Generate permutations and combination for name columnPermutation and Combination of wordsSQL Server 2008 datetime index performance bugDoes SQL Server check disk space before allocating a new page?Oracle GoldenGate add trandata errorsImprove query performance when selecting almost all rows with many “group by” columnsColumn Name in separate table SQL ServerReplication and AlwaysOn combinationInvalid column name 'database_id'Investigating errors from strange queryGroup by sum based on under group in SQL Serverselect single row from table for a particular column combination

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Generate permutations and combination for name column


Permutation and Combination of wordsSQL Server 2008 datetime index performance bugDoes SQL Server check disk space before allocating a new page?Oracle GoldenGate add trandata errorsImprove query performance when selecting almost all rows with many “group by” columnsColumn Name in separate table SQL ServerReplication and AlwaysOn combinationInvalid column name 'database_id'Investigating errors from strange queryGroup by sum based on under group in SQL Serverselect single row from table for a particular column combination






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








8















I have the following sample data for permutations and combination.



create table tbltest
(
name varchar(50),
addres varchar(100)
);

insert into tbltest values('Sam Mak John','Street 1 HNo 101 USA');
insert into tbltest values('Donatella Nobatti','HNo 101 UK');
insert into tbltest values('Sam Buca','Main Road B Block UAE');
insert into tbltest values('Juan Soponatime','Hight Street CA');
insert into tbltest values('Aaron Spacemuseum','HNo A10 100 feet Road A Block ');


I want to generate permutations and combinations for the name column in the table tbltest and store into temp table.



For an example expected result:



name
----------------
John Mak Sam
John Sam Mak
Mak John Sam
Mak Sam John
Sam John Mak
Sam Mak John
....
....


Tried with following query: Source



Note: Following query works as expected for single record but when I tried on table using cursor its running more than 35 min and still keeps running.



DECLARE @inputStr VARCHAR(MAX)= 'Sam Mak John';
DECLARE @ValueStr VARCHAR(100);
DECLARE @Count INT, @Loop INT= 1, @totalSum INT;
DECLARE @Query1 VARCHAR(1000), @Query2 VARCHAR(1000), @Query3 VARCHAR(1000), @Query4 VARCHAR(1000), @Query5 VARCHAR(1000), @Query6 VARCHAR(1000), @Query VARCHAR(4000), @Combination VARCHAR(1000);

--Temporary table to capture all the words separately
CREATE TABLE #tmpvalues
(intIndex INT IDENTITY(1, 1),
intProc INT,
subStr VARCHAR(100)
);

--Temporary table to store all the possible combinations
CREATE TABLE #tmpCombinations
(subCombStr VARCHAR(1000)
);

--get the sub-strings(words) from input statement into a temp table
WHILE LEN(@inputStr) > 0
BEGIN
SET @ValueStr = LEFT(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr) - 1, -1), LEN(@inputStr)));
SET @inputStr = SUBSTRING(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr), 0), LEN(@inputStr)) + 1, LEN(@inputStr));
INSERT INTO #tmpvalues
VALUES
(@Loop,
@ValueStr
);
SET @Loop = @Loop + 1;
END;
SELECT @Count = MAX(intINDEX)
FROM #tmpvalues;
SET @Loop = 1;

--Set an integer values for each words
--This will be used to filter the combinations in which any two words are repating
DECLARE @tempIntAdd INT;--Addition factor
SET @tempIntAdd = @Loop * @Count;
WHILE @Loop <= (@Count - 1)
BEGIN
DECLARE @tempIntProc INT;
SELECT @tempIntProc = intProc
FROM #tmpvalues
WHERE intIndex = @Loop;
UPDATE #tmpvalues
SET
intProc = @tempIntProc + @tempIntAdd
WHERE intIndex = @Loop + 1;
SET @Loop = @Loop + 1;
SET @tempIntAdd = @tempIntAdd * 2;
END;
--
SET @Loop = 1;
SET @Query1 = 'INSERT INTO #tmpCombinations SELECT DISTINCT ';
SET @Query2 = 'ALL_COMBINATIONS FROM';
SET @Query3 = ' ';
SET @Query4 = ' WHERE';
SET @Query5 = '(';
SET @Query6 = ')';

