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How to use “regular expression” to separate specific strings in Oracle


Regular expression problemRegular Expression DifficultyHow to use SUBSTRING using REGEXP in MySQLRegular expression in a SQL case statementHow to Apply a Title-Case RegEx Condition for Object Names with Policy Based ManagementData Warehouse Design and Double DippingHow to port LTRIM from Oracle to SQL Server?Select Statement with RegEx Replace - DB2 9.7How to make a backup of an Oracle database that does not mess up the regular backup cycle?Compare The length of two string variables inside an Expression task in SSIS






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3















I have a string '(1:30,2:4,52:0,8:1)', and I need to use a regular expression to have this output:



field1 field2 level
1 30 1
2 4 2
52 0 3
8 1 4


The query I've wrote so far is:



select distinct trim(regexp_substr('1:30,2:4,52:0,8:1','[^:,]+',1,level)) repfield,level lvl
from dual
connect by regexp_substr('1:30,2:4,52:0,8:1', '[^:,]+', 1, level) is not null
order by lvl









share|improve this question



















  • 1





    If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

    – LogicalBranch
    Jul 14 at 18:54







  • 2





    Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

    – Peter Mortensen
    Jul 14 at 20:37






  • 1





    @LogicalBranch Yes. It's kind of like an id . you're right.

    – Pantea Tourang
    Jul 15 at 4:46

















3















I have a string '(1:30,2:4,52:0,8:1)', and I need to use a regular expression to have this output:



field1 field2 level
1 30 1
2 4 2
52 0 3
8 1 4


The query I've wrote so far is:



select distinct trim(regexp_substr('1:30,2:4,52:0,8:1','[^:,]+',1,level)) repfield,level lvl
from dual
connect by regexp_substr('1:30,2:4,52:0,8:1', '[^:,]+', 1, level) is not null
order by lvl









share|improve this question



















  • 1





    If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

    – LogicalBranch
    Jul 14 at 18:54







  • 2





    Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

    – Peter Mortensen
    Jul 14 at 20:37






  • 1





    @LogicalBranch Yes. It's kind of like an id . you're right.

    – Pantea Tourang
    Jul 15 at 4:46













3












3








3


1






I have a string '(1:30,2:4,52:0,8:1)', and I need to use a regular expression to have this output:



field1 field2 level
1 30 1
2 4 2
52 0 3
8 1 4


The query I've wrote so far is:



select distinct trim(regexp_substr('1:30,2:4,52:0,8:1','[^:,]+',1,level)) repfield,level lvl
from dual
connect by regexp_substr('1:30,2:4,52:0,8:1', '[^:,]+', 1, level) is not null
order by lvl









share|improve this question
















I have a string '(1:30,2:4,52:0,8:1)', and I need to use a regular expression to have this output:



field1 field2 level
1 30 1
2 4 2
52 0 3
8 1 4


The query I've wrote so far is:



select distinct trim(regexp_substr('1:30,2:4,52:0,8:1','[^:,]+',1,level)) repfield,level lvl
from dual
connect by regexp_substr('1:30,2:4,52:0,8:1', '[^:,]+', 1, level) is not null
order by lvl






oracle oracle-11g plsql regular-expression split






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jul 14 at 20:47









dezso

23.1k11 gold badges61 silver badges100 bronze badges




23.1k11 gold badges61 silver badges100 bronze badges










asked Jul 14 at 5:32









Pantea TourangPantea Tourang

54816 bronze badges




54816 bronze badges







  • 1





    If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

    – LogicalBranch
    Jul 14 at 18:54







  • 2





    Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

    – Peter Mortensen
    Jul 14 at 20:37






  • 1





    @LogicalBranch Yes. It's kind of like an id . you're right.

    – Pantea Tourang
    Jul 15 at 4:46












  • 1





    If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

    – LogicalBranch
    Jul 14 at 18:54







  • 2





    Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

    – Peter Mortensen
    Jul 14 at 20:37






  • 1





    @LogicalBranch Yes. It's kind of like an id . you're right.

