How to extend shading in this figure?LaTeX equivalent of ConTeXt buffersRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insidehow to draw a phasor diagram (like this picture)TikZ: Drawing an arc from an intersection to an intersectionHow to make this figure?Line up nested tikz enviroments or how to get rid of themHow to draw this figure in tikz
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How to extend shading in this figure?
LaTeX equivalent of ConTeXt buffersRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insidehow to draw a phasor diagram (like this picture)TikZ: Drawing an arc from an intersection to an intersectionHow to make this figure?Line up nested tikz enviroments or how to get rid of themHow to draw this figure in tikz
2
The following figure is meant to be a contour graph. How can I extend the current shading out to the rest of the figure, so that there is shading between all of the lines?
Here is the the figure and the code.
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
tikz-pgf tikz-angles
asked Jun 6 at 22:27
MichaelMichael
318212
add a comment |
2
The following figure is meant to be a contour graph. How can I extend the current shading out to the rest of the figure, so that there is shading between all of the lines?
Here is the the figure and the code.
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
tikz-pgf tikz-angles
asked Jun 6 at 22:27
MichaelMichael
318212
add a comment |
2
2
2
The following figure is meant to be a contour graph. How can I extend the current shading out to the rest of the figure, so that there is shading between all of the lines?
Here is the the figure and the code.
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
tikz-pgf tikz-angles
asked Jun 6 at 22:27
MichaelMichael
318212
The following figure is meant to be a contour graph. How can I extend the current shading out to the rest of the figure, so that there is shading between all of the lines?
Here is the the figure and the code.
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
tikz-pgf tikz-angles
tikz-pgf tikz-angles
asked Jun 6 at 22:27
MichaelMichael
318212
asked Jun 6 at 22:27
MichaelMichael
318212
asked Jun 6 at 22:27
MichaelMichael
318212
asked Jun 6 at 22:27
MichaelMichael
318212
asked Jun 6 at 22:27
MichaelMichael
318212
318212
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
6
This does it (but is not the simplest way to obtain the result).
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
path (+80:rad cm-0.5cm) +(+170:3cm) coordinate (auxp)
(-80:rad cm-0.5cm) +(-170:3cm) coordinate (auxm);
path[fill=gray!thecntShader] (+80:rad cm) -- +(+170:3cm) -- (auxp)
-- (+80:rad cm-0.5cm) -- cycle;
path[fill=gray!thecntShader] (-80:rad cm) -- +(-170:3cm) -- (auxm)
-- (-80:rad cm-0.5cm) -- cycle;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
I personally would go along an arguably easier path:
documentclass[tikz]standalone
begindocument
begintikzpicture[line join=bevel]
coordinate (o) at (0,0);
foreach rad [count=Z starting from 0] in 3,2.5,...,.5
pgfmathtruncatemacroGL60-10*Z
draw[line width=5mm,gray!GL] (+80:rad cm-0.25cm) +(+170:3cm) -- (+80:rad cm-0.25cm)
arc(80:-80:rad cm-0.25cm) -- ++ (-170:3cm);
draw (+80:rad cm) +(+170:3cm) -- (+80:rad cm)
arc(80:-80:rad cm) -- ++ (-170:3cm);
draw (+170:3cm) -- (o) -- (-170:3cm);
draw[<->] (+80:4) coordinate (b) -- (o) -- (-80:4) coordinate (c);
endtikzpicture
enddocument
answered Jun 6 at 23:22
marmotmarmot
135k6176324
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replacebegintikzpicturebybegintikzpicture[line join=bevel].
– marmot
Jun 7 at 3:09
add a comment |
4
Something like this:
Here is the code:
documentclass[tikz, border=20mm]standalone
usetikzlibraryangles,calc
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad [evaluate=rad as prad using rad-0.5, count=c,
evaluate=c as sh using 70-10*c] in 3,2.5,...,.5
draw pic[draw,fill=gray!sh, angle radius=rad cm] angle=c--o--b;
draw[fill=gray!sh](+80:prad cm)--(+80:rad cm)--++(170:3cm)--($(+80:prad cm)+(170:3cm)$)--cycle;
draw[fill=gray!sh](-80:prad cm)--(-80:rad cm)--++(-170:3cm)--($(-80:prad cm)+(-170:3cm)$)--cycle;
endtikzpicture
enddocument
Note also that I have replaced your cntShader with sh using count=c, inthe
evaluate=c as sh using 70-10*cforeach statement.