-- Generate the dynamic query to get permutations and combination of individual words
WHILE @Loop <= @Count
BEGIN
SELECT @ValueStr = subStr
FROM #tmpvalues
WHERE intIndex = @Loop;
SET @Query1 = @Query1 + 'T' + CAST(@Loop AS VARCHAR) + '.subStr ';
IF(@Loop < @Count)
SET @Query1 = @Query1 + '+ '' '' + ';
SET @Query3 = @Query3 + '#tmpvalues ' + 'T' + CAST(@Loop AS VARCHAR);
IF(@Loop < @Count)
SET @Query3 = @Query3 + ', ';
SET @Query5 = @Query5 + 'T' + CAST(@Loop AS VARCHAR) + '.intProc';
IF(@Loop < @Count)
SET @Query5 = @Query5 + ' + ';
SET @Loop = @Loop + 1;
END;
SELECT @totalSum = SUM(intProc)
FROM #tmpvalues;

--Create final query
SET @Query = @Query1 + @Query2 + @Query3 + @Query4 + @Query5 + @Query6 + ' =' + CAST(@totalSum AS VARCHAR);

--Execute the dynamic Query
EXECUTE (@Query);

SELECT subCombStr from #tmpCombinations









share|improve this question






















  • So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

    – George.Palacios
    May 8 at 7:51











  • @George.Palacios, Yes exactly.

    – MAK
    May 8 at 7:53











  • Should they all be 3 names long? Or do you want every possible combination?

    – George.Palacios
    May 8 at 7:59











  • @George.Palacios, They may comes with any numbers of words.

    – MAK
    May 8 at 8:02

















8















I have the following sample data for permutations and combination.



create table tbltest
(
name varchar(50),
addres varchar(100)
);

insert into tbltest values('Sam Mak John','Street 1 HNo 101 USA');
insert into tbltest values('Donatella Nobatti','HNo 101 UK');
insert into tbltest values('Sam Buca','Main Road B Block UAE');
insert into tbltest values('Juan Soponatime','Hight Street CA');
insert into tbltest values('Aaron Spacemuseum','HNo A10 100 feet Road A Block ');


I want to generate permutations and combinations for the name column in the table tbltest and store into temp table.



For an example expected result:



name
----------------
John Mak Sam
John Sam Mak
Mak John Sam
Mak Sam John
Sam John Mak
Sam Mak John
....
....


Tried with following query: Source



Note: Following query works as expected for single record but when I tried on table using cursor its running more than 35 min and still keeps running.



DECLARE @inputStr VARCHAR(MAX)= 'Sam Mak John';
DECLARE @ValueStr VARCHAR(100);
DECLARE @Count INT, @Loop INT= 1, @totalSum INT;
DECLARE @Query1 VARCHAR(1000), @Query2 VARCHAR(1000), @Query3 VARCHAR(1000), @Query4 VARCHAR(1000), @Query5 VARCHAR(1000), @Query6 VARCHAR(1000), @Query VARCHAR(4000), @Combination VARCHAR(1000);

--Temporary table to capture all the words separately
CREATE TABLE #tmpvalues
(intIndex INT IDENTITY(1, 1),
intProc INT,
subStr VARCHAR(100)
);

--Temporary table to store all the possible combinations
CREATE TABLE #tmpCombinations
(subCombStr VARCHAR(1000)
);

--get the sub-strings(words) from input statement into a temp table
WHILE LEN(@inputStr) > 0
BEGIN
SET @ValueStr = LEFT(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr) - 1, -1), LEN(@inputStr)));
SET @inputStr = SUBSTRING(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr), 0), LEN(@inputStr)) + 1, LEN(@inputStr));
INSERT INTO #tmpvalues
VALUES
(@Loop,
@ValueStr
);
SET @Loop = @Loop + 1;
END;
SELECT @Count = MAX(intINDEX)
FROM #tmpvalues;
SET @Loop = 1;

