How do I design a circuit to convert a 100 mV and 50 Hz sine wave to a square wave? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Triangular waveform to square waveform circuitSquare wave / Sine wave is more audibleSine wave to square wave - Schmitt triggerWhat is the best way to get a sine wave from a square wave?How to build a circuit that generates a sine wave?High-current capable (±250A) AC power-supply, sine wave/square wave (±20V)Why sine wave not square wave?Sine to Square only with a MCUHow to check (with DIY methods) if an Inverter returns a Square or a Sine Wave?Need a circuit to convert 230V sine wave into 5V square waveSine to square wave converter

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How do I design a circuit to convert a 100 mV and 50 Hz sine wave to a square wave?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Triangular waveform to square waveform circuitSquare wave / Sine wave is more audibleSine wave to square wave - Schmitt triggerWhat is the best way to get a sine wave from a square wave?How to build a circuit that generates a sine wave?High-current capable (±250A) AC power-supply, sine wave/square wave (±20V)Why sine wave not square wave?Sine to Square only with a MCUHow to check (with DIY methods) if an Inverter returns a Square or a Sine Wave?Need a circuit to convert 230V sine wave into 5V square waveSine to square wave converter



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








7












$begingroup$


I have a sine wave of 100 mV and 50 Hz. I want to design a circuit that converts this sine wave into a square wave as shown in a figure.



Enter image description here






circuit-design sine square







share|improve this question









New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 2




    $begingroup$
    Possible duplicate of Triangular waveform to square waveform circuit
    $endgroup$
    – Eugene Sh.
    2 days ago










  • $begingroup$
    You would almost certainly want to add hysteresis to your solution for a low level low frequency application
    $endgroup$
    – sstobbe
    2 days ago










  • $begingroup$
    Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
    $endgroup$
    – analogsystemsrf
    2 days ago

















7












$begingroup$


I have a sine wave of 100 mV and 50 Hz. I want to design a circuit that converts this sine wave into a square wave as shown in a figure.



Enter image description here






circuit-design sine square







share|improve this question









New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 2




    $begingroup$
    Possible duplicate of Triangular waveform to square waveform circuit
    $endgroup$
    – Eugene Sh.
    2 days ago










  • $begingroup$
    You would almost certainly want to add hysteresis to your solution for a low level low frequency application
    $endgroup$
    – sstobbe
    2 days ago










  • $begingroup$
    Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
    $endgroup$
    – analogsystemsrf
    2 days ago













7












7








7


1



$begingroup$


I have a sine wave of 100 mV and 50 Hz. I want to design a circuit that converts this sine wave into a square wave as shown in a figure.



Enter image description here






circuit-design sine square







share|improve this question









New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I have a sine wave of 100 mV and 50 Hz. I want to design a circuit that converts this sine wave into a square wave as shown in a figure.



Enter image description here






circuit-design sine square




circuit-design sine square






share|improve this question









New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 2 days ago









Peter Mortensen

1,60031422




1,60031422






New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 2 days ago









UmangcernUmangcern

344




344




New contributor




Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Umangcern is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 2




    $begingroup$
    Possible duplicate of Triangular waveform to square waveform circuit
    $endgroup$
    – Eugene Sh.
    2 days ago










  • $begingroup$
    You would almost certainly want to add hysteresis to your solution for a low level low frequency application
    $endgroup$
    – sstobbe
    2 days ago










  • $begingroup$
    Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
    $endgroup$
    – analogsystemsrf
    2 days ago












  • 2




    $begingroup$
    Possible duplicate of Triangular waveform to square waveform circuit
    $endgroup$
    – Eugene Sh.
    2 days ago










  • $begingroup$
    You would almost certainly want to add hysteresis to your solution for a low level low frequency application
    $endgroup$
    – sstobbe
    2 days ago










  • $begingroup$
    Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
    $endgroup$
    – analogsystemsrf
    2 days ago







2




2




$begingroup$
Possible duplicate of Triangular waveform to square waveform circuit
$endgroup$
– Eugene Sh.
2 days ago




$begingroup$
Possible duplicate of Triangular waveform to square waveform circuit
$endgroup$
– Eugene Sh.
2 days ago












$begingroup$
You would almost certainly want to add hysteresis to your solution for a low level low frequency application
$endgroup$
– sstobbe
2 days ago




$begingroup$
You would almost certainly want to add hysteresis to your solution for a low level low frequency application
$endgroup$
– sstobbe
2 days ago












$begingroup$
Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
$endgroup$
– analogsystemsrf
2 days ago




$begingroup$
Does the OP want a 50% duty cycle? in which case, some zero-crossing is needed.
$endgroup$
– analogsystemsrf
2 days ago










1 Answer
1






active

oldest

votes


















17












$begingroup$

The easiest way to do this would be to use a comparator.



enter image description here



Picture taken from linked site



All you have to do is set your Vref level to where you want your square wave to trigger. When the sine wave crosses the Vref level, the comparator output will go high. As it approaches it again and goes below the Vref level, the comparator output goes low.



You will then get yourself a square wave.



