tblRepresentatives] AS tblReps

FULL OUTER JOIN
tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode

WHERE
tblDaily.sDate = CAST(GETDATE() AS DATE)
AND tblReps.[sActive] = 'True'









share|improve this question







New contributor



Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    3















    I have 2 tables (Reps and DailyStartTimes).
    the Rep Table returns 37 rows, but when I Join it with the 2nd table I get 36 rows as the 2nd table only has 36 rows that match the first table. How do I go about getting the 37 rows back with a Null result for the row that was not matched?



    Here is the query that I have so far



    SELECT 
    tblReps.[sName] AS 'RepName',
    tblReps.sNote AS 'Type',
    RIGHT(CAST(tblDaily.sDateAndTimeStart AS smalldatetime), 8) AS 'DayStarted'

    FROM
    [tblRepresentatives] AS tblReps

    FULL OUTER JOIN
    tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode

    WHERE
    tblDaily.sDate = CAST(GETDATE() AS DATE)
    AND tblReps.[sActive] = 'True'









    share|improve this question







    New contributor



    Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      3












      3








      3


      1






      I have 2 tables (Reps and DailyStartTimes).
      the Rep Table returns 37 rows, but when I Join it with the 2nd table I get 36 rows as the 2nd table only has 36 rows that match the first table. How do I go about getting the 37 rows back with a Null result for the row that was not matched?



      Here is the query that I have so far



      SELECT 
      tblReps.[sName] AS 'RepName',
      tblReps.sNote AS 'Type',
      RIGHT(CAST(tblDaily.sDateAndTimeStart AS smalldatetime), 8) AS 'DayStarted'

      FROM
      [tblRepresentatives] AS tblReps

      FULL OUTER JOIN
      tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode

      WHERE
      tblDaily.sDate = CAST(GETDATE() AS DATE)
      AND tblReps.[sActive] = 'True'









      share|improve this question







      New contributor



      Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I have 2 tables (Reps and DailyStartTimes).
      the Rep Table returns 37 rows, but when I Join it with the 2nd table I get 36 rows as the 2nd table only has 36 rows that match the first table. How do I go about getting the 37 rows back with a Null result for the row that was not matched?



      Here is the query that I have so far



      SELECT 
      tblReps.[sName] AS 'RepName',
      tblReps.sNote AS 'Type',
      RIGHT(CAST(tblDaily.sDateAndTimeStart AS smalldatetime), 8) AS 'DayStarted'

      FROM
      [tblRepresentatives] AS tblReps

      FULL OUTER JOIN
      tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode

      WHERE
      tblDaily.sDate = CAST(GETDATE() AS DATE)
      AND tblReps.[sActive] = 'True'






      sql-server






      share|improve this question







      New contributor



      Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share|improve this question







      New contributor



      Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share|improve this question




      share|improve this question






      New contributor



      Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      asked May 27 at 13:06









      Mark BlackburnMark Blackburn

      182




      182




      New contributor



      Mark Blackburn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




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      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes


















          4














          First of all, the correct type of join to use in this case is a left join:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          ...


          In your specific case, you could still use FULL because this condition in WHERE would turn it into a left join anyway:



          tblReps.[sActive] = 'True'


          But it is better to express the intent accurately.



          The same effect that turns your full join into a left join is actually responsible for the missing 37th row that you expected. More specifically, this other WHERE condition:



          tblDaily.sDate = CAST(GETDATE() AS DATE)


          transforms your join further into an inner join. That is why the 37th row is missing from the output.



          The reason for that happening is this. The FROM clause returns a null in tblDaily.sDate for the unmatched row. Because the WHERE clause logically executes after the FROM, the above-mentioned predicate excludes the unmatched row, since NULL = CAST(GETDATE() AS DATE) does not evaluate to True.



          What you need to do instead is move the sDate condition to the ON subclause:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          AND tblDaily.sDate = CAST(GETDATE() AS DATE)

          WHERE
          tblReps.[sActive] = 'True'


          That way the right-hand side of the join is filtered on tblDaily.sDate = CAST(GETDATE() AS DATE) before the join takes place. Consequently, the query will return the expected 37 rows from tblReps complemented either with matching data from tblDaily or with nulls.






          share|improve this answer

























          • Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

            – Mark Blackburn
            May 27 at 14:26











          Your Answer








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          1 Answer
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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          4














          First of all, the correct type of join to use in this case is a left join:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          ...


          In your specific case, you could still use FULL because this condition in WHERE would turn it into a left join anyway:



          tblReps.[sActive] = 'True'


          But it is better to express the intent accurately.



          The same effect that turns your full join into a left join is actually responsible for the missing 37th row that you expected. More specifically, this other WHERE condition:



          tblDaily.sDate = CAST(GETDATE() AS DATE)


          transforms your join further into an inner join. That is why the 37th row is missing from the output.



          The reason for that happening is this. The FROM clause returns a null in tblDaily.sDate for the unmatched row. Because the WHERE clause logically executes after the FROM, the above-mentioned predicate excludes the unmatched row, since NULL = CAST(GETDATE() AS DATE) does not evaluate to True.



