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How do I use JSON.generator to generate an unnamed array?
How do I generate a random string?Scheduled Apex Class Testing IssueJson Generator Object within ArraySystem.JSONException: Unexpected character ('}' (code 125))How to deserialize JSON to sObject?JSONError - System.JSONException: Can not start an object, expecting field nameAPEX Deserializing/Parsing RESTful JSON Webservice ResponseHow to grab everything between start of substring and and of text?Apex Quick Start — How do I use the Book?JSON generation in apex batch - how to correctly configure cc in email sending
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I'm trying to generate:
"["hello" : "world"]"
gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();
Throws the error:System.JSONException: Can not start an array, expecting field name
But the array in my example does not have a field name?
apex
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
add a comment |
I'm trying to generate:
"["hello" : "world"]"
gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();
Throws the error:System.JSONException: Can not start an array, expecting field name
But the array in my example does not have a field name?
apex
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
add a comment |
I'm trying to generate:
"["hello" : "world"]"
gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();
Throws the error:System.JSONException: Can not start an array, expecting field name
But the array in my example does not have a field name?
apex
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
I'm trying to generate:
"["hello" : "world"]"
gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();
Throws the error:System.JSONException: Can not start an array, expecting field name
But the array in my example does not have a field name?
apex
apex
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
asked Jul 29 at 16:40
muchaviemuchavie
763 bronze badges
763 bronze badges
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.
gen.writeStartObject();
// output:
// remove this line
gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart
gen.writeStartObject();
// output:
gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild
gen.writeEndObject();
// output:
gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd
gen.writeEndObject();
// output:
// remove this line
Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:
String payload = JSON.serialize(new List<Object>
new Map<String, String> 'hello' => 'world'
);
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
1
Also itswriteStartArrayandwriteEndArray
– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.
gen.writeStartObject();
// output:
// remove this line
gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart
gen.writeStartObject();
// output:
gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild
gen.writeEndObject();
// output:
gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd
gen.writeEndObject();
// output:
// remove this line
Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:
String payload = JSON.serialize(new List<Object>
new Map<String, String> 'hello' => 'world'
);
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
1
Also itswriteStartArrayandwriteEndArray
– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
add a comment |
Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.
gen.writeStartObject();
// output:
// remove this line
gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart
gen.writeStartObject();
// output:
gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild
gen.writeEndObject();
// output:
gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd
gen.writeEndObject();
// output:
// remove this line
Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:
String payload = JSON.serialize(new List<Object>
new Map<String, String> 'hello' => 'world'
);
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
1
Also itswriteStartArrayandwriteEndArray
– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
add a comment |
Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.
gen.writeStartObject();
// output:
// remove this line
gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart
gen.writeStartObject();
// output:
gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild
gen.writeEndObject();
// output:
gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd
gen.writeEndObject();
// output:
// remove this line
Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:
String payload = JSON.serialize(new List<Object>
new Map<String, String> 'hello' => 'world'
);
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.
gen.writeStartObject();
// output:
// remove this line
gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart
gen.writeStartObject();
// output:
gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild
gen.writeEndObject();
// output:
gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd
gen.writeEndObject();
// output:
// remove this line
Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:
String payload = JSON.serialize(new List<Object>
new Map<String, String> 'hello' => 'world'
);
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
edited Jul 29 at 17:32
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
answered Jul 29 at 16:44
Adrian Larson♦Adrian Larson
115k19 gold badges135 silver badges274 bronze badges
115k19 gold badges135 silver badges274 bronze badges
1
Also itswriteStartArrayandwriteEndArray
– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
add a comment |
1
Also itswriteStartArrayandwriteEndArray
– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
1
1
Also its
writeStartArray and writeEndArray– salesforce-sas
Jul 29 at 17:00
Also its
writeStartArray and writeEndArray– salesforce-sas
Jul 29 at 17:00
Thank you Adrian!
– muchavie
Jul 29 at 17:35
Thank you Adrian!
– muchavie
Jul 29 at 17:35
1
1
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
@muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
– Adrian Larson♦
Jul 29 at 17:38
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
I already upvoted it. I don't know why it didn't turn green.
– muchavie
Jul 31 at 13:53
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
Upvoting and accepting are completely different mechanisms. You have to click the little checkmark next to the answer to indicate that it has solved your problem.
– Adrian Larson♦
Jul 31 at 13:56
add a comment |
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