    – Pantea Tourang
    Jul 15 at 4:46







1




1





If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

– LogicalBranch
Jul 14 at 18:54






If you don't mind me asking, what does the level column mean? Is it an id? E.G: row 1 = level 1, row 2 = level 2, row n = level n?

– LogicalBranch
Jul 14 at 18:54





2




2





Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

– Peter Mortensen
Jul 14 at 20:37





Isn't there a convention of using upper case for the SQL keywords (SELECT, FROM, WHERE, etc.)?

– Peter Mortensen
Jul 14 at 20:37




1




1





@LogicalBranch Yes. It's kind of like an id . you're right.

– Pantea Tourang
Jul 15 at 4:46





@LogicalBranch Yes. It's kind of like an id . you're right.

– Pantea Tourang
Jul 15 at 4:46










2 Answers
2






active

oldest

votes


















4














Simple method:



col field1 format a6
col field2 format a6
col lvl format a3
variable B1 varchar2(32);
exec :B1 := '1:30,2:4,52:0,8:1';
select
regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 1) field1,
regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 2) field2,
level lvl from dual
connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

FIELD1 FIELD2 LVL
------ ------ ---
1 30 1
2 4 2
52 2 3
8 1 4


Or with fewer regexp_substr calls:



col field1 format a6
col field2 format a6
col lvl format a3
variable B1 varchar2(32);
exec :B1 := '1:30,2:4,52:0,8:1';
select
regexp_substr(:B1, '[^:,]+', 1, level*2 - 1 ) field1,
regexp_substr(:B1, '[^:,]+', 1, level*2) field2,
level lvl from dual
connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

FIELD1 FIELD2 LVL
------ ------ ---
1 30 1
2 4 2
52 0 3
8 1 4





share|improve this answer


















  • 1





    I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

    – Pantea Tourang
    Jul 14 at 10:07







  • 2





    @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

    – Balazs Papp
    Jul 14 at 10:40



















3














with cte as
( select distinct trim(regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level)) repfield,
level lvl
from dual
connect by regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level) is not null
order by lvl)
select
SUBSTR(repfield,1,instr(repfield , ':')-1) AS Field1,
SUBSTR(repfield,instr(repfield,':')+1,length(repfield)) as field2,
lvl
from cte


Thanks for you're answer. I came to another way to solve this. I could not use regular expressions (I did not have enough information) so i used SUBSTR and INSTR instead






share|improve this answer

























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Simple method:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 1) field1,
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 2 3
    8 1 4


    Or with fewer regexp_substr calls:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(:B1, '[^:,]+', 1, level*2 - 1 ) field1,
    regexp_substr(:B1, '[^:,]+', 1, level*2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 0 3
    8 1 4





    share|improve this answer


















    • 1





      I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

      – Pantea Tourang
      Jul 14 at 10:07







    • 2





      @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

      – Balazs Papp
      Jul 14 at 10:40
















    4














    Simple method:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 1) field1,
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 2 3
    8 1 4


    Or with fewer regexp_substr calls:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(:B1, '[^:,]+', 1, level*2 - 1 ) field1,
    regexp_substr(:B1, '[^:,]+', 1, level*2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 0 3
    8 1 4





    share|improve this answer


















    • 1





      I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

      – Pantea Tourang
      Jul 14 at 10:07







    • 2





      @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

      – Balazs Papp
      Jul 14 at 10:40














    4












    4








    4







    Simple method:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 1) field1,
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 2 3
    8 1 4


    Or with fewer regexp_substr calls:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(:B1, '[^:,]+', 1, level*2 - 1 ) field1,
    regexp_substr(:B1, '[^:,]+', 1, level*2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 0 3
    8 1 4





    share|improve this answer













    Simple method:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 1) field1,
    regexp_substr(regexp_substr(:B1, '[^,]+', 1, level), '[^:]+', 2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 2 3
    8 1 4