--Set an integer values for each words
--This will be used to filter the combinations in which any two words are repating
DECLARE @tempIntAdd INT;--Addition factor
SET @tempIntAdd = @Loop * @Count;
WHILE @Loop <= (@Count - 1)
BEGIN
DECLARE @tempIntProc INT;
SELECT @tempIntProc = intProc
FROM #tmpvalues
WHERE intIndex = @Loop;
UPDATE #tmpvalues
SET
intProc = @tempIntProc + @tempIntAdd
WHERE intIndex = @Loop + 1;
SET @Loop = @Loop + 1;
SET @tempIntAdd = @tempIntAdd * 2;
END;
--
SET @Loop = 1;
SET @Query1 = 'INSERT INTO #tmpCombinations SELECT DISTINCT ';
SET @Query2 = 'ALL_COMBINATIONS FROM';
SET @Query3 = ' ';
SET @Query4 = ' WHERE';
SET @Query5 = '(';
SET @Query6 = ')';

-- Generate the dynamic query to get permutations and combination of individual words
WHILE @Loop <= @Count
BEGIN
SELECT @ValueStr = subStr
FROM #tmpvalues
WHERE intIndex = @Loop;
SET @Query1 = @Query1 + 'T' + CAST(@Loop AS VARCHAR) + '.subStr ';
IF(@Loop < @Count)
SET @Query1 = @Query1 + '+ '' '' + ';
SET @Query3 = @Query3 + '#tmpvalues ' + 'T' + CAST(@Loop AS VARCHAR);
IF(@Loop < @Count)
SET @Query3 = @Query3 + ', ';
SET @Query5 = @Query5 + 'T' + CAST(@Loop AS VARCHAR) + '.intProc';
IF(@Loop < @Count)
SET @Query5 = @Query5 + ' + ';
SET @Loop = @Loop + 1;
END;
SELECT @totalSum = SUM(intProc)
FROM #tmpvalues;

--Create final query
SET @Query = @Query1 + @Query2 + @Query3 + @Query4 + @Query5 + @Query6 + ' =' + CAST(@totalSum AS VARCHAR);

--Execute the dynamic Query
EXECUTE (@Query);

SELECT subCombStr from #tmpCombinations









share|improve this question






















  • So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

    – George.Palacios
    May 8 at 7:51











  • @George.Palacios, Yes exactly.

    – MAK
    May 8 at 7:53











  • Should they all be 3 names long? Or do you want every possible combination?

    – George.Palacios
    May 8 at 7:59











  • @George.Palacios, They may comes with any numbers of words.

    – MAK
    May 8 at 8:02













8












8








8


2






I have the following sample data for permutations and combination.



create table tbltest
(
name varchar(50),
addres varchar(100)
);

insert into tbltest values('Sam Mak John','Street 1 HNo 101 USA');
insert into tbltest values('Donatella Nobatti','HNo 101 UK');
insert into tbltest values('Sam Buca','Main Road B Block UAE');
insert into tbltest values('Juan Soponatime','Hight Street CA');
insert into tbltest values('Aaron Spacemuseum','HNo A10 100 feet Road A Block ');


I want to generate permutations and combinations for the name column in the table tbltest and store into temp table.



For an example expected result:



name
----------------
John Mak Sam
John Sam Mak
Mak John Sam
Mak Sam John
Sam John Mak
Sam Mak John
....
....


Tried with following query: Source



Note: Following query works as expected for single record but when I tried on table using cursor its running more than 35 min and still keeps running.



DECLARE @inputStr VARCHAR(MAX)= 'Sam Mak John';
DECLARE @ValueStr VARCHAR(100);
DECLARE @Count INT, @Loop INT= 1, @totalSum INT;
DECLARE @Query1 VARCHAR(1000), @Query2 VARCHAR(1000), @Query3 VARCHAR(1000), @Query4 VARCHAR(1000), @Query5 VARCHAR(1000), @Query6 VARCHAR(1000), @Query VARCHAR(4000), @Combination VARCHAR(1000);

--Temporary table to capture all the words separately
CREATE TABLE #tmpvalues
(intIndex INT IDENTITY(1, 1),
intProc INT,
subStr VARCHAR(100)
);

