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Enigma between Colleagues (Part1)

A benevolent but cumbersome batch of four sequence puzzlesWhat is the next number in sequence?Don't try this if you don't know your maths!Hidden Number SequenceFill in the blanks of this number sequenceWhat is the next number in this sequence? (My first)What is a RAP Number™?SafeCracker #1 - Look who's talkingNumber Sequence Series-Question 6Number sequence puzzle; 2, 10, 44 (+2 hints)

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

10

$begingroup$

With a colleague, we tried to create enigma to challenge ourselves.

Here is our first try, hope you will enjoy it.

4 = 2

12 = 3

19 = 3

24 = 4

47 = 5

50 = ?

Hint 1 :

1987 = 10

Don't hesitate to comment some advice for the following enigma :)

number-sequence

share|improve this question

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

$endgroup$

add a comment | 

10

$begingroup$

With a colleague, we tried to create enigma to challenge ourselves.

Here is our first try, hope you will enjoy it.

4 = 2

12 = 3

19 = 3

24 = 4

47 = 5

50 = ?

Hint 1 :

1987 = 10

Don't hesitate to comment some advice for the following enigma :)

number-sequence

share|improve this question

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

$endgroup$

add a comment | 

$begingroup$

With a colleague, we tried to create enigma to challenge ourselves.

Here is our first try, hope you will enjoy it.

4 = 2

12 = 3

19 = 3

24 = 4

47 = 5

50 = ?

Hint 1 :

1987 = 10

Don't hesitate to comment some advice for the following enigma :)

number-sequence

share|improve this question

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

$endgroup$

share|improve this question

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

share|improve this question

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

edited Aug 13 at 4:19

Rubio♦

32.9k66 gold badges7575 silver badges203203 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

asked Aug 12 at 14:31

TinyDoowyTinyDoowy

19566 bronze badges

1 Answer
1

active

oldest

votes

9

$begingroup$

I'll go with

50 = 1.

Surely the number on the right must be

the length of the number in Roman numerals.

Double checking everything:

 4 = IV = 2
 12 = XII = 3
 19 = XIX = 3
 24 = XXIV = 4
 47 = XLVII = 5 

And finally

1987 = MCMLXXXVII = 10.

Yup, seems to match nicely.

share|improve this answer

edited Aug 12 at 14:53

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Was it too easy ? How to improve it ? Did you use the hint ?
  $endgroup$
  – TinyDoowy
  Aug 12 at 14:40
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  It was pretty much in the sweet spot of "easy, but rewarding to solve", well done! Yes, I took a peek at the hint, which gave a pretty good idea of how large the numbers were going to get. On this site, it's usual to withhold any actual hints (that aren't really a part of the question) until the next day, so any hints posted along with the question kind of get read automatically. Maybe I should try to get rid of that habit, come to think of it :-)
  $endgroup$
  – Bass
  Aug 12 at 14:46
  

  
  
  
  

add a comment | 

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9

$begingroup$

I'll go with

50 = 1.

Surely the number on the right must be

the length of the number in Roman numerals.

Double checking everything:

 4 = IV = 2
 12 = XII = 3
 19 = XIX = 3
 24 = XXIV = 4
 47 = XLVII = 5 

And finally

1987 = MCMLXXXVII = 10.

Yup, seems to match nicely.

share|improve this answer

edited Aug 12 at 14:53

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Was it too easy ? How to improve it ? Did you use the hint ?
  $endgroup$
  – TinyDoowy
  Aug 12 at 14:40
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  It was pretty much in the sweet spot of "easy, but rewarding to solve", well done! Yes, I took a peek at the hint, which gave a pretty good idea of how large the numbers were going to get. On this site, it's usual to withhold any actual hints (that aren't really a part of the question) until the next day, so any hints posted along with the question kind of get read automatically. Maybe I should try to get rid of that habit, come to think of it :-)
  $endgroup$
  – Bass
  Aug 12 at 14:46
  

  
  
  
  

add a comment | 

9

$begingroup$

I'll go with

50 = 1.

Surely the number on the right must be

the length of the number in Roman numerals.

Double checking everything:

 4 = IV = 2
 12 = XII = 3
 19 = XIX = 3
 24 = XXIV = 4
 47 = XLVII = 5 

And finally

1987 = MCMLXXXVII = 10.

Yup, seems to match nicely.

share|improve this answer

edited Aug 12 at 14:53

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Was it too easy ? How to improve it ? Did you use the hint ?
  $endgroup$
  – TinyDoowy
  Aug 12 at 14:40
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  It was pretty much in the sweet spot of "easy, but rewarding to solve", well done! Yes, I took a peek at the hint, which gave a pretty good idea of how large the numbers were going to get. On this site, it's usual to withhold any actual hints (that aren't really a part of the question) until the next day, so any hints posted along with the question kind of get read automatically. Maybe I should try to get rid of that habit, come to think of it :-)
  $endgroup$
  – Bass
  Aug 12 at 14:46
  

  
  
  
  

add a comment | 

$begingroup$

I'll go with

50 = 1.

Surely the number on the right must be

the length of the number in Roman numerals.

Double checking everything:

 4 = IV = 2
 12 = XII = 3
 19 = XIX = 3
 24 = XXIV = 4
 47 = XLVII = 5 

And finally

1987 = MCMLXXXVII = 10.

Yup, seems to match nicely.

share|improve this answer

edited Aug 12 at 14:53

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

$endgroup$

share|improve this answer

edited Aug 12 at 14:53

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges

answered Aug 12 at 14:37

BassBass

36k44 gold badges8888 silver badges208208 bronze badges