    Or with fewer regexp_substr calls:



    col field1 format a6
    col field2 format a6
    col lvl format a3
    variable B1 varchar2(32);
    exec :B1 := '1:30,2:4,52:0,8:1';
    select
    regexp_substr(:B1, '[^:,]+', 1, level*2 - 1 ) field1,
    regexp_substr(:B1, '[^:,]+', 1, level*2) field2,
    level lvl from dual
    connect by regexp_substr(:B1, '[^,]+', 1, level) is not null;

    FIELD1 FIELD2 LVL
    ------ ------ ---
    1 30 1
    2 4 2
    52 0 3
    8 1 4






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jul 14 at 8:49









    Balazs PappBalazs Papp

    28.4k2 gold badges10 silver badges32 bronze badges




    28.4k2 gold badges10 silver badges32 bronze badges







    • 1





      I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

      – Pantea Tourang
      Jul 14 at 10:07







    • 2





      @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

      – Balazs Papp
      Jul 14 at 10:40













    • 1





      I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

      – Pantea Tourang
      Jul 14 at 10:07







    • 2





      @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

      – Balazs Papp
      Jul 14 at 10:40








    1




    1





    I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

    – Pantea Tourang
    Jul 14 at 10:07






    I'm using Oracle 11-g and it gives me this error : Invalid sql statement . Would you mind editing your answer please?

    – Pantea Tourang
    Jul 14 at 10:07





    2




    2





    @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

    – Balazs Papp
    Jul 14 at 10:40






    @PanteaTourang There is nothing to edit. The above works fine in 11g as well. The error is thrown most likely by your client handling the statements differently. Use SQL*Plus and Oracle SQL Developer. Anything else is suboptimal. The above is from SQL Developer 19.1.

    – Balazs Papp
    Jul 14 at 10:40














    3














    with cte as
    ( select distinct trim(regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level)) repfield,
    level lvl
    from dual
    connect by regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level) is not null
    order by lvl)
    select
    SUBSTR(repfield,1,instr(repfield , ':')-1) AS Field1,
    SUBSTR(repfield,instr(repfield,':')+1,length(repfield)) as field2,
    lvl
    from cte


    Thanks for you're answer. I came to another way to solve this. I could not use regular expressions (I did not have enough information) so i used SUBSTR and INSTR instead






    share|improve this answer



























      3














      with cte as
      ( select distinct trim(regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level)) repfield,
      level lvl
      from dual
      connect by regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level) is not null
      order by lvl)
      select
      SUBSTR(repfield,1,instr(repfield , ':')-1) AS Field1,
      SUBSTR(repfield,instr(repfield,':')+1,length(repfield)) as field2,
      lvl
      from cte


      Thanks for you're answer. I came to another way to solve this. I could not use regular expressions (I did not have enough information) so i used SUBSTR and INSTR instead






      share|improve this answer

























        3












        3








        3







        with cte as
        ( select distinct trim(regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level)) repfield,
        level lvl
        from dual
        connect by regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level) is not null
        order by lvl)
        select
        SUBSTR(repfield,1,instr(repfield , ':')-1) AS Field1,
        SUBSTR(repfield,instr(repfield,':')+1,length(repfield)) as field2,
        lvl
        from cte


        Thanks for you're answer. I came to another way to solve this. I could not use regular expressions (I did not have enough information) so i used SUBSTR and INSTR instead






        share|improve this answer













        with cte as
        ( select distinct trim(regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level)) repfield,
        level lvl
        from dual
        connect by regexp_substr('1:30,2:4,52:0,8:1,90:54', '[^,]+', 1, level) is not null
        order by lvl)
        select
        SUBSTR(repfield,1,instr(repfield , ':')-1) AS Field1,
        SUBSTR(repfield,instr(repfield,':')+1,length(repfield)) as field2,
        lvl
        from cte


        Thanks for you're answer. I came to another way to solve this. I could not use regular expressions (I did not have enough information) so i used SUBSTR and INSTR instead







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jul 14 at 10:03









        Pantea TourangPantea Tourang

        54816 bronze badges




        54816 bronze badges



























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