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How do I rename multiple files which have a slightly different extension?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

2

1

I have multiple files which all have a similar naming pattern like:

filename.jpegrandom number

I want to rename these files so that their extension is just .jpeg. How can I do this?

bash filenames rename

share|improve this question

edited Jul 28 at 16:15

Jeff Schaller♦

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asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please take a look at: What should I do when someone answers my question?
  
  – Cyrus
  Jul 28 at 17:49
  

  
  
  
  

add a comment | 

2

1

I have multiple files which all have a similar naming pattern like:

filename.jpegrandom number

I want to rename these files so that their extension is just .jpeg. How can I do this?

bash filenames rename

share|improve this question

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please take a look at: What should I do when someone answers my question?
  
  – Cyrus
  Jul 28 at 17:49
  

  
  
  
  

add a comment | 

I have multiple files which all have a similar naming pattern like:

filename.jpegrandom number

I want to rename these files so that their extension is just .jpeg. How can I do this?

bash filenames rename

share|improve this question

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

filename.jpegrandom number

share|improve this question

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

share|improve this question

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

edited Jul 28 at 16:15

Jeff Schaller♦

48.5k1111 gold badges7272 silver badges162162 bronze badges

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

asked Jul 28 at 6:33

nooby noobsonnooby noobson

1111 bronze badge

3 Answers
3

active

oldest

votes

6

If you have Larry Wall's perl rename

rename 's/[.]jpeg[0-9]*/.jpeg/' *.jpeg[0-9]*

if you have only the Util-Linux rename that won't work.

You could use a for loop in bash

for n in *.jpeg[0-9]*
do mv -i "$n" "$n%%.jpeg[0-9]*.jpeg"
done

$var%%pattern is a standard parameter expansion that expands to the value of var, with the (longest) trailing part matching pattern removed. So, if n is foo.jpeg123, $n%%.jpeg[0-9* is foo. (foo.jpeg1abc would also result in foo.)

share|improve this answer

edited Jul 28 at 16:18

ilkkachu

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answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could you please explain your answer a bit? (I'd personally like to understand the n%%). Thanks.
  
  – Biggybi
  Jul 28 at 10:56
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Biggybi, there.
  
  – ilkkachu
  Jul 28 at 16:18
  

  
  
  
  

add a comment | 

3

I'd recommend using zsh's zmv here which would guard against potential conflicts (like there being both a file.jpeg1 and file.jpeg2 files in the current directory) before doing any rename.

In zsh:

autoload zmv # best in ~/.zshrc
zmv -n '(*.jpeg)<->' '$1'

Where <-> (<x-y> number range matching here without boundaries) matches any sequence of decimal digits, same as [0-9]##.

(remove the -n for dry-run when happy).

share|improve this answer

edited Jul 29 at 14:09

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

1

Assuming there is only a single .jpeg substring in each name and that you'd like to remove everything after that substring (no matter if it's a number or some other string), using a standard shell loop:

for name in *.jpeg*; do
 mv -i -- "$name" "$name%.jpeg*.jpeg"
done

The parameter substitution $name%.jpeg* would delete .jpeg and anything following it from the value of $name. We then add the .jpeg string to the result of that substitution to create the new filename.

The mv -i -- bit will invoke mv in such a way that it will ask for confirmation before overwriting an existing name. The -- is to protect the following filename from accidentally being recognised as a set of options if the name starts with a dash (-- signals the end of command line options).

share|improve this answer

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

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add a comment | 

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6

If you have Larry Wall's perl rename

rename 's/[.]jpeg[0-9]*/.jpeg/' *.jpeg[0-9]*

if you have only the Util-Linux rename that won't work.

You could use a for loop in bash

for n in *.jpeg[0-9]*
do mv -i "$n" "$n%%.jpeg[0-9]*.jpeg"
done

$var%%pattern is a standard parameter expansion that expands to the value of var, with the (longest) trailing part matching pattern removed. So, if n is foo.jpeg123, $n%%.jpeg[0-9* is foo. (foo.jpeg1abc would also result in foo.)

share|improve this answer

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could you please explain your answer a bit? (I'd personally like to understand the n%%). Thanks.
  
  – Biggybi
  Jul 28 at 10:56
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Biggybi, there.
  
  – ilkkachu
  Jul 28 at 16:18
  

  
  
  
  

add a comment | 

6

If you have Larry Wall's perl rename

rename 's/[.]jpeg[0-9]*/.jpeg/' *.jpeg[0-9]*

if you have only the Util-Linux rename that won't work.

You could use a for loop in bash

for n in *.jpeg[0-9]*
do mv -i "$n" "$n%%.jpeg[0-9]*.jpeg"
done

$var%%pattern is a standard parameter expansion that expands to the value of var, with the (longest) trailing part matching pattern removed. So, if n is foo.jpeg123, $n%%.jpeg[0-9* is foo. (foo.jpeg1abc would also result in foo.)

share|improve this answer

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could you please explain your answer a bit? (I'd personally like to understand the n%%). Thanks.
  
  – Biggybi
  Jul 28 at 10:56
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Biggybi, there.
  
