How to extract lower and upper bound in numeric format from a confidence interval string?How can I plot data with confidence intervals?R - Bootstrapped Confidence Interval - Obtain Parameters of Upper and Lower BoundsHow to display several bootstrap confidence intervals on one plotHow can confidence intervals be numerically visualized in corrplot()?How to compute confidence Interval of the fitted value via nls()rAmCharts Scattered plot with Upper and lower confidence interval around Fitted valuesextract confidence intervals from binomial test in Rhow to add confidence interval as coloured area to a boxplot of predicted values in ggplot2?How to extract values of confidence interval from ggplot2 stat summary in R?Plotting a ggplot() when having the confidence interval upper and lower values
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How to extract lower and upper bound in numeric format from a confidence interval string?
How can I plot data with confidence intervals?R - Bootstrapped Confidence Interval - Obtain Parameters of Upper and Lower BoundsHow to display several bootstrap confidence intervals on one plotHow can confidence intervals be numerically visualized in corrplot()?How to compute confidence Interval of the fitted value via nls()rAmCharts Scattered plot with Upper and lower confidence interval around Fitted valuesextract confidence intervals from binomial test in Rhow to add confidence interval as coloured area to a boxplot of predicted values in ggplot2?How to extract values of confidence interval from ggplot2 stat summary in R?Plotting a ggplot() when having the confidence interval upper and lower values
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Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
r
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked May 27 at 12:31
FatetaFateta
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked May 27 at 12:31
FatetaFateta
826
asked May 27 at 12:31
FatetaFateta
826
826
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Fateta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
6 Answers
6
active
oldest
votes
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
24.5k92345
add a comment |
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
21018
add a comment |
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment |
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
Thank you all!
answered May 27 at 13:22
FatetaFateta
826
add a comment |
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
add a comment |
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
816316
add a comment |
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
24.5k92345
add a comment |
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
24.5k92345
add a comment |
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
24.5k92345
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
24.5k92345
edited May 27 at 12:45
answered May 27 at 12:41
G5WG5W
24.5k92345
answered May 27 at 12:41
G5WG5W
24.5k92345
answered May 27 at 12:41
G5WG5W
24.5k92345
24.5k92345
add a comment |
add a comment |
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
21018
add a comment |
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
21018
add a comment |
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
21018
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
21018
answered May 27 at 12:52
pzhaopzhao
21018
answered May 27 at 12:52
pzhaopzhao
21018
answered May 27 at 12:52
pzhaopzhao
21018
21018
add a comment |
add a comment |
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment |
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment |
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
edited May 27 at 12:58
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
answered May 27 at 12:49
tmfmnktmfmnk
6,3861821
6,3861821
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment |
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment |
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
Thank you all!
answered May 27 at 13:22
FatetaFateta
826
add a comment |
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
Thank you all!
answered May 27 at 13:22
FatetaFateta
826
add a comment |
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
Thank you all!
answered May 27 at 13:22
FatetaFateta
826
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
Thank you all!
answered May 27 at 13:22
FatetaFateta
826
edited May 28 at 6:18
answered May 27 at 13:22
FatetaFateta
826
answered May 27 at 13:22
FatetaFateta
826
answered May 27 at 13:22
FatetaFateta
826
826
add a comment |
add a comment |
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
add a comment |
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
add a comment |
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
edited May 27 at 12:45
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
answered May 27 at 12:38
demarsylvaindemarsylvain
1,2722621
1,2722621
add a comment |
add a comment |
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
816316
add a comment |
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
816316
add a comment |
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
816316
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
816316
answered May 27 at 14:12
FinoFino
816316
answered May 27 at 14:12
FinoFino
816316
answered May 27 at 14:12
FinoFino
816316
816316
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