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
This does it (but is not the simplest way to obtain the result).
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
path (+80:rad cm-0.5cm) +(+170:3cm) coordinate (auxp)
(-80:rad cm-0.5cm) +(-170:3cm) coordinate (auxm);
path[fill=gray!thecntShader] (+80:rad cm) -- +(+170:3cm) -- (auxp)
-- (+80:rad cm-0.5cm) -- cycle;
path[fill=gray!thecntShader] (-80:rad cm) -- +(-170:3cm) -- (auxm)
-- (-80:rad cm-0.5cm) -- cycle;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
I personally would go along an arguably easier path:
documentclass[tikz]standalone
begindocument
begintikzpicture[line join=bevel]
coordinate (o) at (0,0);
foreach rad [count=Z starting from 0] in 3,2.5,...,.5
pgfmathtruncatemacroGL60-10*Z
draw[line width=5mm,gray!GL] (+80:rad cm-0.25cm) +(+170:3cm) -- (+80:rad cm-0.25cm)
arc(80:-80:rad cm-0.25cm) -- ++ (-170:3cm);
draw (+80:rad cm) +(+170:3cm) -- (+80:rad cm)
arc(80:-80:rad cm) -- ++ (-170:3cm);
draw (+170:3cm) -- (o) -- (-170:3cm);
draw[<->] (+80:4) coordinate (b) -- (o) -- (-80:4) coordinate (c);
endtikzpicture
enddocument
answered Jun 6 at 23:22
marmotmarmot
135k6176324
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replacebegintikzpicturebybegintikzpicture[line join=bevel].
– marmot
Jun 7 at 3:09
add a comment |
6
This does it (but is not the simplest way to obtain the result).
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
path (+80:rad cm-0.5cm) +(+170:3cm) coordinate (auxp)
(-80:rad cm-0.5cm) +(-170:3cm) coordinate (auxm);
path[fill=gray!thecntShader] (+80:rad cm) -- +(+170:3cm) -- (auxp)
-- (+80:rad cm-0.5cm) -- cycle;
path[fill=gray!thecntShader] (-80:rad cm) -- +(-170:3cm) -- (auxm)
-- (-80:rad cm-0.5cm) -- cycle;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
I personally would go along an arguably easier path:
documentclass[tikz]standalone
begindocument
begintikzpicture[line join=bevel]
coordinate (o) at (0,0);
foreach rad [count=Z starting from 0] in 3,2.5,...,.5
pgfmathtruncatemacroGL60-10*Z
draw[line width=5mm,gray!GL] (+80:rad cm-0.25cm) +(+170:3cm) -- (+80:rad cm-0.25cm)
arc(80:-80:rad cm-0.25cm) -- ++ (-170:3cm);
draw (+80:rad cm) +(+170:3cm) -- (+80:rad cm)
arc(80:-80:rad cm) -- ++ (-170:3cm);
draw (+170:3cm) -- (o) -- (-170:3cm);
draw[<->] (+80:4) coordinate (b) -- (o) -- (-80:4) coordinate (c);
endtikzpicture
enddocument
answered Jun 6 at 23:22
marmotmarmot
135k6176324
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replacebegintikzpicturebybegintikzpicture[line join=bevel].
– marmot
Jun 7 at 3:09
add a comment |
6
6
6
This does it (but is not the simplest way to obtain the result).
