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How is it possible for this circuit to continue functioning correctly?
Why don't people tend to use voltage dividers or zeners in front of linear regulators3.7V to 9V DC to DC boost step-up converter design help!How to work with the MCP1702?Emitter follower regulator with sziklai pair, transistor heating up!How to know if my voltage regulator is still working or notNeed for 3.3V regulatorWhat could cause an LDO regulator to fail to regulate properly?Voltage regulator - unexpected voltage drop, is this normal?Cooling Methods for Voltage RegulatorsLM2937 Replacement/Upgrade Thermal issues
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$begingroup$
A circuit uses the RN5RT33A voltage regulator to generate the 3.3V rail.
According to its datasheet the abs. max output current is 150mA, typical output current is 60mA.
There's an add-on board that feeds on that 3.3V rail and draws additional current from the regulator. I've measured the approx. current used by the add-on board and it was why of 310mA max and around 200mA most of the time.
How is that possible? It seems that would exceed the ratings of the regulator, however the circuit seems to be working fine.
voltage-regulator
asked May 8 at 15:49
user733606user733606
98111
$endgroup$
|
show 2 more comments
$begingroup$
A circuit uses the RN5RT33A voltage regulator to generate the 3.3V rail.
According to its datasheet the abs. max output current is 150mA, typical output current is 60mA.
There's an add-on board that feeds on that 3.3V rail and draws additional current from the regulator. I've measured the approx. current used by the add-on board and it was why of 310mA max and around 200mA most of the time.
How is that possible? It seems that would exceed the ratings of the regulator, however the circuit seems to be working fine.
voltage-regulator
asked May 8 at 15:49
user733606user733606
98111
$endgroup$
8
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
2
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
1
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
$endgroup$
– laptop2d
May 8 at 16:41
|
show 2 more comments
$begingroup$
A circuit uses the RN5RT33A voltage regulator to generate the 3.3V rail.
According to its datasheet the abs. max output current is 150mA, typical output current is 60mA.
There's an add-on board that feeds on that 3.3V rail and draws additional current from the regulator. I've measured the approx. current used by the add-on board and it was why of 310mA max and around 200mA most of the time.
How is that possible? It seems that would exceed the ratings of the regulator, however the circuit seems to be working fine.
voltage-regulator
asked May 8 at 15:49
user733606user733606
98111
$endgroup$
A circuit uses the RN5RT33A voltage regulator to generate the 3.3V rail.
According to its datasheet the abs. max output current is 150mA, typical output current is 60mA.
There's an add-on board that feeds on that 3.3V rail and draws additional current from the regulator. I've measured the approx. current used by the add-on board and it was why of 310mA max and around 200mA most of the time.
How is that possible? It seems that would exceed the ratings of the regulator, however the circuit seems to be working fine.
voltage-regulator
voltage-regulator
asked May 8 at 15:49
user733606user733606
98111
asked May 8 at 15:49
user733606user733606
98111
asked May 8 at 15:49
user733606user733606
98111
asked May 8 at 15:49
user733606user733606
98111
asked May 8 at 15:49
user733606user733606
98111
98111
8
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
2
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
1
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
$endgroup$
– laptop2d
May 8 at 16:41
|
show 2 more comments
8
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
2
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
1
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
$endgroup$
– laptop2d
May 8 at 16:41
8
8
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
2
2
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
1
1
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
$endgroup$
– laptop2d
May 8 at 16:41
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
$endgroup$
– laptop2d
May 8 at 16:41
|
show 2 more comments
2 Answers
2
active
oldest
votes
$begingroup$
The value given in the datasheet as "absolute maximum" is the maximum value at which the manufacturer guarantees the device will not break. That doesn't mean it will break, just that it may break and if it does it's definitely your fault, so they're not legally liable for damages caused.
Most of the time, devices can survive conditions outside their absolute maximum, as long as they aren't too far outside it and don't stay outside it for too long. But you shouldn't depend on that, and you definitely shouldn't depend on them actually doing what they're meant to do under those conditions.
answered May 8 at 16:05
HearthHearth
5,66511342
$endgroup$
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
add a comment |
$begingroup$
@Hearth answers the question correctly, I just want to point out that on the RN5RT33A's datasheet it does say there is a "current limit circuit".
This will not limit the output current to a known value, merely that in case of a Vout short to ground the IC will only output 30mA of current in order to protect itself from immediate destruction.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
add a comment |
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2 Answers
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active
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
The value given in the datasheet as "absolute maximum" is the maximum value at which the manufacturer guarantees the device will not break. That doesn't mean it will break, just that it may break and if it does it's definitely your fault, so they're not legally liable for damages caused.
Most of the time, devices can survive conditions outside their absolute maximum, as long as they aren't too far outside it and don't stay outside it for too long. But you shouldn't depend on that, and you definitely shouldn't depend on them actually doing what they're meant to do under those conditions.
answered May 8 at 16:05
HearthHearth
5,66511342
$endgroup$
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
add a comment |
$begingroup$
The value given in the datasheet as "absolute maximum" is the maximum value at which the manufacturer guarantees the device will not break. That doesn't mean it will break, just that it may break and if it does it's definitely your fault, so they're not legally liable for damages caused.
