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/bin/ls sorts differently than just ls


Why does OS X Lion's terminal treat the PS1 prompt codes differently than Snow Leopard?Associating a renamed executable with our application fails on command line in WindowsWindows “tree” command sorts randomlyWhat is the different between “sudo su” and “sudo bash”?Kali Linux: Renaming files in binFile sorting confusionwhat is `ssh-agent bin/bash` and why I have to `ssh-add` everytimeusing awk on only files which START with 'xyz'SSH executes the command differentlyWhy does symlink to VLC break but but .bash_profile alias works?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








20















$ ls |sort
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm
xyz-0.0.1-1554323568.rpm

$ /bin/ls |sort
xyz-0.0.1-1554323568.rpm
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm

$ which ls
alias ls='/bin/ls --color'
/bin/ls


Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?










share|improve this question

















  • 1





    To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

    – Hastur
    2 days ago







  • 1





    The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

    – Basic
    2 days ago


















20















$ ls |sort
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm
xyz-0.0.1-1554323568.rpm

$ /bin/ls |sort
xyz-0.0.1-1554323568.rpm
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm

$ which ls
alias ls='/bin/ls --color'
/bin/ls


Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?










share|improve this question

















  • 1





    To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

    – Hastur
    2 days ago







  • 1





    The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

    – Basic
    2 days ago














20












20








20


3






$ ls |sort
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm
xyz-0.0.1-1554323568.rpm

$ /bin/ls |sort
xyz-0.0.1-1554323568.rpm
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm

$ which ls
alias ls='/bin/ls --color'
/bin/ls


Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?










share|improve this question














$ ls |sort
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm
xyz-0.0.1-1554323568.rpm

$ /bin/ls |sort
xyz-0.0.1-1554323568.rpm
xyz-0.0.1-1554490900.rpm
xyz-0.0.1-1554745305.rpm
xyz-0.0.1-1554751021.rpm
xyz-0.0.1-1555513460.rpm
xyz-0.0.1-1555951745.rpm

$ which ls
alias ls='/bin/ls --color'
/bin/ls


Note that the sorting is different between the two commands (ls |sort results in incorrect sorting). This must be due to the color flag, but why?







linux command-line bash unix






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Apr 22 at 18:31









Josh M.Josh M.

75051329




75051329







  • 1





    To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

    – Hastur
    2 days ago







  • 1





    The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

    – Basic
    2 days ago













  • 1





    To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

    – Hastur
    2 days ago







  • 1





    The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

    – Basic
    2 days ago








1




1





To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

– Hastur
2 days ago






To sort the output of ls, in many cases, you may found useful to specify directly the -v option: ls -v . Better to avoid the deprecated and risky parsing of its output... In many modern distributions the alias of ls is directly set to /bin/ls --color=auto, as they suggest you in an answer.

– Hastur
2 days ago





1




1





The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

– Basic
2 days ago






The thing you're missing is how ANSI colour codes are signalled in a terminal. I'm not sure if it's constant or varies between terminals, but for me red can be triggered by printing 33[91m. Once you imagine the colour codes that are output by ls (normally consumed by the terminal), you can see why your sort would break (and then, the terminal strips them out so you can't see why the sort broke). I'm guessing the results were grouped by colour, then sorted by name?

– Basic
2 days ago











2 Answers
2






active

oldest

votes


















23














Do:



/bin/ls --color > file1
/bin/ls > file2


and compare content, you'll see the difference.



Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).






share|improve this answer


















  • 15





    @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

    – Kamil Maciorowski
    Apr 22 at 19:43






  • 6





    @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

    – John1024
    Apr 22 at 19:46






  • 5





    @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

    – Freddy
    Apr 22 at 19:58







  • 10





    Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

    – John1024
    Apr 22 at 20:00






  • 1





    How does this answer answer the OP's question?

    – pts
    yesterday


















25














In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
of the non-colored output. The other lines are sorted equally.



If we have at a look at the colored escape codes (non-sorted), we can see that the first
line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).



$ /bin/ls --color xyz* | cat -A
^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$
^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$
^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$
^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$
^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$
^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$





share|improve this answer























    Your Answer








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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    23














    Do:



    /bin/ls --color > file1
    /bin/ls > file2


    and compare content, you'll see the difference.



    Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).






    share|improve this answer


















    • 15





      @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

      – Kamil Maciorowski
      Apr 22 at 19:43






    • 6





      @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

      – John1024
      Apr 22 at 19:46






    • 5





      @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

      – Freddy
      Apr 22 at 19:58







    • 10





      Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

      – John1024
      Apr 22 at 20:00






    • 1





      How does this answer answer the OP's question?

