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Convert seconds to minutes
recursive search for a pattern, then for each match print out the specific SEQUENCE: line number, file name, and no file contentsExtract Values from simple html file via grep/awkStrategy to extract movies's name from this ununiform dataset?Print a line in stdout that matches an expression if the output contains another expressionUsing Awk to Search Bro Log for IPs/Keywords Found in Online Text FileHow to limit printed output based on number of occurences (AWK)stream editing tools: output what's scrapedText processing - Building a slurm topology.conf file from ibnetdiscover outputBash script command to search and highlight text in terminal bufferSumming minutes and seconds with awk
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/duration //'
bash awk
edited yesterday
αғsнιη
17.1k103069
asked yesterday
JoeJoe
223
add a comment |
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/duration //'
bash awk
edited yesterday
αғsнιη
17.1k103069
asked yesterday
JoeJoe
223
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
yesterday
add a comment |
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/duration //'
bash awk
edited yesterday
αғsнιη
17.1k103069
asked yesterday
JoeJoe
223
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/duration //'
bash awk
bash awk
edited yesterday
αғsнιη
17.1k103069
asked yesterday
JoeJoe
223
edited yesterday
αғsнιη
17.1k103069
asked yesterday
JoeJoe
223
edited yesterday
αғsнιη
17.1k103069
edited yesterday
αғsнιη
17.1k103069
edited yesterday
αғsнιη
17.1k103069
17.1k103069
asked yesterday
JoeJoe
223
asked yesterday
JoeJoe
223
asked yesterday
JoeJoe
223
223
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
yesterday
add a comment |
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
yesterday
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
yesterday
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
yesterday
add a comment |
1 Answer
1
active
oldest
votes
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered yesterday
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
22 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered yesterday
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
22 hours ago
add a comment |
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered yesterday
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
22 hours ago
add a comment |
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered yesterday
glenn jackmanglenn jackman
53k573114
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered yesterday
glenn jackmanglenn jackman
53k573114
answered yesterday
glenn jackmanglenn jackman
53k573114
answered yesterday
glenn jackmanglenn jackman
53k573114
answered yesterday
glenn jackmanglenn jackman
53k573114
53k573114
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
22 hours ago
add a comment |
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
22 hours ago
Thanks! That's working perfectly :)
– Joe
yesterday
Thanks! That's working perfectly :)
– Joe
yesterday
Here's the same operation using a second iteration of awk ...
awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'– RubberStamp
22 hours ago
Here's the same operation using a second iteration of awk ...
awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'– RubberStamp
22 hours ago
add a comment |
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Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
yesterday
Using
date -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.– bu5hman
yesterday