Most of the time, devices can survive conditions outside their absolute maximum, as long as they aren't too far outside it and don't stay outside it for too long. But you shouldn't depend on that, and you definitely shouldn't depend on them actually doing what they're meant to do under those conditions.
answered May 8 at 16:05
HearthHearth
5,66511342
$endgroup$
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
add a comment |
$begingroup$
The value given in the datasheet as "absolute maximum" is the maximum value at which the manufacturer guarantees the device will not break. That doesn't mean it will break, just that it may break and if it does it's definitely your fault, so they're not legally liable for damages caused.
Most of the time, devices can survive conditions outside their absolute maximum, as long as they aren't too far outside it and don't stay outside it for too long. But you shouldn't depend on that, and you definitely shouldn't depend on them actually doing what they're meant to do under those conditions.
answered May 8 at 16:05
HearthHearth
5,66511342
$endgroup$
The value given in the datasheet as "absolute maximum" is the maximum value at which the manufacturer guarantees the device will not break. That doesn't mean it will break, just that it may break and if it does it's definitely your fault, so they're not legally liable for damages caused.
Most of the time, devices can survive conditions outside their absolute maximum, as long as they aren't too far outside it and don't stay outside it for too long. But you shouldn't depend on that, and you definitely shouldn't depend on them actually doing what they're meant to do under those conditions.
answered May 8 at 16:05
HearthHearth
5,66511342
edited May 8 at 16:41
answered May 8 at 16:05
HearthHearth
5,66511342
answered May 8 at 16:05
HearthHearth
5,66511342
answered May 8 at 16:05
HearthHearth
5,66511342
5,66511342
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
add a comment |
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Worse, it may not "break" instantly. It may break at 150.1 mA if left in that condition long enough. And you may not be around to put out the fire when it finally burns out.
$endgroup$
– scorpdaddy
May 8 at 16:12
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
$begingroup$
Good point, I should add that to the answer.
$endgroup$
– Hearth
May 8 at 16:41
add a comment |
$begingroup$
@Hearth answers the question correctly, I just want to point out that on the RN5RT33A's datasheet it does say there is a "current limit circuit".
This will not limit the output current to a known value, merely that in case of a Vout short to ground the IC will only output 30mA of current in order to protect itself from immediate destruction.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
add a comment |
$begingroup$
@Hearth answers the question correctly, I just want to point out that on the RN5RT33A's datasheet it does say there is a "current limit circuit".
This will not limit the output current to a known value, merely that in case of a Vout short to ground the IC will only output 30mA of current in order to protect itself from immediate destruction.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
add a comment |
$begingroup$
@Hearth answers the question correctly, I just want to point out that on the RN5RT33A's datasheet it does say there is a "current limit circuit".
This will not limit the output current to a known value, merely that in case of a Vout short to ground the IC will only output 30mA of current in order to protect itself from immediate destruction.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
@Hearth answers the question correctly, I just want to point out that on the RN5RT33A's datasheet it does say there is a "current limit circuit".
This will not limit the output current to a known value, merely that in case of a Vout short to ground the IC will only output 30mA of current in order to protect itself from immediate destruction.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered May 8 at 17:54
HatmanHatman
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered May 8 at 17:54
HatmanHatman
215
answered May 8 at 17:54
HatmanHatman
215
215
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Hatman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
add a comment |
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
I tried to find a datasheet for this thing and couldn't! Thanks for digging one up.
$endgroup$
– Hearth
May 8 at 19:13
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
$begingroup$
@Hearth i had to use a round about way to find it: i searched the part on octopart, then followed their links to a few distributors, and finally found the datasheet on Rochester Electronic's website.
$endgroup$
– Hatman
May 8 at 20:36
add a comment |
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8
$begingroup$
"Absolute maximum" doesn't mean they promise it will fail at that level. It means they don't promise it won't be damaged at that level.
$endgroup$
– The Photon
May 8 at 15:52
$begingroup$
@ThePhoton However it seems to me risky to be running over that, sometimes as much as twice that.
$endgroup$
– user733606
May 8 at 15:59
2
$begingroup$
Yes, it is risky. But you didn't ask if it was a good idea, you asked how it was possible.
$endgroup$
– Elliot Alderson
May 8 at 16:00
1
$begingroup$
@user733606, yes it's risky and you shouldn't do it. But there's no promise it will fail right away. It could appear to work for minutes or days or hours or weeks before failing.
$endgroup$
– The Photon
May 8 at 16:01
$begingroup$
Usually thermal death is the main cause of failure, if this had a heatsink or good thermal relief one could see it surviving past the absolute maximum ratings, which were probably tested with no heatsink.
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– laptop2d
May 8 at 16:41