  – ilkkachu
  Jul 28 at 16:18
  

  
  
  
  

add a comment | 

If you have Larry Wall's perl rename

rename 's/[.]jpeg[0-9]*/.jpeg/' *.jpeg[0-9]*

if you have only the Util-Linux rename that won't work.

You could use a for loop in bash

for n in *.jpeg[0-9]*
do mv -i "$n" "$n%%.jpeg[0-9]*.jpeg"
done

$var%%pattern is a standard parameter expansion that expands to the value of var, with the (longest) trailing part matching pattern removed. So, if n is foo.jpeg123, $n%%.jpeg[0-9* is foo. (foo.jpeg1abc would also result in foo.)

share|improve this answer

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

rename 's/[.]jpeg[0-9]*/.jpeg/' *.jpeg[0-9]*

for n in *.jpeg[0-9]*
do mv -i "$n" "$n%%.jpeg[0-9]*.jpeg"
done

share|improve this answer

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

edited Jul 28 at 16:18

ilkkachu

66.7k1010 gold badges111111 silver badges193193 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

answered Jul 28 at 6:50

JasenJasen

2,61188 silver badges1313 bronze badges

3

I'd recommend using zsh's zmv here which would guard against potential conflicts (like there being both a file.jpeg1 and file.jpeg2 files in the current directory) before doing any rename.

In zsh:

autoload zmv # best in ~/.zshrc
zmv -n '(*.jpeg)<->' '$1'

Where <-> (<x-y> number range matching here without boundaries) matches any sequence of decimal digits, same as [0-9]##.

(remove the -n for dry-run when happy).

share|improve this answer

edited Jul 29 at 14:09

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

3

I'd recommend using zsh's zmv here which would guard against potential conflicts (like there being both a file.jpeg1 and file.jpeg2 files in the current directory) before doing any rename.

In zsh:

autoload zmv # best in ~/.zshrc
zmv -n '(*.jpeg)<->' '$1'

Where <-> (<x-y> number range matching here without boundaries) matches any sequence of decimal digits, same as [0-9]##.

(remove the -n for dry-run when happy).

share|improve this answer

edited Jul 29 at 14:09

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

I'd recommend using zsh's zmv here which would guard against potential conflicts (like there being both a file.jpeg1 and file.jpeg2 files in the current directory) before doing any rename.

In zsh:

autoload zmv # best in ~/.zshrc
zmv -n '(*.jpeg)<->' '$1'

Where <-> (<x-y> number range matching here without boundaries) matches any sequence of decimal digits, same as [0-9]##.

(remove the -n for dry-run when happy).

share|improve this answer

edited Jul 29 at 14:09

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

autoload zmv # best in ~/.zshrc
zmv -n '(*.jpeg)<->' '$1'

share|improve this answer

edited Jul 29 at 14:09

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

answered Jul 28 at 7:07

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

1

Assuming there is only a single .jpeg substring in each name and that you'd like to remove everything after that substring (no matter if it's a number or some other string), using a standard shell loop:

for name in *.jpeg*; do
 mv -i -- "$name" "$name%.jpeg*.jpeg"
done

The parameter substitution $name%.jpeg* would delete .jpeg and anything following it from the value of $name. We then add the .jpeg string to the result of that substitution to create the new filename.

The mv -i -- bit will invoke mv in such a way that it will ask for confirmation before overwriting an existing name. The -- is to protect the following filename from accidentally being recognised as a set of options if the name starts with a dash (-- signals the end of command line options).

share|improve this answer

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges

add a comment | 

1

Assuming there is only a single .jpeg substring in each name and that you'd like to remove everything after that substring (no matter if it's a number or some other string), using a standard shell loop:

for name in *.jpeg*; do
 mv -i -- "$name" "$name%.jpeg*.jpeg"
done

The parameter substitution $name%.jpeg* would delete .jpeg and anything following it from the value of $name. We then add the .jpeg string to the result of that substitution to create the new filename.

The mv -i -- bit will invoke mv in such a way that it will ask for confirmation before overwriting an existing name. The -- is to protect the following filename from accidentally being recognised as a set of options if the name starts with a dash (-- signals the end of command line options).

share|improve this answer

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges

add a comment | 

Assuming there is only a single .jpeg substring in each name and that you'd like to remove everything after that substring (no matter if it's a number or some other string), using a standard shell loop:

for name in *.jpeg*; do
 mv -i -- "$name" "$name%.jpeg*.jpeg"
done

The parameter substitution $name%.jpeg* would delete .jpeg and anything following it from the value of $name. We then add the .jpeg string to the result of that substitution to create the new filename.

The mv -i -- bit will invoke mv in such a way that it will ask for confirmation before overwriting an existing name. The -- is to protect the following filename from accidentally being recognised as a set of options if the name starts with a dash (-- signals the end of command line options).

share|improve this answer

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges

for name in *.jpeg*; do
 mv -i -- "$name" "$name%.jpeg*.jpeg"
done

share|improve this answer

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges

answered Jul 29 at 12:39

Kusalananda♦Kusalananda

158k1818 gold badges313313 silver badges499499 bronze badges