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How to use structured binding in an array passed as arg to some function?
Using std NamespaceIs there a max array length limit in C++?Autocompletion in VimFunction passed as template argumentWhat is the copy-and-swap idiom?How do I use arrays in C++?Image Processing: Algorithm Improvement for 'Coca-Cola Can' Recognitionc++ passing Pointers into a function, for passing int arrays out of and into a functionReplacing a 32-bit loop counter with 64-bit introduces crazy performance deviationspassing character arrays to a functionStructure Binding : binding to public data members (inherited base class )
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I'm trying to decompose an array of 2 integers given to a function into x, y
It doesn't work when using int init[2] as a parameter. But it does when I change it to int (&init)[2].
vector<vector<State>> Search(vector<vector<State>> board,
int init[2], int goal[2])
auto [x, y] = init;
What does (&init) mean here? And why it doesn't work when using int init[2]?
c++ c++17
edited May 11 at 17:35
StoryTeller
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
add a comment |
I'm trying to decompose an array of 2 integers given to a function into x, y
It doesn't work when using int init[2] as a parameter. But it does when I change it to int (&init)[2].
vector<vector<State>> Search(vector<vector<State>> board,
int init[2], int goal[2])
auto [x, y] = init;
What does (&init) mean here? And why it doesn't work when using int init[2]?
c++ c++17
edited May 11 at 17:35
StoryTeller
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
Don't dousing namespace std;.
– Williham Totland
May 11 at 19:50
add a comment |
I'm trying to decompose an array of 2 integers given to a function into x, y
It doesn't work when using int init[2] as a parameter. But it does when I change it to int (&init)[2].
vector<vector<State>> Search(vector<vector<State>> board,
int init[2], int goal[2])
auto [x, y] = init;
What does (&init) mean here? And why it doesn't work when using int init[2]?
c++ c++17
edited May 11 at 17:35
StoryTeller
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
I'm trying to decompose an array of 2 integers given to a function into x, y
It doesn't work when using int init[2] as a parameter. But it does when I change it to int (&init)[2].
vector<vector<State>> Search(vector<vector<State>> board,
int init[2], int goal[2])
auto [x, y] = init;
What does (&init) mean here? And why it doesn't work when using int init[2]?
c++ c++17
c++ c++17
edited May 11 at 17:35
StoryTeller
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
edited May 11 at 17:35
StoryTeller
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
edited May 11 at 17:35
StoryTeller
108k16227290
edited May 11 at 17:35
StoryTeller
108k16227290
edited May 11 at 17:35
StoryTeller
108k16227290
108k16227290
asked May 11 at 17:10
BrunoBruno
14414
asked May 11 at 17:10
BrunoBruno
14414
asked May 11 at 17:10
BrunoBruno
14414
14414
Don't dousing namespace std;.
– Williham Totland
May 11 at 19:50
add a comment |
Don't dousing namespace std;.
– Williham Totland
May 11 at 19:50
Don't do
using namespace std;.– Williham Totland
May 11 at 19:50
Don't do
using namespace std;.– Williham Totland
May 11 at 19:50
add a comment |
1 Answer
1
active
oldest
votes
int (&init)[2] is a reference to an array of two integers. int init[2] as a function parameter is a leftover from C++'s C heritage. It doesn't declare the function as taking an array. The type of the parameter is adjusted to int* and all size information for an array being passed into the function is lost.
A function taking int init[2] can be called with an array of any size, on account of actually taking a pointer. It may even be passed nullptr. While a function taking int(&)[2] may only be given a valid array of two as an argument.
Since in the working version init refers to a int[2] object, structured bindings can work with that array object. But a decayed pointer cannot be the subject of structured bindings, because the static type information available only gives access to a single element being pointed at.
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
int (&init)[2] is a reference to an array of two integers. int init[2] as a function parameter is a leftover from C++'s C heritage. It doesn't declare the function as taking an array. The type of the parameter is adjusted to int* and all size information for an array being passed into the function is lost.
A function taking int init[2] can be called with an array of any size, on account of actually taking a pointer. It may even be passed nullptr. While a function taking int(&)[2] may only be given a valid array of two as an argument.
Since in the working version init refers to a int[2] object, structured bindings can work with that array object. But a decayed pointer cannot be the subject of structured bindings, because the static type information available only gives access to a single element being pointed at.
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
add a comment |
int (&init)[2] is a reference to an array of two integers. int init[2] as a function parameter is a leftover from C++'s C heritage. It doesn't declare the function as taking an array. The type of the parameter is adjusted to int* and all size information for an array being passed into the function is lost.
A function taking int init[2] can be called with an array of any size, on account of actually taking a pointer. It may even be passed nullptr. While a function taking int(&)[2] may only be given a valid array of two as an argument.
Since in the working version init refers to a int[2] object, structured bindings can work with that array object. But a decayed pointer cannot be the subject of structured bindings, because the static type information available only gives access to a single element being pointed at.
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
add a comment |
int (&init)[2] is a reference to an array of two integers. int init[2] as a function parameter is a leftover from C++'s C heritage. It doesn't declare the function as taking an array. The type of the parameter is adjusted to int* and all size information for an array being passed into the function is lost.
A function taking int init[2] can be called with an array of any size, on account of actually taking a pointer. It may even be passed nullptr. While a function taking int(&)[2] may only be given a valid array of two as an argument.
Since in the working version init refers to a int[2] object, structured bindings can work with that array object. But a decayed pointer cannot be the subject of structured bindings, because the static type information available only gives access to a single element being pointed at.
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
int (&init)[2] is a reference to an array of two integers. int init[2] as a function parameter is a leftover from C++'s C heritage. It doesn't declare the function as taking an array. The type of the parameter is adjusted to int* and all size information for an array being passed into the function is lost.
A function taking int init[2] can be called with an array of any size, on account of actually taking a pointer. It may even be passed nullptr. While a function taking int(&)[2] may only be given a valid array of two as an argument.
Since in the working version init refers to a int[2] object, structured bindings can work with that array object. But a decayed pointer cannot be the subject of structured bindings, because the static type information available only gives access to a single element being pointed at.
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
answered May 11 at 17:16
StoryTellerStoryTeller
108k16227290
108k16227290
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
add a comment |
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
1
1
Thanks!! I got it :)
– Bruno
May 11 at 17:25
Thanks!! I got it :)
– Bruno
May 11 at 17:25
add a comment |
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Don't do
using namespace std;.– Williham Totland
May 11 at 19:50