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
path (+80:rad cm-0.5cm) +(+170:3cm) coordinate (auxp)
(-80:rad cm-0.5cm) +(-170:3cm) coordinate (auxm);
path[fill=gray!thecntShader] (+80:rad cm) -- +(+170:3cm) -- (auxp)
-- (+80:rad cm-0.5cm) -- cycle;
path[fill=gray!thecntShader] (-80:rad cm) -- +(-170:3cm) -- (auxm)
-- (-80:rad cm-0.5cm) -- cycle;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
I personally would go along an arguably easier path:
documentclass[tikz]standalone
begindocument
begintikzpicture[line join=bevel]
coordinate (o) at (0,0);
foreach rad [count=Z starting from 0] in 3,2.5,...,.5
pgfmathtruncatemacroGL60-10*Z
draw[line width=5mm,gray!GL] (+80:rad cm-0.25cm) +(+170:3cm) -- (+80:rad cm-0.25cm)
arc(80:-80:rad cm-0.25cm) -- ++ (-170:3cm);
draw (+80:rad cm) +(+170:3cm) -- (+80:rad cm)
arc(80:-80:rad cm) -- ++ (-170:3cm);
draw (+170:3cm) -- (o) -- (-170:3cm);
draw[<->] (+80:4) coordinate (b) -- (o) -- (-80:4) coordinate (c);
endtikzpicture
enddocument
answered Jun 6 at 23:22
marmotmarmot
135k6176324
This does it (but is not the simplest way to obtain the result).
documentclass[tikz]standalone
usetikzlibraryangles
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad in 3,2.5,...,.5
draw pic[draw,fill=gray!thecntShader, angle radius=rad cm] angle=c--o--b;
path (+80:rad cm-0.5cm) +(+170:3cm) coordinate (auxp)
(-80:rad cm-0.5cm) +(-170:3cm) coordinate (auxm);
path[fill=gray!thecntShader] (+80:rad cm) -- +(+170:3cm) -- (auxp)
-- (+80:rad cm-0.5cm) -- cycle;
path[fill=gray!thecntShader] (-80:rad cm) -- +(-170:3cm) -- (auxm)
-- (-80:rad cm-0.5cm) -- cycle;
pgfmathsetcountercntShaderthecntShader-10
setcountercntShaderthecntShader
draw (+80:rad cm) -- +(+170:3cm);
draw (-80:rad cm) -- +(-170:3cm);
endtikzpicture
enddocument
I personally would go along an arguably easier path:
documentclass[tikz]standalone
begindocument
begintikzpicture[line join=bevel]
coordinate (o) at (0,0);
foreach rad [count=Z starting from 0] in 3,2.5,...,.5
pgfmathtruncatemacroGL60-10*Z
draw[line width=5mm,gray!GL] (+80:rad cm-0.25cm) +(+170:3cm) -- (+80:rad cm-0.25cm)
arc(80:-80:rad cm-0.25cm) -- ++ (-170:3cm);
draw (+80:rad cm) +(+170:3cm) -- (+80:rad cm)
arc(80:-80:rad cm) -- ++ (-170:3cm);
draw (+170:3cm) -- (o) -- (-170:3cm);
draw[<->] (+80:4) coordinate (b) -- (o) -- (-80:4) coordinate (c);
endtikzpicture
enddocument
answered Jun 6 at 23:22
marmotmarmot
135k6176324
edited Jun 7 at 3:11
answered Jun 6 at 23:22
marmotmarmot
135k6176324
answered Jun 6 at 23:22
marmotmarmot
135k6176324
answered Jun 6 at 23:22
marmotmarmot
135k6176324
135k6176324
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replacebegintikzpicturebybegintikzpicture[line join=bevel].
– marmot
Jun 7 at 3:09
add a comment |
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replacebegintikzpicturebybegintikzpicture[line join=bevel].
– marmot
Jun 7 at 3:09
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
+1 More efficient as always:)
– Andrew
Jun 6 at 23:41
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
Thanks for the code! This looks great. It's easier to tell with the PDF: the vertex of the narrow cone (which opens to the left), protrudes just to the right of the origin, where it intersects with the lines that lean at 80 and -80 degrees. Is there a way of eliminating this?