Be aware the example shown in the graphic is of a non-inverting comparator. An inverting comparator works with the same principle, but the output is inverted






share|improve this answer









$endgroup$












  • $begingroup$
    The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
    $endgroup$
    – JimmyB
    2 days ago






  • 3




    $begingroup$
    @JimmyB Not if you pick a comparator that can handle a negative input voltage.
    $endgroup$
    – Hearth
    2 days ago










  • $begingroup$
    A diode for 100mV will be hard to find...
    $endgroup$
    – Eugene Sh.
    2 days ago











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









17












$begingroup$

The easiest way to do this would be to use a comparator.



enter image description here



Picture taken from linked site



All you have to do is set your Vref level to where you want your square wave to trigger. When the sine wave crosses the Vref level, the comparator output will go high. As it approaches it again and goes below the Vref level, the comparator output goes low.



You will then get yourself a square wave.



Be aware the example shown in the graphic is of a non-inverting comparator. An inverting comparator works with the same principle, but the output is inverted






share|improve this answer









$endgroup$












  • $begingroup$
    The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
    $endgroup$
    – JimmyB
    2 days ago






  • 3




    $begingroup$
    @JimmyB Not if you pick a comparator that can handle a negative input voltage.
    $endgroup$
    – Hearth
    2 days ago










  • $begingroup$
    A diode for 100mV will be hard to find...
    $endgroup$
    – Eugene Sh.
    2 days ago















17












$begingroup$

The easiest way to do this would be to use a comparator.



enter image description here



Picture taken from linked site



All you have to do is set your Vref level to where you want your square wave to trigger. When the sine wave crosses the Vref level, the comparator output will go high. As it approaches it again and goes below the Vref level, the comparator output goes low.



You will then get yourself a square wave.



Be aware the example shown in the graphic is of a non-inverting comparator. An inverting comparator works with the same principle, but the output is inverted






share|improve this answer









$endgroup$












  • $begingroup$
    The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
    $endgroup$
    – JimmyB
    2 days ago






  • 3




    $begingroup$
    @JimmyB Not if you pick a comparator that can handle a negative input voltage.
    $endgroup$
    – Hearth
    2 days ago










  • $begingroup$
    A diode for 100mV will be hard to find...
    $endgroup$
    – Eugene Sh.
    2 days ago













17












17








17





$begingroup$

The easiest way to do this would be to use a comparator.



enter image description here



Picture taken from linked site



All you have to do is set your Vref level to where you want your square wave to trigger. When the sine wave crosses the Vref level, the comparator output will go high. As it approaches it again and goes below the Vref level, the comparator output goes low.



You will then get yourself a square wave.



Be aware the example shown in the graphic is of a non-inverting comparator. An inverting comparator works with the same principle, but the output is inverted






share|improve this answer









$endgroup$



The easiest way to do this would be to use a comparator.



enter image description here



Picture taken from linked site



All you have to do is set your Vref level to where you want your square wave to trigger. When the sine wave crosses the Vref level, the comparator output will go high. As it approaches it again and goes below the Vref level, the comparator output goes low.



You will then get yourself a square wave.



Be aware the example shown in the graphic is of a non-inverting comparator. An inverting comparator works with the same principle, but the output is inverted







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









MCGMCG

6,84431851




6,84431851











  • $begingroup$
    The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
    $endgroup$
    – JimmyB
    2 days ago






  • 3




    $begingroup$
    @JimmyB Not if you pick a comparator that can handle a negative input voltage.
    $endgroup$
    – Hearth
    2 days ago










  • $begingroup$
    A diode for 100mV will be hard to find...
    $endgroup$
    – Eugene Sh.
    2 days ago
















  • $begingroup$
    The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
    $endgroup$
    – JimmyB
    2 days ago






  • 3




    $begingroup$
    @JimmyB Not if you pick a comparator that can handle a negative input voltage.
    $endgroup$
    – Hearth
    2 days ago










  • $begingroup$
    A diode for 100mV will be hard to find...
    $endgroup$
    – Eugene Sh.
    2 days ago















$begingroup$
The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
$endgroup$
– JimmyB
2 days ago




$begingroup$
The OP seems to want to cut off the negative half of the sine wave, so a diode may be needed at the input.
$endgroup$
– JimmyB
2 days ago




3




3




$begingroup$
@JimmyB Not if you pick a comparator that can handle a negative input voltage.
$endgroup$
– Hearth
2 days ago




$begingroup$
@JimmyB Not if you pick a comparator that can handle a negative input voltage.
$endgroup$
– Hearth
2 days ago












$begingroup$
A diode for 100mV will be hard to find...
$endgroup$
– Eugene Sh.
2 days ago




$begingroup$
A diode for 100mV will be hard to find...
$endgroup$
– Eugene Sh.
2 days ago










Umangcern is a new contributor. Be nice, and check out our Code of Conduct.









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Umangcern is a new contributor. Be nice, and check out our Code of Conduct.












Umangcern is a new contributor. Be nice, and check out our Code of Conduct.











Umangcern is a new contributor. Be nice, and check out our Code of Conduct.














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