--Temporary table to store all the possible combinations
CREATE TABLE #tmpCombinations
(subCombStr VARCHAR(1000)
);

--get the sub-strings(words) from input statement into a temp table
WHILE LEN(@inputStr) > 0
BEGIN
SET @ValueStr = LEFT(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr) - 1, -1), LEN(@inputStr)));
SET @inputStr = SUBSTRING(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr), 0), LEN(@inputStr)) + 1, LEN(@inputStr));
INSERT INTO #tmpvalues
VALUES
(@Loop,
@ValueStr
);
SET @Loop = @Loop + 1;
END;
SELECT @Count = MAX(intINDEX)
FROM #tmpvalues;
SET @Loop = 1;

--Set an integer values for each words
--This will be used to filter the combinations in which any two words are repating
DECLARE @tempIntAdd INT;--Addition factor
SET @tempIntAdd = @Loop * @Count;
WHILE @Loop <= (@Count - 1)
BEGIN
DECLARE @tempIntProc INT;
SELECT @tempIntProc = intProc
FROM #tmpvalues
WHERE intIndex = @Loop;
UPDATE #tmpvalues
SET
intProc = @tempIntProc + @tempIntAdd
WHERE intIndex = @Loop + 1;
SET @Loop = @Loop + 1;
SET @tempIntAdd = @tempIntAdd * 2;
END;
--
SET @Loop = 1;
SET @Query1 = 'INSERT INTO #tmpCombinations SELECT DISTINCT ';
SET @Query2 = 'ALL_COMBINATIONS FROM';
SET @Query3 = ' ';
SET @Query4 = ' WHERE';
SET @Query5 = '(';
SET @Query6 = ')';

-- Generate the dynamic query to get permutations and combination of individual words
WHILE @Loop <= @Count
BEGIN
SELECT @ValueStr = subStr
FROM #tmpvalues
WHERE intIndex = @Loop;
SET @Query1 = @Query1 + 'T' + CAST(@Loop AS VARCHAR) + '.subStr ';
IF(@Loop < @Count)
SET @Query1 = @Query1 + '+ '' '' + ';
SET @Query3 = @Query3 + '#tmpvalues ' + 'T' + CAST(@Loop AS VARCHAR);
IF(@Loop < @Count)
SET @Query3 = @Query3 + ', ';
SET @Query5 = @Query5 + 'T' + CAST(@Loop AS VARCHAR) + '.intProc';
IF(@Loop < @Count)
SET @Query5 = @Query5 + ' + ';
SET @Loop = @Loop + 1;
END;
SELECT @totalSum = SUM(intProc)
FROM #tmpvalues;

--Create final query
SET @Query = @Query1 + @Query2 + @Query3 + @Query4 + @Query5 + @Query6 + ' =' + CAST(@totalSum AS VARCHAR);

--Execute the dynamic Query
EXECUTE (@Query);

SELECT subCombStr from #tmpCombinations









share|improve this question














I have the following sample data for permutations and combination.



create table tbltest
(
name varchar(50),
addres varchar(100)
);

insert into tbltest values('Sam Mak John','Street 1 HNo 101 USA');
insert into tbltest values('Donatella Nobatti','HNo 101 UK');
insert into tbltest values('Sam Buca','Main Road B Block UAE');
insert into tbltest values('Juan Soponatime','Hight Street CA');
insert into tbltest values('Aaron Spacemuseum','HNo A10 100 feet Road A Block ');


I want to generate permutations and combinations for the name column in the table tbltest and store into temp table.



For an example expected result:



name
----------------
John Mak Sam
John Sam Mak
Mak John Sam
Mak Sam John
Sam John Mak
Sam Mak John
....
....


Tried with following query: Source



Note: Following query works as expected for single record but when I tried on table using cursor its running more than 35 min and still keeps running.