– Michael
Jun 7 at 2:37
@Michael Yes, of course. Just replace
begintikzpicture by begintikzpicture[line join=bevel].– marmot
Jun 7 at 3:09
@Michael Yes, of course. Just replace
begintikzpicture by begintikzpicture[line join=bevel].– marmot
Jun 7 at 3:09
add a comment |
4
Something like this:
Here is the code:
documentclass[tikz, border=20mm]standalone
usetikzlibraryangles,calc
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad [evaluate=rad as prad using rad-0.5, count=c,
evaluate=c as sh using 70-10*c] in 3,2.5,...,.5
draw pic[draw,fill=gray!sh, angle radius=rad cm] angle=c--o--b;
draw[fill=gray!sh](+80:prad cm)--(+80:rad cm)--++(170:3cm)--($(+80:prad cm)+(170:3cm)$)--cycle;
draw[fill=gray!sh](-80:prad cm)--(-80:rad cm)--++(-170:3cm)--($(-80:prad cm)+(-170:3cm)$)--cycle;
endtikzpicture
enddocument
Note also that I have replaced your cntShader with sh using count=c, inthe
evaluate=c as sh using 70-10*cforeach statement.
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
add a comment |
4
Something like this:
Here is the code:
documentclass[tikz, border=20mm]standalone
usetikzlibraryangles,calc
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad [evaluate=rad as prad using rad-0.5, count=c,
evaluate=c as sh using 70-10*c] in 3,2.5,...,.5
draw pic[draw,fill=gray!sh, angle radius=rad cm] angle=c--o--b;
draw[fill=gray!sh](+80:prad cm)--(+80:rad cm)--++(170:3cm)--($(+80:prad cm)+(170:3cm)$)--cycle;
draw[fill=gray!sh](-80:prad cm)--(-80:rad cm)--++(-170:3cm)--($(-80:prad cm)+(-170:3cm)$)--cycle;
endtikzpicture
enddocument
Note also that I have replaced your cntShader with sh using count=c, inthe
evaluate=c as sh using 70-10*cforeach statement.
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
add a comment |
4
4
4
Something like this:
Here is the code:
documentclass[tikz, border=20mm]standalone
usetikzlibraryangles,calc
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad [evaluate=rad as prad using rad-0.5, count=c,
evaluate=c as sh using 70-10*c] in 3,2.5,...,.5
draw pic[draw,fill=gray!sh, angle radius=rad cm] angle=c--o--b;
draw[fill=gray!sh](+80:prad cm)--(+80:rad cm)--++(170:3cm)--($(+80:prad cm)+(170:3cm)$)--cycle;
draw[fill=gray!sh](-80:prad cm)--(-80:rad cm)--++(-170:3cm)--($(-80:prad cm)+(-170:3cm)$)--cycle;
endtikzpicture
enddocument
Note also that I have replaced your cntShader with sh using count=c, inthe
evaluate=c as sh using 70-10*cforeach statement.
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
Something like this:
Here is the code:
documentclass[tikz, border=20mm]standalone
usetikzlibraryangles,calc
begindocument
begintikzpicture
newcountercntShader
setcountercntShader60
coordinate (o) at (0,0);
draw[->] (o) -- (+80:4) coordinate (b);
draw[->] (o) -- (-80:4) coordinate (c);
draw (o) -- (+170:3);
draw (o) -- (-170:3);
foreach rad [evaluate=rad as prad using rad-0.5, count=c,
evaluate=c as sh using 70-10*c] in 3,2.5,...,.5
draw pic[draw,fill=gray!sh, angle radius=rad cm] angle=c--o--b;
draw[fill=gray!sh](+80:prad cm)--(+80:rad cm)--++(170:3cm)--($(+80:prad cm)+(170:3cm)$)--cycle;
draw[fill=gray!sh](-80:prad cm)--(-80:rad cm)--++(-170:3cm)--($(-80:prad cm)+(-170:3cm)$)--cycle;
endtikzpicture
enddocument
Note also that I have replaced your cntShader with sh using count=c, inthe
evaluate=c as sh using 70-10*cforeach statement.
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
answered Jun 6 at 23:38
AndrewAndrew
33.9k35088
33.9k35088
add a comment |
add a comment |
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