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Loop in macOS not working

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5

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

5

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

share|improve this question

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 18 hours ago

Kusalananda♦

139k17259430

edited 18 hours ago

Kusalananda♦

139k17259430

asked 22 hours ago

spicyramenspicyramen

1284

New contributor

spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 22 hours ago

spicyramenspicyramen

1284

2 Answers
2

active

oldest

votes

5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 19 hours ago

answered 21 hours ago

Jakub JindraJakub Jindra

571413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  21 hours ago
  

  
  
  
  

add a comment | 

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 18 hours ago

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  18 hours ago
  
  

  
  
  
  

add a comment | 

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5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 19 hours ago

answered 21 hours ago

Jakub JindraJakub Jindra

571413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  21 hours ago
  

  
  
  
  

add a comment | 

5

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 19 hours ago

answered 21 hours ago

Jakub JindraJakub Jindra

571413

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  21 hours ago
  

  
  
  
  

add a comment | 

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 19 hours ago

answered 21 hours ago

Jakub JindraJakub Jindra

571413

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited 19 hours ago

answered 21 hours ago

Jakub JindraJakub Jindra

571413

answered 21 hours ago

Jakub JindraJakub Jindra

571413

answered 21 hours ago

Jakub JindraJakub Jindra

571413

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 18 hours ago

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  18 hours ago
  
  

  
  
  
  

add a comment | 

6

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 18 hours ago

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  18 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  18 hours ago
  
  

  
  
  
  

add a comment | 

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited 18 hours ago

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

share|improve this answer

edited 18 hours ago

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430

answered 21 hours ago

Kusalananda♦Kusalananda

139k17259430