DECLARE @inputStr VARCHAR(MAX)= 'Sam Mak John';
DECLARE @ValueStr VARCHAR(100);
DECLARE @Count INT, @Loop INT= 1, @totalSum INT;
DECLARE @Query1 VARCHAR(1000), @Query2 VARCHAR(1000), @Query3 VARCHAR(1000), @Query4 VARCHAR(1000), @Query5 VARCHAR(1000), @Query6 VARCHAR(1000), @Query VARCHAR(4000), @Combination VARCHAR(1000);

--Temporary table to capture all the words separately
CREATE TABLE #tmpvalues
(intIndex INT IDENTITY(1, 1),
intProc INT,
subStr VARCHAR(100)
);

--Temporary table to store all the possible combinations
CREATE TABLE #tmpCombinations
(subCombStr VARCHAR(1000)
);

--get the sub-strings(words) from input statement into a temp table
WHILE LEN(@inputStr) > 0
BEGIN
SET @ValueStr = LEFT(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr) - 1, -1), LEN(@inputStr)));
SET @inputStr = SUBSTRING(@inputStr, ISNULL(NULLIF(CHARINDEX(' ', @inputStr), 0), LEN(@inputStr)) + 1, LEN(@inputStr));
INSERT INTO #tmpvalues
VALUES
(@Loop,
@ValueStr
);
SET @Loop = @Loop + 1;
END;
SELECT @Count = MAX(intINDEX)
FROM #tmpvalues;
SET @Loop = 1;

--Set an integer values for each words
--This will be used to filter the combinations in which any two words are repating
DECLARE @tempIntAdd INT;--Addition factor
SET @tempIntAdd = @Loop * @Count;
WHILE @Loop <= (@Count - 1)
BEGIN
DECLARE @tempIntProc INT;
SELECT @tempIntProc = intProc
FROM #tmpvalues
WHERE intIndex = @Loop;
UPDATE #tmpvalues
SET
intProc = @tempIntProc + @tempIntAdd
WHERE intIndex = @Loop + 1;
SET @Loop = @Loop + 1;
SET @tempIntAdd = @tempIntAdd * 2;
END;
--
SET @Loop = 1;
SET @Query1 = 'INSERT INTO #tmpCombinations SELECT DISTINCT ';
SET @Query2 = 'ALL_COMBINATIONS FROM';
SET @Query3 = ' ';
SET @Query4 = ' WHERE';
SET @Query5 = '(';
SET @Query6 = ')';

-- Generate the dynamic query to get permutations and combination of individual words
WHILE @Loop <= @Count
BEGIN
SELECT @ValueStr = subStr
FROM #tmpvalues
WHERE intIndex = @Loop;
SET @Query1 = @Query1 + 'T' + CAST(@Loop AS VARCHAR) + '.subStr ';
IF(@Loop < @Count)
SET @Query1 = @Query1 + '+ '' '' + ';
SET @Query3 = @Query3 + '#tmpvalues ' + 'T' + CAST(@Loop AS VARCHAR);
IF(@Loop < @Count)
SET @Query3 = @Query3 + ', ';
SET @Query5 = @Query5 + 'T' + CAST(@Loop AS VARCHAR) + '.intProc';
IF(@Loop < @Count)
SET @Query5 = @Query5 + ' + ';
SET @Loop = @Loop + 1;
END;
SELECT @totalSum = SUM(intProc)
FROM #tmpvalues;

--Create final query
SET @Query = @Query1 + @Query2 + @Query3 + @Query4 + @Query5 + @Query6 + ' =' + CAST(@totalSum AS VARCHAR);

--Execute the dynamic Query
EXECUTE (@Query);

SELECT subCombStr from #tmpCombinations






sql-server sql-server-2008-r2






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked May 8 at 7:49









MAKMAK

1684




1684












  • So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

    – George.Palacios
    May 8 at 7:51











  • @George.Palacios, Yes exactly.

    – MAK
    May 8 at 7:53











  • Should they all be 3 names long? Or do you want every possible combination?

    – George.Palacios
    May 8 at 7:59











  • @George.Palacios, They may comes with any numbers of words.

    – MAK
    May 8 at 8:02

















  • So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

    – George.Palacios
    May 8 at 7:51











  • @George.Palacios, Yes exactly.