          What you need to do instead is move the sDate condition to the ON subclause:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          AND tblDaily.sDate = CAST(GETDATE() AS DATE)

          WHERE
          tblReps.[sActive] = 'True'


          That way the right-hand side of the join is filtered on tblDaily.sDate = CAST(GETDATE() AS DATE) before the join takes place. Consequently, the query will return the expected 37 rows from tblReps complemented either with matching data from tblDaily or with nulls.






          share|improve this answer

























          • Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

            – Mark Blackburn
            May 27 at 14:26















          4














          First of all, the correct type of join to use in this case is a left join:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          ...


          In your specific case, you could still use FULL because this condition in WHERE would turn it into a left join anyway:



          tblReps.[sActive] = 'True'


          But it is better to express the intent accurately.



          The same effect that turns your full join into a left join is actually responsible for the missing 37th row that you expected. More specifically, this other WHERE condition:



          tblDaily.sDate = CAST(GETDATE() AS DATE)


          transforms your join further into an inner join. That is why the 37th row is missing from the output.



          The reason for that happening is this. The FROM clause returns a null in tblDaily.sDate for the unmatched row. Because the WHERE clause logically executes after the FROM, the above-mentioned predicate excludes the unmatched row, since NULL = CAST(GETDATE() AS DATE) does not evaluate to True.



          What you need to do instead is move the sDate condition to the ON subclause:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          AND tblDaily.sDate = CAST(GETDATE() AS DATE)

          WHERE
          tblReps.[sActive] = 'True'


          That way the right-hand side of the join is filtered on tblDaily.sDate = CAST(GETDATE() AS DATE) before the join takes place. Consequently, the query will return the expected 37 rows from tblReps complemented either with matching data from tblDaily or with nulls.






          share|improve this answer

























          • Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

            – Mark Blackburn
            May 27 at 14:26













          4












          4








          4







          First of all, the correct type of join to use in this case is a left join:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          ...


          In your specific case, you could still use FULL because this condition in WHERE would turn it into a left join anyway:



          tblReps.[sActive] = 'True'


          But it is better to express the intent accurately.



          The same effect that turns your full join into a left join is actually responsible for the missing 37th row that you expected. More specifically, this other WHERE condition:



          tblDaily.sDate = CAST(GETDATE() AS DATE)


          transforms your join further into an inner join. That is why the 37th row is missing from the output.



          The reason for that happening is this. The FROM clause returns a null in tblDaily.sDate for the unmatched row. Because the WHERE clause logically executes after the FROM, the above-mentioned predicate excludes the unmatched row, since NULL = CAST(GETDATE() AS DATE) does not evaluate to True.



          What you need to do instead is move the sDate condition to the ON subclause:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          AND tblDaily.sDate = CAST(GETDATE() AS DATE)

          WHERE
          tblReps.[sActive] = 'True'


          That way the right-hand side of the join is filtered on tblDaily.sDate = CAST(GETDATE() AS DATE) before the join takes place. Consequently, the query will return the expected 37 rows from tblReps complemented either with matching data from tblDaily or with nulls.






          share|improve this answer















          First of all, the correct type of join to use in this case is a left join:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          ...


          In your specific case, you could still use FULL because this condition in WHERE would turn it into a left join anyway:



          tblReps.[sActive] = 'True'


          But it is better to express the intent accurately.



          The same effect that turns your full join into a left join is actually responsible for the missing 37th row that you expected. More specifically, this other WHERE condition:



          tblDaily.sDate = CAST(GETDATE() AS DATE)


          transforms your join further into an inner join. That is why the 37th row is missing from the output.



          The reason for that happening is this. The FROM clause returns a null in tblDaily.sDate for the unmatched row. Because the WHERE clause logically executes after the FROM, the above-mentioned predicate excludes the unmatched row, since NULL = CAST(GETDATE() AS DATE) does not evaluate to True.



          What you need to do instead is move the sDate condition to the ON subclause:



          ...
          FROM
          [tblRepresentatives] AS tblReps

          LEFT OUTER JOIN
          tblDailyWorkingTime AS tblDaily ON tblDaily.sRepresentativeCode = tblReps.sCode
          AND tblDaily.sDate = CAST(GETDATE() AS DATE)

          WHERE
          tblReps.[sActive] = 'True'


          That way the right-hand side of the join is filtered on tblDaily.sDate = CAST(GETDATE() AS DATE) before the join takes place. Consequently, the query will return the expected 37 rows from tblReps complemented either with matching data from tblDaily or with nulls.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited May 27 at 16:13

























          answered May 27 at 13:39









          Andriy MAndriy M

          16.6k63777




          16.6k63777












          • Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

            – Mark Blackburn
            May 27 at 14:26

















          • Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

            – Mark Blackburn
            May 27 at 14:26
















          Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

          – Mark Blackburn
          May 27 at 14:26





          Thank you, Andriy that explanation was very helpful and makes sense to me. I have tested and I am now getting the expected result.

          – Mark Blackburn
          May 27 at 14:26










          Mark Blackburn is a new contributor. Be nice, and check out our Code of Conduct.









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          Mark Blackburn is a new contributor. Be nice, and check out our Code of Conduct.











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