      – pts
      yesterday















    23














    Do:



    /bin/ls --color > file1
    /bin/ls > file2


    and compare content, you'll see the difference.



    Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).






    share|improve this answer


















    • 15





      @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

      – Kamil Maciorowski
      Apr 22 at 19:43






    • 6





      @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

      – John1024
      Apr 22 at 19:46






    • 5





      @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

      – Freddy
      Apr 22 at 19:58







    • 10





      Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

      – John1024
      Apr 22 at 20:00






    • 1





      How does this answer answer the OP's question?

      – pts
      yesterday













    23












    23








    23







    Do:



    /bin/ls --color > file1
    /bin/ls > file2


    and compare content, you'll see the difference.



    Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).






    share|improve this answer













    Do:



    /bin/ls --color > file1
    /bin/ls > file2


    and compare content, you'll see the difference.



    Aliasing ls to /bin/ls --color=auto is likely better idea, it will stop ls from using color codes when not writing directly to terminal (like when piping to next program or writing to a file).







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Apr 22 at 18:44









    TomekTomek

    62956




    62956







    • 15





      @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

      – Kamil Maciorowski
      Apr 22 at 19:43






    • 6





      @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

      – John1024
      Apr 22 at 19:46






    • 5





      @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

      – Freddy
      Apr 22 at 19:58







    • 10





      Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

      – John1024
      Apr 22 at 20:00






    • 1





      How does this answer answer the OP's question?

      – pts
      yesterday












    • 15





      @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

      – Kamil Maciorowski
      Apr 22 at 19:43






    • 6





      @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

      – John1024
      Apr 22 at 19:46






    • 5





      @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

      – Freddy
      Apr 22 at 19:58







    • 10





      Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

      – John1024
      Apr 22 at 20:00






    • 1





      How does this answer answer the OP's question?

      – pts
      yesterday







    15




    15





    @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

    – Kamil Maciorowski
    Apr 22 at 19:43





    @JoshM. Well, sorting should be done by ls itself, if possible. Sorting with sort is parsing, not recommended in general.

    – Kamil Maciorowski
    Apr 22 at 19:43




    6




    6





    @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

    – John1024
    Apr 22 at 19:46





    @JoshM., rather than using /bin/ls, change your alias to what Tomak suggested and you will get the better behavior automatically.

    – John1024
    Apr 22 at 19:46




    5




    5





    @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

    – Freddy
    Apr 22 at 19:58






    @JoshM. You can also use ls for an unaliased ls or command ls for /bin/ls.

    – Freddy
    Apr 22 at 19:58





    10




    10





    Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

    – John1024
    Apr 22 at 20:00





    Yes, @Freddy, very true. But, using alias ls='/bin/ls --color' is just a recipe for trouble.

    – John1024
    Apr 22 at 20:00




    1




    1





    How does this answer answer the OP's question?

    – pts
    yesterday





    How does this answer answer the OP's question?

    – pts
    yesterday













    25














    In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
    of the non-colored output. The other lines are sorted equally.



    If we have at a look at the colored escape codes (non-sorted), we can see that the first
    line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).



    $ /bin/ls --color xyz* | cat -A
    ^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$
    ^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$
    ^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$
    ^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$
    ^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$
    ^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$





    share|improve this answer



























      25














      In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
      of the non-colored output. The other lines are sorted equally.



      If we have at a look at the colored escape codes (non-sorted), we can see that the first
      line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).



      $ /bin/ls --color xyz* | cat -A
      ^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$
      ^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$
      ^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$
      ^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$
      ^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$
      ^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$





      share|improve this answer

























        25












        25








        25







        In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
        of the non-colored output. The other lines are sorted equally.



        If we have at a look at the colored escape codes (non-sorted), we can see that the first
        line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).



        $ /bin/ls --color xyz* | cat -A
        ^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$





        share|improve this answer













        In the sorted colored output ls|sort, we can see that the last line xyz-0.0.1-1554323568.rpm is the first line
        of the non-colored output. The other lines are sorted equally.



        If we have at a look at the colored escape codes (non-sorted), we can see that the first
        line starts with a different escape code ^[[0m. This is causing the wrong order when sorted (^[[01 before ^[[0m).



        $ /bin/ls --color xyz* | cat -A
        ^[[0m^[[01;31mxyz-0.0.1-1554323568.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554490900.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554745305.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1554751021.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1555513460.rpm^[[0m$
        ^[[01;31mxyz-0.0.1-1555951745.rpm^[[0m$






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Apr 22 at 19:49









        FreddyFreddy

        59019




        59019



























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