    – MAK
    May 8 at 7:53











  • Should they all be 3 names long? Or do you want every possible combination?

    – George.Palacios
    May 8 at 7:59











  • @George.Palacios, They may comes with any numbers of words.

    – MAK
    May 8 at 8:02
















So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

– George.Palacios
May 8 at 7:51





So just to be clear, you want to take the name column, split it by the space character into rows, and then get every possible combination of names between those rows?

– George.Palacios
May 8 at 7:51













@George.Palacios, Yes exactly.

– MAK
May 8 at 7:53





@George.Palacios, Yes exactly.

– MAK
May 8 at 7:53













Should they all be 3 names long? Or do you want every possible combination?

– George.Palacios
May 8 at 7:59





Should they all be 3 names long? Or do you want every possible combination?

– George.Palacios
May 8 at 7:59













@George.Palacios, They may comes with any numbers of words.

– MAK
May 8 at 8:02





@George.Palacios, They may comes with any numbers of words.

– MAK
May 8 at 8:02










1 Answer
1






active

oldest

votes


















12














If you split each name into a separate table of the following structure,



CREATE TABLE dbo.NameParts
(
ID int NOT NULL,
NamePart varchar(30) NOT NULL
);


(where ID marks name parts that belong to the same name, to avoid permutation of parts of different names) – then you can use a recursive CTE to produce the permutations:



WITH
permutations AS
(
SELECT
ID = t.ID,
FullNameVariation = CAST(t.NamePart AS varchar(500)),
Level = COUNT(*) OVER (PARTITION BY t.ID)
FROM
dbo.NameParts AS t
UNION ALL
SELECT
ID = t.ID,
FullNameVariation = CAST(p.FullNameVariation + ' ' + t.NamePart AS varchar(500)),
Level = p.Level - 1
FROM
dbo.NameParts AS t
INNER JOIN permutations AS p ON t.ID = p.ID
WHERE 1=1
AND p.Level > 1
AND ' ' + p.FullNameVariation + ' ' NOT LIKE '% ' + t.NamePart + ' %'
)
SELECT
ID,
FullNameVariation
FROM
permutations
WHERE
Level = 1
ORDER BY
ID,
FullNameVariation
;


Applying the query to this data sample:



INSERT INTO dbo.NameParts
VALUES
(1, 'Sam'), (1, 'Mak'), (1, 'John'),
(2, 'Donatella'), (2, 'Nobatti'),
(3, 'Sam'), (3, 'Buca'),
(4, 'Juan'), (4, 'Soponatime'),
(5, 'Aaron'), (5, 'Spacemuseum')
;


produces the following output:



ID FullNameVariation
-- -----------------
1 John Mak Sam
1 John Sam Mak
1 Mak John Sam
1 Mak Sam John
1 Sam John Mak
1 Sam Mak John
2 Donatella Nobatti
2 Nobatti Donatella
3 Buca Sam
3 Sam Buca
4 Juan Soponatime
4 Soponatime Juan
5 Aaron Spacemuseum
5 Spacemuseum Aaron


You can play with this solution using a live demo at dbfiddle logodb<>fiddle.uk.






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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    12














    If you split each name into a separate table of the following structure,



    CREATE TABLE dbo.NameParts
    (
    ID int NOT NULL,
    NamePart varchar(30) NOT NULL
    );


    (where ID marks name parts that belong to the same name, to avoid permutation of parts of different names) – then you can use a recursive CTE to produce the permutations:



    WITH
    permutations AS
    (
    SELECT
    ID = t.ID,
    FullNameVariation = CAST(t.NamePart AS varchar(500)),
    Level = COUNT(*) OVER (PARTITION BY t.ID)
    FROM
    dbo.NameParts AS t
    UNION ALL
    SELECT
    ID = t.ID,
    FullNameVariation = CAST(p.FullNameVariation + ' ' + t.NamePart AS varchar(500)),
    Level = p.Level - 1
    FROM
    dbo.NameParts AS t
    INNER JOIN permutations AS p ON t.ID = p.ID
    WHERE 1=1
    AND p.Level > 1
    AND ' ' + p.FullNameVariation + ' ' NOT LIKE '% ' + t.NamePart + ' %'
    )
    SELECT
    ID,
    FullNameVariation
    FROM
    permutations
    WHERE
    Level = 1
    ORDER BY
    ID,
    FullNameVariation
    ;


