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Replace all items that are not belong to characters and numbers by ' '
What is difference between [-a-z] and [a-z] in regular expression?Search and replace strings that are not substrings of other stringssome POSIX Bracket Expressions not workingHow do I keep a part of the pattern matched and use it to replace on BSD sed?find: list all directories except those with numbers in their names and their childrensearch and replace numbers in vimReplace spaces with sed and regexp grouping not workingfind and replace one number with anotherGNU Pattern Match and replace exact number of charactersUsing sed to replace the hexadecimal code for URL and to insert new SVG codes after SVG tag in all SVG filesLinux sed command replace two lines having spaces and special characters using regular expression
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I want to replace all symbols like '.','-','/' and so on by ' '
I triedsed 's/[[!:alnum:]]/ /g' example.txt but it does not work
and for sed 's/[,;.-/()_]/ /g' example.txt, I found that I cannot replace '-' by ' '.
is there any way to do that?
shell regular-expression
asked May 12 at 15:02
Yiling LiuYiling Liu
304
add a comment |
I want to replace all symbols like '.','-','/' and so on by ' '
I triedsed 's/[[!:alnum:]]/ /g' example.txt but it does not work
and for sed 's/[,;.-/()_]/ /g' example.txt, I found that I cannot replace '-' by ' '.
is there any way to do that?
shell regular-expression
asked May 12 at 15:02
Yiling LiuYiling Liu
304
1
Perhaps the class you are looking for is[[:punct:]]? Regarding the use of-in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?
– steeldriver
May 12 at 15:15
add a comment |
I want to replace all symbols like '.','-','/' and so on by ' '
I triedsed 's/[[!:alnum:]]/ /g' example.txt but it does not work
and for sed 's/[,;.-/()_]/ /g' example.txt, I found that I cannot replace '-' by ' '.
is there any way to do that?
shell regular-expression
asked May 12 at 15:02
Yiling LiuYiling Liu
304
I want to replace all symbols like '.','-','/' and so on by ' '
I triedsed 's/[[!:alnum:]]/ /g' example.txt but it does not work
and for sed 's/[,;.-/()_]/ /g' example.txt, I found that I cannot replace '-' by ' '.
is there any way to do that?
shell regular-expression
shell regular-expression
asked May 12 at 15:02
Yiling LiuYiling Liu
304
asked May 12 at 15:02
Yiling LiuYiling Liu
304
asked May 12 at 15:02
Yiling LiuYiling Liu
304
asked May 12 at 15:02
Yiling LiuYiling Liu
304
asked May 12 at 15:02
Yiling LiuYiling Liu
304
304
1
Perhaps the class you are looking for is[[:punct:]]? Regarding the use of-in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?
– steeldriver
May 12 at 15:15
add a comment |
1
Perhaps the class you are looking for is[[:punct:]]? Regarding the use of-in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?
– steeldriver
May 12 at 15:15
1
1
Perhaps the class you are looking for is
[[:punct:]]? Regarding the use of - in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?– steeldriver
May 12 at 15:15
Perhaps the class you are looking for is
[[:punct:]]? Regarding the use of - in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?– steeldriver
May 12 at 15:15
add a comment |
1 Answer
1
active
oldest
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To match all non-alphanumerics, use [^[:alnum:]]. It's similar to [^abc]: the leading caret makes the bracket expression match all but the listed characters.
To match a literal dash, you need to make sure it's not interpreted as creating a list of characters to match. Make it the first character of the bracket expression: [-,.;/()_].
Note that sed doesn't take the / as a separator for s/// if it's within a bracket expression, so there's no need to put a backslash in front of it. (The backslash will match itself.) E.g. echo 'ab/c' | sed 's/[/]/./g' prints a.b.c.
See for example the regex(7) man page for a description of the regular expression syntax. (Note that it mainly discusses extended regular expressions (ERE), used by sed -E in many/most seds.)
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
add a comment |
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To match all non-alphanumerics, use [^[:alnum:]]. It's similar to [^abc]: the leading caret makes the bracket expression match all but the listed characters.
To match a literal dash, you need to make sure it's not interpreted as creating a list of characters to match. Make it the first character of the bracket expression: [-,.;/()_].
Note that sed doesn't take the / as a separator for s/// if it's within a bracket expression, so there's no need to put a backslash in front of it. (The backslash will match itself.) E.g. echo 'ab/c' | sed 's/[/]/./g' prints a.b.c.
See for example the regex(7) man page for a description of the regular expression syntax. (Note that it mainly discusses extended regular expressions (ERE), used by sed -E in many/most seds.)
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
add a comment |
To match all non-alphanumerics, use [^[:alnum:]]. It's similar to [^abc]: the leading caret makes the bracket expression match all but the listed characters.
To match a literal dash, you need to make sure it's not interpreted as creating a list of characters to match. Make it the first character of the bracket expression: [-,.;/()_].
Note that sed doesn't take the / as a separator for s/// if it's within a bracket expression, so there's no need to put a backslash in front of it. (The backslash will match itself.) E.g. echo 'ab/c' | sed 's/[/]/./g' prints a.b.c.
See for example the regex(7) man page for a description of the regular expression syntax. (Note that it mainly discusses extended regular expressions (ERE), used by sed -E in many/most seds.)
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
add a comment |
To match all non-alphanumerics, use [^[:alnum:]]. It's similar to [^abc]: the leading caret makes the bracket expression match all but the listed characters.
To match a literal dash, you need to make sure it's not interpreted as creating a list of characters to match. Make it the first character of the bracket expression: [-,.;/()_].
Note that sed doesn't take the / as a separator for s/// if it's within a bracket expression, so there's no need to put a backslash in front of it. (The backslash will match itself.) E.g. echo 'ab/c' | sed 's/[/]/./g' prints a.b.c.
See for example the regex(7) man page for a description of the regular expression syntax. (Note that it mainly discusses extended regular expressions (ERE), used by sed -E in many/most seds.)
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
To match all non-alphanumerics, use [^[:alnum:]]. It's similar to [^abc]: the leading caret makes the bracket expression match all but the listed characters.
To match a literal dash, you need to make sure it's not interpreted as creating a list of characters to match. Make it the first character of the bracket expression: [-,.;/()_].
Note that sed doesn't take the / as a separator for s/// if it's within a bracket expression, so there's no need to put a backslash in front of it. (The backslash will match itself.) E.g. echo 'ab/c' | sed 's/[/]/./g' prints a.b.c.
See for example the regex(7) man page for a description of the regular expression syntax. (Note that it mainly discusses extended regular expressions (ERE), used by sed -E in many/most seds.)
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
answered May 12 at 15:28
ilkkachuilkkachu
64k10105183
64k10105183
add a comment |
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Perhaps the class you are looking for is
[[:punct:]]? Regarding the use of-in character brackets, see What is difference between [-a-z] and [a-z] in regular expression?– steeldriver
May 12 at 15:15