    Applying the query to this data sample:



    INSERT INTO dbo.NameParts
    VALUES
    (1, 'Sam'), (1, 'Mak'), (1, 'John'),
    (2, 'Donatella'), (2, 'Nobatti'),
    (3, 'Sam'), (3, 'Buca'),
    (4, 'Juan'), (4, 'Soponatime'),
    (5, 'Aaron'), (5, 'Spacemuseum')
    ;


    produces the following output:



    ID FullNameVariation
    -- -----------------
    1 John Mak Sam
    1 John Sam Mak
    1 Mak John Sam
    1 Mak Sam John
    1 Sam John Mak
    1 Sam Mak John
    2 Donatella Nobatti
    2 Nobatti Donatella
    3 Buca Sam
    3 Sam Buca
    4 Juan Soponatime
    4 Soponatime Juan
    5 Aaron Spacemuseum
    5 Spacemuseum Aaron


    You can play with this solution using a live demo at dbfiddle logodb<>fiddle.uk.






    share|improve this answer





























      12














      If you split each name into a separate table of the following structure,



      CREATE TABLE dbo.NameParts
      (
      ID int NOT NULL,
      NamePart varchar(30) NOT NULL
      );


      (where ID marks name parts that belong to the same name, to avoid permutation of parts of different names) – then you can use a recursive CTE to produce the permutations:



      WITH
      permutations AS
      (
      SELECT
      ID = t.ID,
      FullNameVariation = CAST(t.NamePart AS varchar(500)),
      Level = COUNT(*) OVER (PARTITION BY t.ID)
      FROM
      dbo.NameParts AS t
      UNION ALL
      SELECT
      ID = t.ID,
      FullNameVariation = CAST(p.FullNameVariation + ' ' + t.NamePart AS varchar(500)),
      Level = p.Level - 1
      FROM
      dbo.NameParts AS t
      INNER JOIN permutations AS p ON t.ID = p.ID
      WHERE 1=1
      AND p.Level > 1
      AND ' ' + p.FullNameVariation + ' ' NOT LIKE '% ' + t.NamePart + ' %'
      )
      SELECT
      ID,
      FullNameVariation
      FROM
      permutations
      WHERE
      Level = 1
      ORDER BY
      ID,
      FullNameVariation
      ;


      Applying the query to this data sample:



      INSERT INTO dbo.NameParts
      VALUES
      (1, 'Sam'), (1, 'Mak'), (1, 'John'),
      (2, 'Donatella'), (2, 'Nobatti'),
      (3, 'Sam'), (3, 'Buca'),
      (4, 'Juan'), (4, 'Soponatime'),
      (5, 'Aaron'), (5, 'Spacemuseum')
      ;


      produces the following output:



      ID FullNameVariation
      -- -----------------
      1 John Mak Sam
      1 John Sam Mak
      1 Mak John Sam
      1 Mak Sam John
      1 Sam John Mak
      1 Sam Mak John
      2 Donatella Nobatti
      2 Nobatti Donatella
      3 Buca Sam
      3 Sam Buca
      4 Juan Soponatime
      4 Soponatime Juan
      5 Aaron Spacemuseum
      5 Spacemuseum Aaron


      You can play with this solution using a live demo at dbfiddle logodb<>fiddle.uk.






      share|improve this answer



























        12












        12








        12







        If you split each name into a separate table of the following structure,



        CREATE TABLE dbo.NameParts
        (
        ID int NOT NULL,
        NamePart varchar(30) NOT NULL
        );


        (where ID marks name parts that belong to the same name, to avoid permutation of parts of different names) – then you can use a recursive CTE to produce the permutations:



        WITH
        permutations AS
        (
        SELECT
        ID = t.ID,
        FullNameVariation = CAST(t.NamePart AS varchar(500)),
        Level = COUNT(*) OVER (PARTITION BY t.ID)
        FROM
        dbo.NameParts AS t
        UNION ALL
        SELECT
        ID = t.ID,
        FullNameVariation = CAST(p.FullNameVariation + ' ' + t.NamePart AS varchar(500)),
        Level = p.Level - 1
        FROM
        dbo.NameParts AS t
        INNER JOIN permutations AS p ON t.ID = p.ID
        WHERE 1=1
        AND p.Level > 1
        AND ' ' + p.FullNameVariation + ' ' NOT LIKE '% ' + t.NamePart + ' %'
        )
        SELECT
        ID,
        FullNameVariation
        FROM
        permutations
        WHERE
        Level = 1
        ORDER BY
        ID,
        FullNameVariation
        ;


        Applying the query to this data sample:



        INSERT INTO dbo.NameParts
        VALUES
        (1, 'Sam'), (1, 'Mak'), (1, 'John'),
        (2, 'Donatella'), (2, 'Nobatti'),
        (3, 'Sam'), (3, 'Buca'),
        (4, 'Juan'), (4, 'Soponatime'),
        (5, 'Aaron'), (5, 'Spacemuseum')
        ;


        produces the following output:



        ID FullNameVariation
        -- -----------------
        1 John Mak Sam
        1 John Sam Mak
        1 Mak John Sam
        1 Mak Sam John
        1 Sam John Mak
        1 Sam Mak John
        2 Donatella Nobatti
        2 Nobatti Donatella
        3 Buca Sam
        3 Sam Buca
        4 Juan Soponatime
        4 Soponatime Juan
        5 Aaron Spacemuseum
        5 Spacemuseum Aaron


        You can play with this solution using a live demo at dbfiddle logodb<>fiddle.uk.






        share|improve this answer















        If you split each name into a separate table of the following structure,



        CREATE TABLE dbo.NameParts
        (
        ID int NOT NULL,
        NamePart varchar(30) NOT NULL
        );


        (where ID marks name parts that belong to the same name, to avoid permutation of parts of different names) – then you can use a recursive CTE to produce the permutations:



        WITH
        permutations AS
        (
        SELECT
        ID = t.ID,
        FullNameVariation = CAST(t.NamePart AS varchar(500)),
        Level = COUNT(*) OVER (PARTITION BY t.ID)
        FROM
        dbo.NameParts AS t
        UNION ALL
        SELECT
        ID = t.ID,
        FullNameVariation = CAST(p.FullNameVariation + ' ' + t.NamePart AS varchar(500)),
        Level = p.Level - 1
        FROM
        dbo.NameParts AS t
        INNER JOIN permutations AS p ON t.ID = p.ID
        WHERE 1=1
        AND p.Level > 1
        AND ' ' + p.FullNameVariation + ' ' NOT LIKE '% ' + t.NamePart + ' %'
        )
        SELECT
        ID,
        FullNameVariation
        FROM
        permutations
        WHERE
        Level = 1
        ORDER BY
        ID,
        FullNameVariation
        ;


        Applying the query to this data sample:



        INSERT INTO dbo.NameParts
        VALUES
        (1, 'Sam'), (1, 'Mak'), (1, 'John'),
        (2, 'Donatella'), (2, 'Nobatti'),
        (3, 'Sam'), (3, 'Buca'),
        (4, 'Juan'), (4, 'Soponatime'),
        (5, 'Aaron'), (5, 'Spacemuseum')
        ;


        produces the following output:



        ID FullNameVariation
        -- -----------------
        1 John Mak Sam
        1 John Sam Mak
        1 Mak John Sam
        1 Mak Sam John
        1 Sam John Mak
        1 Sam Mak John
        2 Donatella Nobatti
        2 Nobatti Donatella
        3 Buca Sam
        3 Sam Buca
        4 Juan Soponatime
        4 Soponatime Juan
        5 Aaron Spacemuseum
        5 Spacemuseum Aaron


        You can play with this solution using a live demo at dbfiddle logodb<>fiddle.uk.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 2 days ago

























        answered May 8 at 10:02









        Andriy MAndriy M

        16.5k63776




        16.5k63776



























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